Acyl transfer (nucleophilic substitution at carbonyl) reactions proceed in two stages via a "tetrahedral intermediate." Draw the tetrahedral intermediate as it is first formed in the following reaction. H₂N OH
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- Acyl transfer (nucleophilic substitution at carbonyl) reactions proceed in two stages via a "tetrahedral intermediate." Draw the tetrahedral intermediate as it is first formed in the following reaction. CI + H₂N • You do not have to consider stereochemistry. • Include all valence lone pairs in your answer. OH • Do not include counter-ions, e.g., Na+, I¯, in your answer. • In cases where there is more than one answer, just draw one.Acyl transfer (nucleophilic substitution at carbonyl) reactions proceed in two stages via a "tetrahedral intermediate." Draw the tetrahedral intermediate as it is first formed in the following reaction. H3C HCI / H2O `NH2 reflux • You do not have to consider stereochemistry. • Include all valence lone pairs in your answer. • Do not include counter-ions, e.g., Na", I, in your answer. • In cases where there is more than one answer, just draw one. opy aste Previous NextAcyl transfer (nucleophilic substitution at carbonyl) reactions proceed in two stages via a "tetrahedral intermediate." Draw the tetrahedral intermediate as it is first formed in the following reaction. CH3OH H3C CI • • • • You do not have to consider stereochemistry. Include all valence lone pairs in your answer. Do not include counter-ions, e.g., Na+, I", in your answer. In cases where there is more than one answer, just draw one.
- Acyl transfer (nucleophilic substitution at carbonyl) reactions proceed in two stages via a "tetrahedral intermediate." Draw the tetrahedral intermediate as it is first formed in the following reaction. H3C. ... NH2 HCI/H₂O reflux • You do not have to consider stereochemistry. • Include all valence lone pairs in your answer. • Do not include counter-ions, e.g., Na+, I, in your answer. • In cases where there is more than one answer, just draw one. + 4 n [ ?Step 4a: Classify step. The target product is present, but the reaction is not over. The ethoxide ion has been regenerated. :0: :0: What is the key process in the next step of the mechanism? proton transfer formation of a o bond between nucleophile and electrophile loss of a leaving group carbocation rearrangement (e.g., methyl or hydride shift)Alcohols are acidic in nature. Therefore, a strong base can abstract the acidic hydrogen atom of the alcohol in a process known as deprotonation. The alcohol forms an alkoxide ion by losing the proton attached to the oxygen atom of the hydroxyl ( -OH) group. The alkoxide formed can act as a base or a nucleophile depending on the substrate and reaction conditions. However, not all bases can abstract the acidic proton of alcohols and not all alcohols easily lose the proton. Deprotonation depends on the strength of the base and the acidity of the alcohol. Strong bases, such as NaNH2, can easily abstract a proton from almost all alcohols. Likewise, more acidic alcohols lose a proton more easily. Determine which of the following reactions would undergo deprotonation based on the strength of the base and the acidity of the alcohol. Check all that apply. ► View Available Hint(s) CH3CH,OH + NH3 →CH,CH,O-NH CH3 CH3 H3C-C-H+NH3 → H3 C-C-H OH O-NH CH3CH2OH + NaNH, → CH3CH,O-Na* + NH3 CHC12 Cl₂…
- Answer the question below the reaction. O4S H3C H3C H3C OH In the first step of the reaction mechanism, which of the following is formed? CH3 H3C CH3 CH3 + Excess NH4Cl OH CH3 (+) -OH2 CH 3 CH3 OH CH3 H₂SO₁ CH3 CI ха +H2OIn an E2 mediated elimination reaction of an alkyl halide (H-X) using NaOCH3 as base, which of the following statement is not true? O The reactivity order for alkyl halides (RX) is tertiary secondary> primary. O The rate of reaction = k2 (alkyl halide] [NaOCH₂] O The reaction occurs in a single step. O The rate is independent of the leaving group.Nonconjugated B,y-unsaturated ketones are in base-catalyzed equilibrium with their conjugated a,ß-unsaturated isomers. The mechanism of interconversion involves the formation of a resonance-stabilized intermediate with three resonance contributors. Draw the structures of these three resonance contributors. OH • You do not have to consider stereochemistry. • Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner. Separate resonance structures using the symbol from the drop-down menu. + *** Sn [F
- Draw the reactants and complete the mechanism by drawing in the appropriate electron-flow arrows (including stereochemistry) for the following Sy2 reaction of an alkyl bromide. Represent the nucleophile as an ion. Draw all missing reactants and/or products in the appropriate boxes by placing atoms on the grid and connecting them with bonds, including charges where needed. Indicate the mechanism by drawing the electron-flow arrows on the molecules. Arrows should start on an atom or a bond and should end on an atom, bond, or where a new bond should be created. • View Available Hint(s) + CH N H. S CH H,C C-ÖH CI HC Br HC F [1] APredict the products of this organic reaction: CH3 CH₂ || No reaction CH3 -CH-CH₂-CH3 + NaOH A Specifically, in the drawing area below draw the structure of the product, or products, of this reaction. (If there's more than one product, draw them in any arrangement you like, so long as they aren't touching.) If there aren't any products because this reaction won't happen, check the No reaction box under the drawing area. ? Click anywhere to draw the first atom of your structure. X ŚDraw the neutral organic starting material. The Hint: The reaction conditions support electrophilic addition of Br2 to an alkene's C=C double bond, which would normally yield a dibromo product. However, the product has only one bromine atom, with a C–O bond on the adjacent carbon. This fragment is diagnostic for a halohydrin, where an oxygen nucleophile (water or alcohol) reacts with a bromonium intermediate to generate the O–CH2CH2–Br motif. Work backwards to determine what the starting material must look like. There should be an alcohol and an alkene in the neutral organic starting material.