Organic Chemistry: Structure and Function
Organic Chemistry: Structure and Function
8th Edition
ISBN: 9781319079451
Author: K. Peter C. Vollhardt, Neil E. Schore
Publisher: W. H. Freeman
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Chapter 7.9, Problem 7.18E

(a)

Interpretation Introduction

Interpretation: The structure of major organic product and pathway followed that would result from reaction of 1-bromopropane with sodium cyanide in acetone should be written.

Concept introduction: Carbocation formation is relatively slower than acid-base reactions. Carbocations generated from alkyl halides have two fates; they can be either trapped by nucleophiles to give substitution product or may deprotonated to yield small amount of alkene. Stronger the base more is the probability of elimination over substitution over elimination. Further, if still higher concentration is employed reaction proceeds via bimolecular elimination. On the other hand, weak base waits until the carbocation is formed and the type of elimination with relatively weak base is two-step elimination or E1 .

Analogous to the case that strong nucleophiles are more favored to react via SN2 pathway, greater concentration of strong bases are more favored for single-step elimination E2 pathway. Such strong bases include hydroxide ion or alkoxide ions. The reason of predominance of E2 elimination is that strong bases have high probabilities and high rates to abstract hydrogen from carbon adjacent to carbocation.

(b)

Interpretation Introduction

Interpretation: The structure of major organic product that would result from reaction of 1-bromopropane with sodium methoxide in methanol should be written.

Concept introduction: Carbocation formation is relatively slower than acid-base reactions. Carbocations generated from alkyl halides have two fates; they can be either trapped by nucleophiles to give substitution product or may deprotonated to yield small amount of alkene. Stronger the base more is the probability of elimination over substitution over elimination. Further, if still higher concentration is employed reaction proceeds via bimolecular elimination. On the other hand, weak base waits until the carbocation is formed and the type of elimination with relatively weak base is two-step elimination or E1 .

Analogous to the case that strong nucleophiles are more favored to react via SN2 pathway, greater concentration of strong bases are more favored for single-step elimination E2 pathway. Such strong bases include hydroxide ion or alkoxide ions. The reason of predominance of E2 elimination is that strong bases have high probabilities and high rates to abstract hydrogen from carbon adjacent to carbocation.

(c)

Interpretation Introduction

Interpretation: The structure of major organic product that would result from reaction of 1-bromopropane with potassium tert-butoxide tert-butanol should be written.

Concept introduction: Carbocation formation is relatively slower than acid-base reactions. Carbocations generated from alkyl halides have two fates; they can be either trapped by nucleophiles to give substitution product or may deprotonated to yield small amount of alkene. Stronger the base more is the probability of elimination over substitution over elimination. Further, if still higher concentration is employed reaction proceeds via bimolecular elimination. On the other hand, weak base waits until the carbocation is formed and the type of elimination with relatively weak base is two-step elimination or E1 .

Analogous to the case that strong nucleophiles are more favored to react via SN2 pathway, greater concentration of strong bases are more favored for single-step elimination E2 pathway. Such strong bases include hydroxide ion or alkoxide ions. The reason of predominance of E2 elimination is that strong bases have high probabilities and high rates to abstract hydrogen from carbon adjacent to carbocation.

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Write down the common (not IUPAC) names of the organic molecules that would be released if this molecule were hydrolyzed: CH₂ E CH CH,−O O || 11 O -(CH₂)7-CH=CH-CH₂-CH=CH-CH₂-CH=CH-CH₂-CH3 (CH₂)7 -CH=CH-CH₂-CH=CH-CH₂-CH=CH-CH₂-CH3 -(CH₂)16-CH3 Separate each name with a comma. You will find useful information in the ALEKS Data resource. a × Y Ś
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