Introduction to Genetic Analysis
11th Edition
ISBN: 9781464109485
Author: Anthony J.F. Griffiths, Susan R. Wessler, Sean B. Carroll, John Doebley
Publisher: W. H. Freeman
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Chapter 2, Problem 69P
Summary Introduction
To determine: Whether the results fit the hypothesis of a cross between purple and blue plant.
Introduction: Gregor Mendel delivered three principles of inheritance implement to
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Two pure-breeding lines of petunia plants are crossed. Line 1 plants grow to a height of 54
cm, and Line 2 plants grow to a height of 18 cm. Petunia plant height is controlled by three
genes, A, B and C. Line 1 has the genotype A₁A₁B₁B₁C₁C₁, and line 2 has the genotype
A2A2B₂B₂C₂C₂. Assume that genotype alone determines plant height under ideal growth
conditions and that the alleles of the three genes are additive.
If the F1 plants are self crossed, what is the expected proportion of F2 plants with the
genotype A₁A₁B₁B₁C₁C₁
1/8
1/32
1/16
1/4
1/64
A type of tomato (Solanum lycopersicum) produces fruit in three possible colors: red, green, and orange. You cross a true-breeding orange-fruited plant with a true-breeding green-fruited plant, and all the F1 offspring are red. You intercross the red F1s, and the resulting F2 generation consists of 108 red-, 40 orange-, and 44 green-fruited plants.
1) What type of epistasis is acting (dominant, recessive, duplicate dominant, or duplicate recessive)?
2) Assign the phenotypes to a modified 9:3:3:1 ratio. (Do not just calculate the actual ratio of the phenotypes.)
Red : _____Orange : _____Green: _____
A particular flower can be blue, red, or white. A pure-breeding red-flowered plant is crossed with a pure-breeding white-flowered one. The F 1 are then crossed to produce an F 2 generation. Which of the following phenotypic ratios in the F 2 indicate that flower color in these two strains is controlled by two genes?
A)2:1
B)3:1
C)1:2:1
D)9:3:4
Chapter 2 Solutions
Introduction to Genetic Analysis
Ch. 2 - Prob. 1PCh. 2 - Prob. 2PCh. 2 - Prob. 3PCh. 2 - Prob. 4PCh. 2 - Prob. 6PCh. 2 - Prob. 7PCh. 2 - Prob. 8PCh. 2 - Prob. 9PCh. 2 - Prob. 10PCh. 2 - Prob. 11P
Ch. 2 - Prob. 12PCh. 2 - Prob. 13PCh. 2 - Prob. 14PCh. 2 - Prob. 15PCh. 2 - Prob. 16PCh. 2 - Prob. 17PCh. 2 - Prob. 18PCh. 2 - Prob. 19PCh. 2 - Prob. 20PCh. 2 - Prob. 21PCh. 2 - Prob. 22PCh. 2 - Prob. 23PCh. 2 - Prob. 24PCh. 2 - Prob. 25PCh. 2 - Prob. 26PCh. 2 - Prob. 27PCh. 2 - Prob. 28PCh. 2 - Prob. 31PCh. 2 - Prob. 32PCh. 2 - Prob. 33PCh. 2 - Prob. 34PCh. 2 - Prob. 35PCh. 2 - Prob. 36PCh. 2 - Prob. 37PCh. 2 - Prob. 38PCh. 2 - Prob. 39PCh. 2 - Prob. 40PCh. 2 - Prob. 41PCh. 2 - Prob. 42PCh. 2 - Prob. 43PCh. 2 - Prob. 44PCh. 2 - Prob. 44.1PCh. 2 - Prob. 44.2PCh. 2 - Prob. 44.3PCh. 2 - Prob. 44.4PCh. 2 - Prob. 44.5PCh. 2 - Prob. 44.6PCh. 2 - Prob. 44.7PCh. 2 - Prob. 44.8PCh. 2 - Prob. 44.9PCh. 2 - Prob. 44.10PCh. 2 - Prob. 44.11PCh. 2 - Prob. 44.12PCh. 2 - Prob. 44.13PCh. 2 - Prob. 44.14PCh. 2 - Prob. 44.15PCh. 2 - Prob. 45PCh. 2 - Prob. 47PCh. 2 - Prob. 48PCh. 2 - Prob. 49PCh. 2 - Prob. 50PCh. 2 - Prob. 51PCh. 2 - Prob. 52PCh. 2 - Prob. 53PCh. 2 - Prob. 56PCh. 2 - Prob. 57PCh. 2 - Prob. 58PCh. 2 - Prob. 59PCh. 2 - Prob. 60PCh. 2 - Prob. 61PCh. 2 - Prob. 62PCh. 2 - Prob. 63PCh. 2 - Prob. 64PCh. 2 - Prob. 65PCh. 2 - Prob. 66PCh. 2 - Prob. 67PCh. 2 - Prob. 68PCh. 2 - Prob. 69PCh. 2 - Prob. 70PCh. 2 - Prob. 71PCh. 2 - Prob. 72PCh. 2 - Prob. 73PCh. 2 - Prob. 74PCh. 2 - Prob. 75PCh. 2 - Prob. 76PCh. 2 - Prob. 77PCh. 2 - Prob. 78PCh. 2 - Prob. 79P
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- You have two true-breeding strains of coneflower. One strain has purple flowers and purple stems. The other strain has white flowers and green stems. When you cross these strains the F1 generation has purple flowers and purple stems. From this information you know that purple flowers is dominant to white flowers and that purple stems is dominant to green stems. In terms of genetic mechanisms, there could be two explanations: (1) flower color and stem color are each controlled by separate, independently segregating genes, and (2) there is one gene controlling both flower color and stem color. A. If explanation #1 is correct what would you see if the F1 generation were self-crossed to produce an F2 generation. Make up appropriate genetic symbols for this model and work out the cross to the F2 generation. B. If explanation #2 is correct what would you see if the F1 generation were self-crossed to produce an F2 generation. Make up appropriate genetic symbols for this model and work out the…arrow_forwardIn Primula vulgaris (primrose), purple flowers are dominant to white flowers, and short plants are dominant to tall plants. The genes controlling these two traits are on different chromosomes. You cross a true-breeding purple, short plant with a true-breeding white, tall plant and then intercross the resulting F1 offspring. In the F2 offspring, you find the following phenotypes: Purple, short Purple, tall 608 161 White, short White, tall 173 58 With your knowledge of the x' test, you will determine whether the outcomes of the F1 intercross corresponds to expectations based on Mendelian genetics. 1. What is your null hypothesis for the outcome of the F1 intercross? Write it here: 2. Based on your null hypothesis, how many individuals do you expect in each of the phenotypic classes? Write your expectations below. Purple, short Purple, tall White, short White, tall 3. What are the degrees of freedom for this test? Write your answer here:arrow_forwardIn tomatoes, regular leaves (L) are multilobed and serrated and potato leaves (l) are broad, smooth, and single (Image 1). Red fruit (F) is dominant to yellow fruit (f). A cross is carried out between two pure lines of tomato plants, one having regular leaves and red fruit and the other having potato leaves and yellow fruit. The F1 generation all have regular leaves and red fruit. The F1 individuals are then crossed with one another. Complete a Punnett square to determine the expected F2 progeny on the basis of Mendel’s Law of Independent Assortment, which states that the alleles for one gene segregate independently of the alleles for other genes during gamete formation.arrow_forward
- In tomatoes, regular leaves (L) are multilobed and serrated and potato leaves (l) are broad, smooth, and single (Image 1). Red fruit (F) is dominant to yellow fruit (f). A cross is carried out between two pure lines of tomato plants, one having regular leaves and red fruit and the other having potato leaves and yellow fruit. The F1 generation all have regular leaves and red fruit. The F1 individuals are then crossed with one another. The information below represents two sets of data collected from the above cross. Phenotypes Data Set 1 Data Set 2 Regular Red 26 846 Regular Yellow 15 273 Potato Red 6 287 Potato Yellow 12 94 Total 59 1 500 Data set 1 is a from a small sample size and data set 2 is from a large sample size. Compare each data set to the expected probabilities. Explain any differences that you see in how different the observed results are from the expected results between the two data sets. Compare the expected probabilities of each phenotypic class to…arrow_forwardIn tomatoes, the red fruit color is completely dominant to yellow. Suppose a tomato plant homozygous for red is crossed with one homozygous for yellow and the progeny are allowed to self pollinate. What phenotypes do you predict in the F2 generation? a) 3 red: 1 yellow b) 9 red : 3 orange : 1 yellow c) 1 red : 2 orange : 1 yellow d) 1 red : 1 yellowarrow_forwardA type of tomato (Solanum lycopersicum) produces fruit in three possible colors: red, orange, and green. You cross a true-breeding red-fruited plant with a true-breeding green-fruited plant, and all the F1 offspring are red. You intercross the red F1s, and the resulting F2 generation consists of 61 red-, 13 orange-, and 6 green-fruited plants. a) Assign the phenotypes to a modified 9:3:3:1 ratio (do not just calculate the actual ratio of the phenotypes). Show your work.arrow_forward
- You successfully isolate an hsf2/hsf2; hsf3/hsf3 double mutant stock. You cross this plant to an hsf1/hsf1 plant and then self-pollinate the F1. You want to recover at least 10 triple mutant homozygous to evaluate the phenotype. How many plants do you need to genotype to expect to recover 10 triple mutant plants?arrow_forwardNicotiana glutinosa (2 n = 24) and N. tabacum (2 n = 48) are two closely related plants that can be intercrossed, but the F1 hybrid plants that result are usually sterile. In 1925, Roy Clausen and Thomas Goodspeed crossed N. glutinosa and N. tabacum and obtained one fertile F1 plant . They were able to self-pollinate the flowers of this plant to produce an F2 generation. Surprisingly, the F2 plants were fully fertile and produced viable seeds. When Clausen and Goodspeed examined the chromosomes of the F2 plants, they observed 36 pairs of chromosomes in metaphase I and 36 individual chromosomes in metaphase II. Explain the origin of the F2 plants obtained by Clausen and Goodspeed and the numbers of chromosomes observed.arrow_forwardA cross was made between two strains of plants that are agriculturallyimportant. One strain was disease-resistant but herbicide-sensitive;the other strain was disease-sensitive but herbicide-resistant. Aplant breeder crossed the two plants and then allowed the F1 generation to self-fertilize. The following data were obtained:F1 generation: All offspring are disease-sensitive andherbicide-resistantF2 generation: 157 disease-sensitive, herbicide-resistant57 disease-sensitive, herbicide-sensitive54 disease-resistant, herbicide-resistant20 disease-resistant, herbicide-sensitiveTotal: 288Formulate a hypothesis that you think is consistent with the observeddata. Test the goodness of fit between the data and your hypothesisusing a chi square test. Explain what the chi square results meanarrow_forward
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