The parameters of the circuit shown in Figure 11.19 are
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Microelectronics: Circuit Analysis and Design
- QUESTION 5: A simplified class-AB output stage with BJTS is shown below. The circuit parameters are Vcc=15 V and R1 = 1900 2. For each transistor, Is= 9 x 10 ¬15 A. Determine the value of VBg that produces icn =ico=1 mA when vị= 0. What is the power dissipated in each transistor? Format : 2.7987275900068 VBB (V) Format : 62 Pon (mW)| (mW)| Format : 26 +Vcc icn VBB V BB 2 RL Qp lice -Vcc wwarrow_forwardQUESTION 7: A BJT diff-amp circuit is biased with a BJT constant- current source Io= 2.32 mA. The BJT constant-current source has an output resistance of Rocs= 4.8 M2. The bipolar transistor parameters are ß = 50 and V4= o. Determine: (a) the differential-mode input resistance, Rid and (b) the common- mode input resistance, Ricm- T7 (kN) Format : 5.69 Rid (kN) Format : 5.45 Ricm (MQ) Format : 335.5arrow_forwardTime left 1:46:17 A bipolar junction transistor is described in the figure below. The transistor is implemented in the circuit with Vcc, Rc, and RB equal to 16 volts, 2k, and 10kn. Determine the value of Vout if Vin = 1.1V. V... in RB B Vec Ro V E outarrow_forward
- V* = + |ov Ri Rip ERC Vs RE V: -sV The following parameters are given for this transistor: B = 200 and VA = o. Design the circuit with the following value ICQ = 1.5mA and VCEQ = 5V. Find the small signal voltage gain AV = Vo/Vs. Find the input resistance in the signal source Vs.arrow_forward2. The parameters of the transistor as shown in the figure below are ß = 100 and VA = 100V. a. Find the dc voltages at the base and emitter terminals. b. Find Rc such that VCEQ = 3.5V. c. Assuming Cc and CE act as short circuits, determine the small-signal voltage gain Av = Vo/Vs. d. Repeat part (c) if a 5000 source resistor is in series with the vs signal source. V+ = +5 V Rs = 100 £2 www Us Cc RB = 10 ΚΩ I= Iausmi 0.35 mA www RC -000 V=-5 V CEarrow_forward(ii) Calculate the RB, Rc, and the minimum power rating of the transistor (Note: the actual power rating should be greater).arrow_forward
- QUESTION 7: A BJT diff-amp circuit is biased with a BJT constant- current source Io=2.32 mA. The BJT constant-current source has an output resistance of Rocs = 4.8 MN. The bipolar transistor parameters are ß = 50 and V4=0. Determine: (a) the differential-mode input resistance, R¡d and (b) the common- mode input resistance, Ricm- Iq (kN) Format : 5.69 Rid (kN) Format : 5.45 Ricm (MQ) Format : 335.5arrow_forwardThe fixed- plus self-bias circuit of Figure 11.13 on page 569 has VDD = 15 V, R1 = 2 MΩ, R2 = 1 MΩ, RS = 4.7 kΩ, and RD=4.7 kΩ. The MOSFET has Vto = 1 V and K = 0.25 mA/V2. Determine the Q point.arrow_forwardDraw ac equivalent circuits for the following amplifiers. Each circuit should include resistancesand one dependent voltage or current source. a) Common Drain b) Common Emitter with single emitter resistance RE c) Common Gate d) Common Source with RSAC and RSDCarrow_forward
- 2) Consider the circuit given below. (Assume: K-4mA/V', Vt=-1V, A=0, (K= µCox.(W/L)) da Perform DC analysis and calculate Va. Vsg, Vs, voltages, and Ip, gm, ro values bo Draw a small-signal equivalent circuit Co Calculate Av, Rin, Rout values as shown on the schematic Also ) satwaton mode Test for Fill inthe table VG VSG O2m A Rin Vs QUin ID vo Coo 9m Ro Av Rout Rin Routarrow_forward1. Assume Q₁ and Q₂ in the following figure have matching characteristics and loss is 1.5 mA. a. What is lo? b. What is the approximate gain? c. If Q₂ is replaced with a transistor with an loss of 1.0 mA, what problem will occur? HI +VDD O 2₁ 22 Ò -Vss -OV ord U |||||arrow_forward(a) A common-emitter circuit using a BJT transistor (Figure 2a) is used to turn on a resistive load R, = 2000, and supply 30 ma through it, when the input voltage V, at the input circuit is set to 5 V. When V, 0, the current through the resistive load should be cut off. Given B = 110, maximum current limit of the input voltage source is 6mA, and, Ersor = 0.2V and Vue= 0.7V when the transistor is saturated, calculate V, and the feasible range of R, for the circuit to function according to the above requirements. %3D !! R2 R1 Figure 2aarrow_forward
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