Organic Chemistry: Structure and Function
Organic Chemistry: Structure and Function
8th Edition
ISBN: 9781319079451
Author: K. Peter C. Vollhardt, Neil E. Schore
Publisher: W. H. Freeman
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Chapter 7.9, Problem 7.20E

(a)

Interpretation Introduction

Interpretation: The structure of major organic product that would result from reaction of 2-bromopropane with ethanol along with the dominant pathway adopted should be written.

Concept introduction: Carbocation formation is relatively slower than acid-base reactions. Carbocations generated from alkyl halides have two fates; they can be either trapped by nucleophiles to give substitution product or may deprotonated to yield small amount of alkene. Stronger the base more is the probability of elimination over substitution over elimination. Further, if still higher concentration is employed reaction proceeds via bimolecular elimination. On the other hand, weak base waits until the carbocation is formed and the type of elimination with relatively weak base is two-step elimination or E1 .

Analogous to the case that strong nucleophiles are more favored to react via SN2 pathway, greater concentration of strong bases are more favored for single-step elimination E2 pathway. Such strong bases include hydroxide ion or alkoxide ions. The reason of predominance of E2 elimination is that strong bases have high probabilities and high rates to abstract hydrogen from carbon adjacent to carbocation.

(b)

Interpretation Introduction

Interpretation: The structure of major organic product that would result from reaction of 2-bromopropane with sodium ethoxide in ethanol along with the dominant pathway adopted should be written.

Concept introduction: Carbocation formation is relatively slower than acid-base reactions. Carbocations generated from alkyl halides have two fates; they can be either trapped by nucleophiles to give substitution product or may deprotonated to yield small amount of alkene. Stronger the base more is the probability of elimination over substitution over elimination. Further, if still higher concentration is employed reaction proceeds via bimolecular elimination. On the other hand, weak base waits until the carbocation is formed and the type of elimination with relatively weak base is two-step elimination or E1 .

Analogous to the case that strong nucleophiles are more favored to react via SN2 pathway, greater concentration of strong bases are more favored for single-step elimination E2 pathway. Such strong bases include hydroxide ion or alkoxide ions. The reason of predominance of E2 elimination is that strong bases have high probabilities and high rates to abstract hydrogen from carbon adjacent to carbocation.

(c)

Interpretation Introduction

Interpretation: The structure of major organic product that would result from reaction of 1-bromo-2-methylpropane with sodium ethoxide in ethanol along with the dominant pathway adopted should be written.

Concept introduction: Carbocation formation is relatively slower than acid base reactions. Carbocations generated from alkyl halides have two fates; they can be either trapped by nucleophiles to give substitution product or may deprotonated to yield small amount of alkene. Stronger the base more is the probability of elimination over substitution over elimination. Further if still higher concentration is employed reaction proceeds via bimolecular elimination. On the other hand weak base waits until the carbocation is formed and the type of elimination with relatively weak base is two-step elimination or E1 .

Analogous to the case that strong nucleophiles are more favored to react via SN2 pathway, greater concentration of strong bases are more favored for single -step elimination E2 pathway. Such strong bases include hydroxide ion or alkoxide ions. The reason of predominance of E2 elimination is that strong bases have high probabilities and high rates to abstract hydrogen from carbon adjacent to carbocation.

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(b) Predict the suitable solvent (H2O or CH3COCH3) to increase the reaction of bromopropane (CH3CH2CH2B1) with sodium hydroxide (NaOH). Two reactions are shown below: NaOH, 55 °C CH;CH,CH,Br CH;CH,CH,OH + NaBr H,O (i) NaOH, 55 °C CH;CH,CH,Br CH;CH,CH,OH NaBr H,C CH (ii)
Predict the product of the following organic reaction: CH₂ CH O || C–CH2–CH=CH—(CH2)3 CH3 (CH₂)3 CH=CH- - CH₂ CH3 + 4 H₂ Ni CH,−O -C–CH2–CH=CH–CH=CH–CH2–CH3 Specifically, in the drawing area below, draw the chemical structure of the product P. If there is no product, because this reaction won't happen, check the No reaction box under the drawing area. Click and drag to start drawing a structure. × Ś +
Describe the reaction mechanism for the hydrolysis of 2-bromo-2-methylpropane [CH3C(CH3)2Br] with aqueous hydroxide ions (OH-).The description should be detailed and must include the type of bond fission that takes place. You may sketch and insert suitable diagrams to aid your description if you wish
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