Concept explainers
(a)
Interpretation: The major organic products that would result from the reaction of
Concept introduction: Carbocation formation is relatively slower than acid-base reactions. Carbocations generated from alkyl halides have two fates; they can be either trapped by nucleophiles to give substitution product or may deprotonate to yield a small amount of alkene. Stronger the base more is the probability of elimination over substitution over elimination. Further, if the still higher concentration is employed reaction proceeds via bimolecular elimination. On the other hand, the weak base waits until the carbocation is formed and the type of elimination with a relatively weak base is two-step elimination or
Three principal factors that affect the competition between substitution and elimination: basicity of the nucleophile, steric hindrance in the alkyl halide, and steric bulk around the nucleophilic atom. The bases such as hydroxide ion, alkoxide ion, amide ion, tertiary amines are highly strong bases that favor elimination over substitution. On the other hand bases such as methanol, halides, alkyl phosphines, azides, cyanides, acetates are regarded as weak bases and they form substitution products in greater ratios than elimination products.
Analogous to the case that strong nucleophiles are more favored to react via
(b)
Interpretation: The major organic products that would result from the reaction of
Concept introduction: Carbocation formation is relatively slower than acid-base reactions. Carbocations generated from alkyl halides have two fates; they can be either trapped by nucleophiles to give substitution product or may deprotonate to yield a small amount of alkene. Stronger the base more is the probability of elimination over substitution over elimination. Further, if the still higher concentration is employed reaction proceeds via bimolecular elimination. On the other hand, the weak base waits until the carbocation is formed and the type of elimination with a relatively weak base is two-step elimination or
Analogous to the case that strong nucleophiles are more favored to react via
(c)
Interpretation: The major organic products that would result from the reaction of
Concept introduction: Carbocation formation is relatively slower than acid-base reactions. Carbocations generated from alkyl halides have two fates; they can be either trapped by nucleophiles to give substitution product or may deprotonate to yield a small amount of alkene. Stronger the base more is the probability of elimination over substitution over elimination. Further, if the still higher concentration is employed reaction proceeds via bimolecular elimination. On the other hand, the weak base waits until the carbocation is formed and the type of elimination with a relatively weak base is two-step elimination or
Analogous to the case that strong nucleophiles are more favored to react via
(d)
Interpretation: The major organic products that would result from the reaction of
Concept introduction: Carbocation formation is relatively slower than acid-base reactions. Carbocations generated from alkyl halides have two fates; they can be either trapped by nucleophiles to give substitution product or may deprotonate to yield a small amount of
Analogous to the case that strong nucleophiles are more favored to react via
(e)
Interpretation: The major organic products that would result from the reaction of
Concept introduction: Carbocation formation is relatively slower than acid-base reactions. Carbocations generated from alkyl halides have two fates; they can be either trapped by nucleophiles to give substitution product or may deprotonate to yield a small amount of alkene. Stronger the base more is the probability of elimination over substitution over elimination. Further, if the still higher concentration is employed reaction proceeds via bimolecular elimination. On the other hand, the weak base waits until the carbocation is formed and the type of elimination with a relatively weak base is two-step elimination or
Analogous to the case that strong nucleophiles are more favored to react via
(f)
Interpretation: The major organic products that would result from the reaction of
Concept introduction: Carbocation formation is relatively slower than acid-base reactions. Carbocations generated from alkyl halides have two fates; they can be either trapped by nucleophiles to give substitution product or may deprotonate to yield a small amount of alkene. Stronger the base more is the probability of elimination over substitution over elimination. Further, if the still higher concentration is employed reaction proceeds via bimolecular elimination. On the other hand, the weak base waits until the carbocation is formed and the type of elimination with a relatively weak base is two-step elimination or
Analogous to the case that strong nucleophiles are more favored to react via
(g)
Interpretation: The major organic products that would result from the reaction of
Concept introduction: Carbocation formation is relatively slower than acid-base reactions. Carbocations generated from alkyl halides have two fates; they can be either trapped by nucleophiles to give substitution product or may deprotonate to yield a small amount of alkene. Stronger the base more is the probability of elimination over substitution over elimination. Further, if the still higher concentration is employed reaction proceeds via bimolecular elimination. On the other hand, the weak base waits until the carbocation is formed and the type of elimination with a relatively weak base is two-step elimination or
Analogous to the case that strong nucleophiles are more favored to react via
(h)
Interpretation: The major organic products that would result from the reaction of
Concept introduction: Carbocation formation is relatively slower than acid-base reactions. Carbocations generated from alkyl halides have two fates; they can be either trapped by nucleophiles to give substitution product or may deprotonate to yield a small amount of alkene. Stronger the base more is the probability of elimination over substitution over elimination. Further, if the still higher concentration is employed reaction proceeds via bimolecular elimination. On the other hand, the weak base waits until the carbocation is formed and the type of elimination with a relatively weak base is two-step elimination or
Analogous to the case that strong nucleophiles are more favored to react via
(i)
Interpretation: The major organic products that would result from the reaction of
Concept introduction: Carbocation formation is relatively slower than acid-base reactions. Carbocations generated from alkyl halides have two fates; they can be either trapped by nucleophiles to give substitution product or may deprotonate to yield a small amount of alkene. Stronger the base more is the probability of elimination over substitution over elimination. Further, if the still higher concentration is employed reaction proceeds via bimolecular elimination. On the other hand, the weak base waits until the carbocation is formed and the type of elimination with a relatively weak base is two-step elimination or
Analogous to the case that strong nucleophiles are more favored to react via
Want to see the full answer?
Check out a sample textbook solutionChapter 7 Solutions
Organic Chemistry: Structure and Function
- 4. Draw the organic products of the reactions of (R)-2-iodobutane with azide ion and methanol. Draw allstereoisomers expected to form. (R)-2-iodobutane Na*N3* CH3OHarrow_forwardFollowing is a balanced equation for the allylic bromination of propene. CH2==CHCH3 + Br2 h CH2==CHCH2Br + HBr (a) Calculate the heat of reaction, H 0, for this conversion. (b) Propose a pair of chain propagation steps and show that they add up to the observed stoichiometry. (c) Calculate the H 0 for each chain propagation step and show that they add up to the observed H 0 for the overall reaction.arrow_forwardThe reaction shown below is carried out in two stages. In the first, the two reactants are combined in tetrahydrofuran (THF) solvent to form a neutral adduct. Aqueous acid is then added to hydrolyze this initial adduct, giving the final product. N(CH3)2 I. H a For the reaction shown above, draw the major organic product having at least one carbonyl group. • You do not have to consider stereochemistry. Pis 85 1. THF 2. H3O+ n [ ]#arrow_forward
- 4. Aldehydes and ketones can be "protected" as acetals and ketals. Complete the following outlined reactions, showing how the protection is accomplished, and what results after deprotection. Br MgBr 1) Br 2) H3O* deprotection herearrow_forwardDraw the most stable resonance form for the intermediate in the following electrophilic substitution reaction. CH3 CH3 H3PO4 HO, + H3C CH3 HO HO First stage in synthesis of the epoxy and polycarbonate ingredient bisphenol-A You do not have to consider stereochemistry. Include all valence lone pairs in your answer. In cases where there is more than one answer, just draw one.arrow_forwardAcyl transfer (nucleophilic substitution at carbonyl) reactions proceed in two stages via a "tetrahedral intermediate." Draw the tetrahedral intermediate as it is first formed in the following reaction. CI H₂N OH • You do not have to consider stereochemistry. • Include all valence lone pairs in your answer. • Do not include counter-ions, e.g., Na+, I, in your answer. • In cases where there is more than one answer, just draw one. Sn [Farrow_forward
- Choose reagents to convert 2-cyclohexenone to the following compounds. Syntheses may require several steps. Use letters from the table to list reagents in the order used (first at the left). i 1. Li(CH2=CH)2Cu Reagents a 1. Li(CH3)2Cu 2. H3O+ e 1. Li(C6H5)2Cu 2. H3O+ b 1. NaBH4 f CH2l2/Zn(Cu) / ether j 2. H3O+ C NH3 / KOH g 1. CH3MgBr/dry ether k 2 H3O+ d H2NNH2/KOH h HN(CH3)2 HO CH3 a) b) OH N(CH3)2 2. H3O+ (C6H5)3P+-CH2 H₂ over Pd/C KMnO4/H3O+arrow_forwardAcyl transfer (nucleophilic substitution at carbonyl) reactions proceed in two stages via a "tetrahedral intermediate." Draw the tetrahedral intermediate as it is first formed in the following reaction. 0 OH CI + H₂N • You do not have to consider stereochemistry. • Include all valence lone pairs in your answer. • Do not include counter-ions, e.g., Na+, I, in your answer. In cases where there is more than one answer, just draw one. A ChemDoodle Activate Windowsarrow_forwardWhy must dehydration reactions of alcohols be carried out under acid catalysis? O 1) the hydroxide group is a poor leaving group and must be protonated to 1) generate a better leaving group. 2) the hydroxide group is a great leaving group and does not need to be protonated to generate a better leaving group. O 3) the acid isn't necessary for the reaction. O4) None of these are correct answers.arrow_forward
- Provide the reagents necessary to convert 3-methyl-2-butanol to 2-bromo-3-methylbutane. CHOOSE FROM THE FOLLOWING REAGRENTS BELOW conc. HBr NaBr, H2SO4 PBr3 HBr, peroxide Br2arrow_forwardH3C CH3 H3C NA C→XT Br Br₂ CH₂Cl₂ H3C Electrophilic addition of bromine, Br₂, to alkenes yields a 1,2-dibromoalkane. The reaction proceeds through a cyclic intermediate known as a bromonium ion. The reaction occurs in an anhydrous solvent such as CH₂Cl₂. CH3 Br In the second step of the reaction, bromide is the nucleophile and attacks at one of the carbons of the bromonium ion to yield the product. Due to steric clashes, the bromide ion always attacks the carbon from the opposite face of the bromonium ion so that a product with anti stereochemistry is formed. Draw curved arrows to show the movement of electrons in this step of the mechanism. Arrow-pushing Instructions Br CH3 H3C CH3arrow_forward9. Hydrates, in which two -OH groups are connected to the same carbon, are not favorable except in a few cases. One case is: a) acetaldehyde c) acetone b) formaldehyde d) chloroform 10. The Wolff-Kishner reaction, in which an aldehyde or ketone is treated with NH2NH2 and KOH, is: a) an oxidation c) an SN2 reaction b) a reduction d) a hydration 11. Which of these is most likely to dissolve in 5% NaOH? a) 1-decanol b) decanal c) decanoic acid d) 2-decanone bu itcolf Draw tbearrow_forward
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning