The circuit parameters for the differential amplifier shown in Figure 11.2 are V + = 5 V , V − = − 5 V , I Q = 0.3 mA , and R C = 20 k Ω . The transistor Parameters are β = 180 , V B E ( on ) = 0.7 V , and V A = ∞ . Determine the voltages v E , v C 1 , v C 2 , v C E 1 , and v C E 2 for ( a ) v 1 = v 2 = 0 , ( b ) v 1 = v 2 = − 1 V and (c) v 1 = v 2 = + 1 V. (Ans. (a) v E = − 0.7 V , v C 1 = v C 2 = 2 V , v C E 1 = v C E 2 = 2.7 V ; (b) v E = − 1.7 V , v C 1 = v C 2 = 2 V , v C E 1 = v C E 2 = 3.7 V (c) v E = + 0.3 V , v C 1 = v C 2 = 2 V , v C E 1 = v C E 2 = 1.7 V ) .

Question

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Answer 1

Textbook Question

Chapter 11, Problem 11.1EP

The circuit parameters for the differential amplifier shown in Figure 11.2 are $V + = 5 V , V − = − 5 V , I Q = 0.3 mA ,$ and $R C = 20 k Ω .$ The transistor Parameters are $β = 180 , V B E ( on ) = 0.7 V ,$ and $V A = ∞ .$ Determine the voltages $v E , v C 1 , v C 2 , v C E 1 ,$ and $v C E 2$ for $( a ) v 1 = v 2 = 0 , ( b ) v 1 = v 2 = − 1 V$ and (c) $v 1 = v 2 = + 1$ V. (Ans. (a) $v E = − 0.7 V , v C 1 = v C 2 = 2 V , v C E 1 =$ $v C E 2 = 2.7 V ;$ (b) $v E = − 1.7 V , v C 1 = v C 2 = 2 V , v C E 1 = v C E 2 = 3.7 V$ (c) $v E = + 0.3 V , v C 1 = v C 2 = 2 V , v C E 1 = v C E 2 = 1.7 V )$ .

a.

Expert Solution

To determine

The collector voltages, collector to emitter voltages and the emitter voltage for the given input values of a differential amplifier.

Answer to Problem 11.1EP

$vE=−0.7 V$ , $vC1=2 V$ , $vC2=2 V$ , $vCE1=2.7 V$ , $vCE2=2.7 V$

Explanation of Solution

Given Information:

The given values are:

$V+=5 V, V−=−5 V,IQ=0.3 mA,RC=20 kΩ,β=180,VBE(on)=0.7 V,VA=∞v1=v2=0$

The given circuit is shown below.

Microelectronics: Circuit Analysis and Design, Chapter 11, Problem 11.1EP , additional homework tip 1

Calculation:

Voltage at emitter of each transistor

$vE=0−VBE(on)$

$vE=−0.7 V$

Assume transistors are matched. Then,

$iE1=iE2=IQ2$

Also assume that the bias currents are negligible. Then,

$iC1≅iE1=IQ2,iC2≅=iE2=IQ2$

Now

$vC1=vC2=V+−IQ2RC=5−0.15×20 V$

$vC1=2 V, vC2=2 V$

Then,

$vCE1=vC1−vE=2−(−0.7)$

$vCE1=2.7 V$

Similarly,

$vCE2=vC2−vE=2−(−0.7)$

$vCE2=2.7 V$

b.

Expert Solution

To determine

The collector voltages, collector to emitter voltages and the emitter voltage for the given values of a differential amplifier.

Answer to Problem 11.1EP

$vE=−1.7 V$ , $vC1=2 V$ , $vC2=2 V$ , $vCE1=3.7 V$ , $vCE2=3.7 V$

Explanation of Solution

Given Information:

The given values are:

$V+=5 V, V−=−5 V,IQ=0.3 mA,RC=20 kΩ,β=180,VBE(on)=0.7 V,VA=∞v1=v2=−1 V$

The given circuit is shown below.

Microelectronics: Circuit Analysis and Design, Chapter 11, Problem 11.1EP , additional homework tip 2

Calculation:

Voltage at emitter of each transistor

$vE=v1−VBE(on)=−1−0.7 V$

$vE=−1.7 V$

Assume transistors are matched. Then,

$iE1=iE2=IQ2$

Also assume the bias currents are negligible. Then,

$iC1≅iE1=IQ2,iC2≅iE2=IQ2$

Now

$vC1=vC2=V+−IQ2RC=5−0.15×20 V$

$vC1=2 V, vC2=2 V$

Then,

$vCE1=vC1−vE=2−(−1.7)$

$vCE1=3.7 V$

Similarly,

$vCE2=vC2−vE=2−(−0.7)$

$vCE2=3.7 V$

c.

Expert Solution

To determine

The collector voltages, collector to emitter voltages and the emitter voltage for the given values of differential amplifier.

Answer to Problem 11.1EP

$vE=0.3 V$ , $vC1=2 V$ , $vC2=2 V$ , $vCE1=1.7 V$ , $vCE2=1.7 V$

Explanation of Solution

Given Information:

The given values are:

$V+=5 V, V−=−5 V,IQ=0.3 mA,RC=20 kΩ,β=180,VBE(on)=0.7 V,VA=∞v1=v2=+1 V$

The given circuit is shown below.

Microelectronics: Circuit Analysis and Design, Chapter 11, Problem 11.1EP , additional homework tip 3

Calculation:

Voltage at emitter of each transistor

$vE=v1−VBE(on)=1−0.7 V$

$vE=0.3 V$

Assume transistors are matched. Then,

$iE1=iE2=IQ2$

Also assume the bias currents are negligible. Then,

$iC1≅iE1=IQ2,iC2≅iE2=IQ2$

Now

$vC1=vC2=V+−IQ2RC=5−0.15×20 V$

$vC1=2 V, vC2=2 V$

Then,

$vCE1=vC1−vE=2−(0.3)$

$vCE1=1.7 V$

Similarly,

$vCE2=vC2−vE=2−(0.3)$

$vCE2=1.7 V$

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Answer 2

Textbook Question

Chapter 11, Problem 11.1EP

The circuit parameters for the differential amplifier shown in Figure 11.2 are $V + = 5 V , V − = − 5 V , I Q = 0.3 mA ,$ and $R C = 20 k Ω .$ The transistor Parameters are $β = 180 , V B E ( on ) = 0.7 V ,$ and $V A = ∞ .$ Determine the voltages $v E , v C 1 , v C 2 , v C E 1 ,$ and $v C E 2$ for $( a ) v 1 = v 2 = 0 , ( b ) v 1 = v 2 = − 1 V$ and (c) $v 1 = v 2 = + 1$ V. (Ans. (a) $v E = − 0.7 V , v C 1 = v C 2 = 2 V , v C E 1 =$ $v C E 2 = 2.7 V ;$ (b) $v E = − 1.7 V , v C 1 = v C 2 = 2 V , v C E 1 = v C E 2 = 3.7 V$ (c) $v E = + 0.3 V , v C 1 = v C 2 = 2 V , v C E 1 = v C E 2 = 1.7 V )$ .

a.

Expert Solution

To determine

The collector voltages, collector to emitter voltages and the emitter voltage for the given input values of a differential amplifier.

Answer to Problem 11.1EP

$vE=−0.7 V$ , $vC1=2 V$ , $vC2=2 V$ , $vCE1=2.7 V$ , $vCE2=2.7 V$

Explanation of Solution

Given Information:

The given values are:

$V+=5 V, V−=−5 V,IQ=0.3 mA,RC=20 kΩ,β=180,VBE(on)=0.7 V,VA=∞v1=v2=0$

The given circuit is shown below.

Microelectronics: Circuit Analysis and Design, Chapter 11, Problem 11.1EP , additional homework tip 1

Calculation:

Voltage at emitter of each transistor

$vE=0−VBE(on)$

$vE=−0.7 V$

Assume transistors are matched. Then,

$iE1=iE2=IQ2$

Also assume that the bias currents are negligible. Then,

$iC1≅iE1=IQ2,iC2≅=iE2=IQ2$

Now

$vC1=vC2=V+−IQ2RC=5−0.15×20 V$

$vC1=2 V, vC2=2 V$

Then,

$vCE1=vC1−vE=2−(−0.7)$

$vCE1=2.7 V$

Similarly,

$vCE2=vC2−vE=2−(−0.7)$

$vCE2=2.7 V$

b.

Expert Solution

To determine

The collector voltages, collector to emitter voltages and the emitter voltage for the given values of a differential amplifier.

Answer to Problem 11.1EP

$vE=−1.7 V$ , $vC1=2 V$ , $vC2=2 V$ , $vCE1=3.7 V$ , $vCE2=3.7 V$

Explanation of Solution

Given Information:

The given values are:

$V+=5 V, V−=−5 V,IQ=0.3 mA,RC=20 kΩ,β=180,VBE(on)=0.7 V,VA=∞v1=v2=−1 V$

The given circuit is shown below.

Microelectronics: Circuit Analysis and Design, Chapter 11, Problem 11.1EP , additional homework tip 2

Calculation:

Voltage at emitter of each transistor

$vE=v1−VBE(on)=−1−0.7 V$

$vE=−1.7 V$

Assume transistors are matched. Then,

$iE1=iE2=IQ2$

Also assume the bias currents are negligible. Then,

$iC1≅iE1=IQ2,iC2≅iE2=IQ2$

Now

$vC1=vC2=V+−IQ2RC=5−0.15×20 V$

$vC1=2 V, vC2=2 V$

Then,

$vCE1=vC1−vE=2−(−1.7)$

$vCE1=3.7 V$

Similarly,

$vCE2=vC2−vE=2−(−0.7)$

$vCE2=3.7 V$

c.

Expert Solution

To determine

The collector voltages, collector to emitter voltages and the emitter voltage for the given values of differential amplifier.

Answer to Problem 11.1EP

$vE=0.3 V$ , $vC1=2 V$ , $vC2=2 V$ , $vCE1=1.7 V$ , $vCE2=1.7 V$

Explanation of Solution

Given Information:

The given values are:

$V+=5 V, V−=−5 V,IQ=0.3 mA,RC=20 kΩ,β=180,VBE(on)=0.7 V,VA=∞v1=v2=+1 V$

The given circuit is shown below.

Microelectronics: Circuit Analysis and Design, Chapter 11, Problem 11.1EP , additional homework tip 3

Calculation:

Voltage at emitter of each transistor

$vE=v1−VBE(on)=1−0.7 V$

$vE=0.3 V$

Assume transistors are matched. Then,

$iE1=iE2=IQ2$

Also assume the bias currents are negligible. Then,

$iC1≅iE1=IQ2,iC2≅iE2=IQ2$

Now

$vC1=vC2=V+−IQ2RC=5−0.15×20 V$

$vC1=2 V, vC2=2 V$

Then,

$vCE1=vC1−vE=2−(0.3)$

$vCE1=1.7 V$

Similarly,

$vCE2=vC2−vE=2−(0.3)$

$vCE2=1.7 V$

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Answer 3

Textbook Question

Chapter 11, Problem 11.1EP

The circuit parameters for the differential amplifier shown in Figure 11.2 are $V + = 5 V , V − = − 5 V , I Q = 0.3 mA ,$ and $R C = 20 k Ω .$ The transistor Parameters are $β = 180 , V B E ( on ) = 0.7 V ,$ and $V A = ∞ .$ Determine the voltages $v E , v C 1 , v C 2 , v C E 1 ,$ and $v C E 2$ for $( a ) v 1 = v 2 = 0 , ( b ) v 1 = v 2 = − 1 V$ and (c) $v 1 = v 2 = + 1$ V. (Ans. (a) $v E = − 0.7 V , v C 1 = v C 2 = 2 V , v C E 1 =$ $v C E 2 = 2.7 V ;$ (b) $v E = − 1.7 V , v C 1 = v C 2 = 2 V , v C E 1 = v C E 2 = 3.7 V$ (c) $v E = + 0.3 V , v C 1 = v C 2 = 2 V , v C E 1 = v C E 2 = 1.7 V )$ .

a.

Expert Solution

To determine

The collector voltages, collector to emitter voltages and the emitter voltage for the given input values of a differential amplifier.

Answer to Problem 11.1EP

$vE=−0.7 V$ , $vC1=2 V$ , $vC2=2 V$ , $vCE1=2.7 V$ , $vCE2=2.7 V$

Explanation of Solution

Given Information:

The given values are:

$V+=5 V, V−=−5 V,IQ=0.3 mA,RC=20 kΩ,β=180,VBE(on)=0.7 V,VA=∞v1=v2=0$

The given circuit is shown below.

Microelectronics: Circuit Analysis and Design, Chapter 11, Problem 11.1EP , additional homework tip 1

Calculation:

Voltage at emitter of each transistor

$vE=0−VBE(on)$

$vE=−0.7 V$

Assume transistors are matched. Then,

$iE1=iE2=IQ2$

Also assume that the bias currents are negligible. Then,

$iC1≅iE1=IQ2,iC2≅=iE2=IQ2$

Now

$vC1=vC2=V+−IQ2RC=5−0.15×20 V$

$vC1=2 V, vC2=2 V$

Then,

$vCE1=vC1−vE=2−(−0.7)$

$vCE1=2.7 V$

Similarly,

$vCE2=vC2−vE=2−(−0.7)$

$vCE2=2.7 V$

b.

Expert Solution

To determine

The collector voltages, collector to emitter voltages and the emitter voltage for the given values of a differential amplifier.

Answer to Problem 11.1EP

$vE=−1.7 V$ , $vC1=2 V$ , $vC2=2 V$ , $vCE1=3.7 V$ , $vCE2=3.7 V$

Explanation of Solution

Given Information:

The given values are:

$V+=5 V, V−=−5 V,IQ=0.3 mA,RC=20 kΩ,β=180,VBE(on)=0.7 V,VA=∞v1=v2=−1 V$

The given circuit is shown below.

Microelectronics: Circuit Analysis and Design, Chapter 11, Problem 11.1EP , additional homework tip 2

Calculation:

Voltage at emitter of each transistor

$vE=v1−VBE(on)=−1−0.7 V$

$vE=−1.7 V$

Assume transistors are matched. Then,

$iE1=iE2=IQ2$

Also assume the bias currents are negligible. Then,

$iC1≅iE1=IQ2,iC2≅iE2=IQ2$

Now

$vC1=vC2=V+−IQ2RC=5−0.15×20 V$

$vC1=2 V, vC2=2 V$

Then,

$vCE1=vC1−vE=2−(−1.7)$

$vCE1=3.7 V$

Similarly,

$vCE2=vC2−vE=2−(−0.7)$

$vCE2=3.7 V$

c.

Expert Solution

To determine

The collector voltages, collector to emitter voltages and the emitter voltage for the given values of differential amplifier.

Answer to Problem 11.1EP

$vE=0.3 V$ , $vC1=2 V$ , $vC2=2 V$ , $vCE1=1.7 V$ , $vCE2=1.7 V$

Explanation of Solution

Given Information:

The given values are:

$V+=5 V, V−=−5 V,IQ=0.3 mA,RC=20 kΩ,β=180,VBE(on)=0.7 V,VA=∞v1=v2=+1 V$

The given circuit is shown below.

Microelectronics: Circuit Analysis and Design, Chapter 11, Problem 11.1EP , additional homework tip 3

Calculation:

Voltage at emitter of each transistor

$vE=v1−VBE(on)=1−0.7 V$

$vE=0.3 V$

Assume transistors are matched. Then,

$iE1=iE2=IQ2$

Also assume the bias currents are negligible. Then,

$iC1≅iE1=IQ2,iC2≅iE2=IQ2$

Now

$vC1=vC2=V+−IQ2RC=5−0.15×20 V$

$vC1=2 V, vC2=2 V$

Then,

$vCE1=vC1−vE=2−(0.3)$

$vCE1=1.7 V$

Similarly,

$vCE2=vC2−vE=2−(0.3)$

$vCE2=1.7 V$

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Answer 4

Textbook Question

Chapter 11, Problem 11.1EP

The circuit parameters for the differential amplifier shown in Figure 11.2 are $V + = 5 V , V − = − 5 V , I Q = 0.3 mA ,$ and $R C = 20 k Ω .$ The transistor Parameters are $β = 180 , V B E ( on ) = 0.7 V ,$ and $V A = ∞ .$ Determine the voltages $v E , v C 1 , v C 2 , v C E 1 ,$ and $v C E 2$ for $( a ) v 1 = v 2 = 0 , ( b ) v 1 = v 2 = − 1 V$ and (c) $v 1 = v 2 = + 1$ V. (Ans. (a) $v E = − 0.7 V , v C 1 = v C 2 = 2 V , v C E 1 =$ $v C E 2 = 2.7 V ;$ (b) $v E = − 1.7 V , v C 1 = v C 2 = 2 V , v C E 1 = v C E 2 = 3.7 V$ (c) $v E = + 0.3 V , v C 1 = v C 2 = 2 V , v C E 1 = v C E 2 = 1.7 V )$ .

a.

Expert Solution

To determine

The collector voltages, collector to emitter voltages and the emitter voltage for the given input values of a differential amplifier.

Answer to Problem 11.1EP

$vE=−0.7 V$ , $vC1=2 V$ , $vC2=2 V$ , $vCE1=2.7 V$ , $vCE2=2.7 V$

Explanation of Solution

Given Information:

The given values are:

$V+=5 V, V−=−5 V,IQ=0.3 mA,RC=20 kΩ,β=180,VBE(on)=0.7 V,VA=∞v1=v2=0$

The given circuit is shown below.

Microelectronics: Circuit Analysis and Design, Chapter 11, Problem 11.1EP , additional homework tip 1

Calculation:

Voltage at emitter of each transistor

$vE=0−VBE(on)$

$vE=−0.7 V$

Assume transistors are matched. Then,

$iE1=iE2=IQ2$

Also assume that the bias currents are negligible. Then,

$iC1≅iE1=IQ2,iC2≅=iE2=IQ2$

Now

$vC1=vC2=V+−IQ2RC=5−0.15×20 V$

$vC1=2 V, vC2=2 V$

Then,

$vCE1=vC1−vE=2−(−0.7)$

$vCE1=2.7 V$

Similarly,

$vCE2=vC2−vE=2−(−0.7)$

$vCE2=2.7 V$

b.

Expert Solution

To determine

The collector voltages, collector to emitter voltages and the emitter voltage for the given values of a differential amplifier.

Answer to Problem 11.1EP

$vE=−1.7 V$ , $vC1=2 V$ , $vC2=2 V$ , $vCE1=3.7 V$ , $vCE2=3.7 V$

Explanation of Solution

Given Information:

The given values are:

$V+=5 V, V−=−5 V,IQ=0.3 mA,RC=20 kΩ,β=180,VBE(on)=0.7 V,VA=∞v1=v2=−1 V$

The given circuit is shown below.

Microelectronics: Circuit Analysis and Design, Chapter 11, Problem 11.1EP , additional homework tip 2

Calculation:

Voltage at emitter of each transistor

$vE=v1−VBE(on)=−1−0.7 V$

$vE=−1.7 V$

Assume transistors are matched. Then,

$iE1=iE2=IQ2$

Also assume the bias currents are negligible. Then,

$iC1≅iE1=IQ2,iC2≅iE2=IQ2$

Now

$vC1=vC2=V+−IQ2RC=5−0.15×20 V$

$vC1=2 V, vC2=2 V$

Then,

$vCE1=vC1−vE=2−(−1.7)$

$vCE1=3.7 V$

Similarly,

$vCE2=vC2−vE=2−(−0.7)$

$vCE2=3.7 V$

c.

Expert Solution

To determine

The collector voltages, collector to emitter voltages and the emitter voltage for the given values of differential amplifier.

Answer to Problem 11.1EP

$vE=0.3 V$ , $vC1=2 V$ , $vC2=2 V$ , $vCE1=1.7 V$ , $vCE2=1.7 V$

Explanation of Solution

Given Information:

The given values are:

$V+=5 V, V−=−5 V,IQ=0.3 mA,RC=20 kΩ,β=180,VBE(on)=0.7 V,VA=∞v1=v2=+1 V$

The given circuit is shown below.

Microelectronics: Circuit Analysis and Design, Chapter 11, Problem 11.1EP , additional homework tip 3

Calculation:

Voltage at emitter of each transistor

$vE=v1−VBE(on)=1−0.7 V$

$vE=0.3 V$

Assume transistors are matched. Then,

$iE1=iE2=IQ2$

Also assume the bias currents are negligible. Then,

$iC1≅iE1=IQ2,iC2≅iE2=IQ2$

Now

$vC1=vC2=V+−IQ2RC=5−0.15×20 V$

$vC1=2 V, vC2=2 V$

Then,

$vCE1=vC1−vE=2−(0.3)$

$vCE1=1.7 V$

Similarly,

$vCE2=vC2−vE=2−(0.3)$

$vCE2=1.7 V$

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Answer 5

Textbook Question

Answer 6

Textbook Question

Answer 7

a.

Expert Solution

To determine

The collector voltages, collector to emitter voltages and the emitter voltage for the given input values of a differential amplifier.

Answer to Problem 11.1EP

$vE=−0.7 V$ , $vC1=2 V$ , $vC2=2 V$ , $vCE1=2.7 V$ , $vCE2=2.7 V$

Explanation of Solution

Given Information:

The given values are:

$V+=5 V, V−=−5 V,IQ=0.3 mA,RC=20 kΩ,β=180,VBE(on)=0.7 V,VA=∞v1=v2=0$

The given circuit is shown below.

Microelectronics: Circuit Analysis and Design, Chapter 11, Problem 11.1EP , additional homework tip 1

Calculation:

Voltage at emitter of each transistor

$vE=0−VBE(on)$

$vE=−0.7 V$

Assume transistors are matched. Then,

$iE1=iE2=IQ2$

Also assume that the bias currents are negligible. Then,

$iC1≅iE1=IQ2,iC2≅=iE2=IQ2$

Now

$vC1=vC2=V+−IQ2RC=5−0.15×20 V$

$vC1=2 V, vC2=2 V$

Then,

$vCE1=vC1−vE=2−(−0.7)$

$vCE1=2.7 V$

Similarly,

$vCE2=vC2−vE=2−(−0.7)$

$vCE2=2.7 V$

b.

Expert Solution

To determine

The collector voltages, collector to emitter voltages and the emitter voltage for the given values of a differential amplifier.

Answer to Problem 11.1EP

$vE=−1.7 V$ , $vC1=2 V$ , $vC2=2 V$ , $vCE1=3.7 V$ , $vCE2=3.7 V$

Explanation of Solution

Given Information:

The given values are:

$V+=5 V, V−=−5 V,IQ=0.3 mA,RC=20 kΩ,β=180,VBE(on)=0.7 V,VA=∞v1=v2=−1 V$

The given circuit is shown below.

Microelectronics: Circuit Analysis and Design, Chapter 11, Problem 11.1EP , additional homework tip 2

Calculation:

Voltage at emitter of each transistor

$vE=v1−VBE(on)=−1−0.7 V$

$vE=−1.7 V$

Assume transistors are matched. Then,

$iE1=iE2=IQ2$

Also assume the bias currents are negligible. Then,

$iC1≅iE1=IQ2,iC2≅iE2=IQ2$

Now

$vC1=vC2=V+−IQ2RC=5−0.15×20 V$

$vC1=2 V, vC2=2 V$

Then,

$vCE1=vC1−vE=2−(−1.7)$

$vCE1=3.7 V$

Similarly,

$vCE2=vC2−vE=2−(−0.7)$

$vCE2=3.7 V$

c.

Expert Solution

To determine

The collector voltages, collector to emitter voltages and the emitter voltage for the given values of differential amplifier.

Answer to Problem 11.1EP

$vE=0.3 V$ , $vC1=2 V$ , $vC2=2 V$ , $vCE1=1.7 V$ , $vCE2=1.7 V$

Explanation of Solution

Given Information:

The given values are:

$V+=5 V, V−=−5 V,IQ=0.3 mA,RC=20 kΩ,β=180,VBE(on)=0.7 V,VA=∞v1=v2=+1 V$

The given circuit is shown below.

Microelectronics: Circuit Analysis and Design, Chapter 11, Problem 11.1EP , additional homework tip 3

Calculation:

Voltage at emitter of each transistor

$vE=v1−VBE(on)=1−0.7 V$

$vE=0.3 V$

Assume transistors are matched. Then,

$iE1=iE2=IQ2$

Also assume the bias currents are negligible. Then,

$iC1≅iE1=IQ2,iC2≅iE2=IQ2$

Now

$vC1=vC2=V+−IQ2RC=5−0.15×20 V$

$vC1=2 V, vC2=2 V$

Then,

$vCE1=vC1−vE=2−(0.3)$

$vCE1=1.7 V$

Similarly,

$vCE2=vC2−vE=2−(0.3)$

$vCE2=1.7 V$

Answer 8

a.

Expert Solution

To determine

The collector voltages, collector to emitter voltages and the emitter voltage for the given input values of a differential amplifier.

Answer to Problem 11.1EP

$vE=−0.7 V$ , $vC1=2 V$ , $vC2=2 V$ , $vCE1=2.7 V$ , $vCE2=2.7 V$

Explanation of Solution

Given Information:

The given values are:

$V+=5 V, V−=−5 V,IQ=0.3 mA,RC=20 kΩ,β=180,VBE(on)=0.7 V,VA=∞v1=v2=0$

The given circuit is shown below.

Microelectronics: Circuit Analysis and Design, Chapter 11, Problem 11.1EP , additional homework tip 1

Calculation:

Voltage at emitter of each transistor

$vE=0−VBE(on)$

$vE=−0.7 V$

Assume transistors are matched. Then,

$iE1=iE2=IQ2$

Also assume that the bias currents are negligible. Then,

$iC1≅iE1=IQ2,iC2≅=iE2=IQ2$

Now

$vC1=vC2=V+−IQ2RC=5−0.15×20 V$

$vC1=2 V, vC2=2 V$

Then,

$vCE1=vC1−vE=2−(−0.7)$

$vCE1=2.7 V$

Similarly,

$vCE2=vC2−vE=2−(−0.7)$

$vCE2=2.7 V$

Answer 9

a.

Expert Solution

Answer 10

a.

Expert Solution

Answer 11

Expert Solution

Answer 12

To determine

The collector voltages, collector to emitter voltages and the emitter voltage for the given input values of a differential amplifier.

Answer 13

Answer to Problem 11.1EP

$vE=−0.7 V$ , $vC1=2 V$ , $vC2=2 V$ , $vCE1=2.7 V$ , $vCE2=2.7 V$

Answer 14

Explanation of Solution

Given Information:

The given values are:

$V+=5 V, V−=−5 V,IQ=0.3 mA,RC=20 kΩ,β=180,VBE(on)=0.7 V,VA=∞v1=v2=0$

The given circuit is shown below.

Microelectronics: Circuit Analysis and Design, Chapter 11, Problem 11.1EP , additional homework tip 1

Calculation:

Voltage at emitter of each transistor

$vE=0−VBE(on)$

$vE=−0.7 V$

Assume transistors are matched. Then,

$iE1=iE2=IQ2$

Also assume that the bias currents are negligible. Then,

$iC1≅iE1=IQ2,iC2≅=iE2=IQ2$

Now

$vC1=vC2=V+−IQ2RC=5−0.15×20 V$

$vC1=2 V, vC2=2 V$

Then,

$vCE1=vC1−vE=2−(−0.7)$

$vCE1=2.7 V$

Similarly,

$vCE2=vC2−vE=2−(−0.7)$

$vCE2=2.7 V$

Answer 15

b.

Expert Solution

To determine

The collector voltages, collector to emitter voltages and the emitter voltage for the given values of a differential amplifier.

Answer to Problem 11.1EP

$vE=−1.7 V$ , $vC1=2 V$ , $vC2=2 V$ , $vCE1=3.7 V$ , $vCE2=3.7 V$

Explanation of Solution

Given Information:

The given values are:

$V+=5 V, V−=−5 V,IQ=0.3 mA,RC=20 kΩ,β=180,VBE(on)=0.7 V,VA=∞v1=v2=−1 V$

The given circuit is shown below.

Microelectronics: Circuit Analysis and Design, Chapter 11, Problem 11.1EP , additional homework tip 2

Calculation:

Voltage at emitter of each transistor

$vE=v1−VBE(on)=−1−0.7 V$

$vE=−1.7 V$

Assume transistors are matched. Then,

$iE1=iE2=IQ2$

Also assume the bias currents are negligible. Then,

$iC1≅iE1=IQ2,iC2≅iE2=IQ2$

Now

$vC1=vC2=V+−IQ2RC=5−0.15×20 V$

$vC1=2 V, vC2=2 V$

Then,

$vCE1=vC1−vE=2−(−1.7)$

$vCE1=3.7 V$

Similarly,

$vCE2=vC2−vE=2−(−0.7)$

$vCE2=3.7 V$

Answer 16

b.

Expert Solution

Answer 17

b.

Expert Solution

Answer 18

Expert Solution

Answer 19

To determine

The collector voltages, collector to emitter voltages and the emitter voltage for the given values of a differential amplifier.

Answer 20

Answer to Problem 11.1EP

$vE=−1.7 V$ , $vC1=2 V$ , $vC2=2 V$ , $vCE1=3.7 V$ , $vCE2=3.7 V$

Answer 21

Explanation of Solution

Given Information:

The given values are:

$V+=5 V, V−=−5 V,IQ=0.3 mA,RC=20 kΩ,β=180,VBE(on)=0.7 V,VA=∞v1=v2=−1 V$

The given circuit is shown below.

Microelectronics: Circuit Analysis and Design, Chapter 11, Problem 11.1EP , additional homework tip 2

Calculation:

Voltage at emitter of each transistor

$vE=v1−VBE(on)=−1−0.7 V$

$vE=−1.7 V$

Assume transistors are matched. Then,

$iE1=iE2=IQ2$

Also assume the bias currents are negligible. Then,

$iC1≅iE1=IQ2,iC2≅iE2=IQ2$

Now

$vC1=vC2=V+−IQ2RC=5−0.15×20 V$

$vC1=2 V, vC2=2 V$

Then,

$vCE1=vC1−vE=2−(−1.7)$

$vCE1=3.7 V$

Similarly,

$vCE2=vC2−vE=2−(−0.7)$

$vCE2=3.7 V$

Answer 22

c.

Expert Solution

To determine

The collector voltages, collector to emitter voltages and the emitter voltage for the given values of differential amplifier.

Answer to Problem 11.1EP

$vE=0.3 V$ , $vC1=2 V$ , $vC2=2 V$ , $vCE1=1.7 V$ , $vCE2=1.7 V$

Explanation of Solution

Given Information:

The given values are:

$V+=5 V, V−=−5 V,IQ=0.3 mA,RC=20 kΩ,β=180,VBE(on)=0.7 V,VA=∞v1=v2=+1 V$

The given circuit is shown below.

Microelectronics: Circuit Analysis and Design, Chapter 11, Problem 11.1EP , additional homework tip 3

Calculation:

Voltage at emitter of each transistor

$vE=v1−VBE(on)=1−0.7 V$

$vE=0.3 V$

Assume transistors are matched. Then,

$iE1=iE2=IQ2$

Also assume the bias currents are negligible. Then,

$iC1≅iE1=IQ2,iC2≅iE2=IQ2$

Now

$vC1=vC2=V+−IQ2RC=5−0.15×20 V$

$vC1=2 V, vC2=2 V$

Then,

$vCE1=vC1−vE=2−(0.3)$

$vCE1=1.7 V$

Similarly,

$vCE2=vC2−vE=2−(0.3)$

$vCE2=1.7 V$

Answer 23

c.

Expert Solution

Answer 24

c.

Expert Solution

Answer 25

Expert Solution

Answer 26

To determine

The collector voltages, collector to emitter voltages and the emitter voltage for the given values of differential amplifier.

Answer 27

Answer to Problem 11.1EP

$vE=0.3 V$ , $vC1=2 V$ , $vC2=2 V$ , $vCE1=1.7 V$ , $vCE2=1.7 V$

Answer 28

Explanation of Solution

Given Information:

The given values are:

$V+=5 V, V−=−5 V,IQ=0.3 mA,RC=20 kΩ,β=180,VBE(on)=0.7 V,VA=∞v1=v2=+1 V$

The given circuit is shown below.

Microelectronics: Circuit Analysis and Design, Chapter 11, Problem 11.1EP , additional homework tip 3

Calculation:

Voltage at emitter of each transistor

$vE=v1−VBE(on)=1−0.7 V$

$vE=0.3 V$

Assume transistors are matched. Then,

$iE1=iE2=IQ2$

Also assume the bias currents are negligible. Then,

$iC1≅iE1=IQ2,iC2≅iE2=IQ2$

Now

$vC1=vC2=V+−IQ2RC=5−0.15×20 V$

$vC1=2 V, vC2=2 V$

Then,

$vCE1=vC1−vE=2−(0.3)$

$vCE1=1.7 V$

Similarly,

$vCE2=vC2−vE=2−(0.3)$

$vCE2=1.7 V$

Answer 29

Ch. 11 - The circuit parameters for the differential...Ch. 11 - Consider the de transfer characteristics shown in...Ch. 11 - Prob. 11.1CSP Ch. 11 - Consider the diff-amp described in Example 11.3 ....Ch. 11 - Prob. 11.4EP Ch. 11 - Prob. 11.1TYU Ch. 11 - Prob. 11.2TYU Ch. 11 - Assume the differential-mode gain of a diff-amp is...Ch. 11 - Prob. 11.5EP Ch. 11 - Consider the diff-amp shown in Figure 11.15 ....

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