The S stereoisomers of lactic and malic acid should be drawn. Concept introduction: The enantiomers are identical chemical compounds that have a mirror-image relationship to each other while diastereomers do not hold mirror image relationships. The former are chiral and optically active while the latter can be chiral or achiral. Together enantiomers and diastereomers constitute the total stereoisomers of any chiral compound. In order to assign absolute configuration of R and S, Cahn − Ingold − Prelog rules are used and the first step is to assign the priority order on the basis of atomic number . The one with highest atomic number gest highest priority and is designated as a and so on with the lowest priority group at the bottom.

Question

Want to see the full answer?

Answer 1

Question

Chapter 8, Problem 59P

Interpretation Introduction

Interpretation: The S stereoisomers of lactic and malic acid should be drawn.

Concept introduction:The enantiomers are identical chemical compounds that have a mirror-image relationship to each other while diastereomers do not hold mirror image relationships. The former are chiral and optically active while the latter can be chiral or achiral. Together enantiomers and diastereomers constitute the total stereoisomers of any chiral compound.

In order to assign absolute configuration of R and S, Cahn − Ingold − Prelog rules are used and the first step is to assign the priority order on the basis of atomic number. The one with highest atomic number gest highest priority and is designated as a and so on with the lowest priority group at the bottom.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

rivatives: Nucleophilic Acyl Substitution Reactions - EOC O C-O [References] One step in the gluconeogenesis pathway for the biosynthesis of glucose is the partial reduction of 3-phosphoglycerate to give glyceraldehyde 3-phosphate. The process occurs by phosphorylation with ATP to give 1,3-bisphosphoglycerate, reaction with a thiol group on the enzyme to give an enzyme-bound thioester, and reduction with NADH. H-C-OH ATP ADP CH₂OPO32- 3-phosphoglycerate 0= OPO32- C H-C-OH CH₂OPO32 1,3-bisphosphoglycerate Enz-SH PO43- O= C S-Enz H-C-OH CH₂OPO3² (Enzyme-bound thioester) NADH/H+ O=C NAD*, Enz-SH H H-C-OH CH₂OPO3²- glyceraldehyde 3-phosphate Propose a structure for the first intermediate in the reaction of the enzyme-bound thioester with NADH to form glyceraldehyde 3-phosphate. To simplify the drawing process, substitute the structure below for the enzyme-bound thioester. S-CH3 substitute for the CH2CH3 enzyme-bound thioester You do not have to consider stereochemistry. • You do not have…

17) Specify the stereochemistry (R or S) at each of the following stereocenters. Write your answers in the boxes provides. Br H3C H •H • OH CH2CH3 SH ОН

4-Chloro-2-pentene has a double bond that can have either the E or the Z configuration and a stereogenic center that can have either the R or the S configuration. How many stereoisomers arepossible altogether? Draw the structure of each, and group the pairs of enantiomers.