Introduction to Genetic Analysis
11th Edition
ISBN: 9781464109485
Author: Anthony J.F. Griffiths, Susan R. Wessler, Sean B. Carroll, John Doebley
Publisher: W. H. Freeman
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Chapter 2, Problem 43P
a.
Summary Introduction
To determine: The probability of taste detecting trait in the progeny.
Introduction: The human consists of 23 pairs of chromosomes, condensed form of chromatids which divide during cell division into daughter cells. The human has 22 autosomes and one pair of sex chromosomes. The sex chromosomes determine the sex in an individual based on the type of sex chromosomes that are present in the fusing gametes.
b.
Summary Introduction
To determine: The probability that the first two children will be taster.
Introduction: When the two or more alleles equally expressed themselves through the
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a. The ability to taste the chemical phenylthiocarbamideis an autosomal dominant phenotype, and the inabilityto taste it is recessive. If a taster woman with a nontasterfather marries a taster man who in a previous marriagehad a nontaster daughter, what is the probability thattheir first child will be(1) A nontaster girl(2) A taster girl(3) A taster boyb. What is the probability that their first two childrenwill be tasters of either sex?
Part VI: Discussion
1. Write the genetic designation for:
a. a male
b. a female
2. Which parent determines the sex of the offspring in humans? Explain.
3. Explain the term "autosomal."
4. In humans, right-handed is dominant to left. Free earlobes are dominant to attached. These are
autosomal characteristics. A right-handed man with attached earlobes whose mother was lefthanded
marries a left-handed woman with free earlobes whose mother had attached earlobes. You are the
genetic counselor. Construct a Punnett square to determine the types of children this couple could
produce.
A. Color-blindness is a recessive, sex-linked disorder in humans. A color-
blind man has a child with a woman who is a carrier of the disorder.
KEY: X= normal vision XC = color-blindness
2. Illustrate using a Punnett square the probability of having children
who will have normal vision and children who will be color-blind.
Guide Questions:
a. What is the genotype of the male?.
b. What is the genotype of the female?
c. What is the chance that the child will be color-blind?
d. What is the chance that a daughter will be color-blind?
e. What is the chance that a son will be color-blind?
Chapter 2 Solutions
Introduction to Genetic Analysis
Ch. 2 - Prob. 1PCh. 2 - Prob. 2PCh. 2 - Prob. 3PCh. 2 - Prob. 4PCh. 2 - Prob. 6PCh. 2 - Prob. 7PCh. 2 - Prob. 8PCh. 2 - Prob. 9PCh. 2 - Prob. 10PCh. 2 - Prob. 11P
Ch. 2 - Prob. 12PCh. 2 - Prob. 13PCh. 2 - Prob. 14PCh. 2 - Prob. 15PCh. 2 - Prob. 16PCh. 2 - Prob. 17PCh. 2 - Prob. 18PCh. 2 - Prob. 19PCh. 2 - Prob. 20PCh. 2 - Prob. 21PCh. 2 - Prob. 22PCh. 2 - Prob. 23PCh. 2 - Prob. 24PCh. 2 - Prob. 25PCh. 2 - Prob. 26PCh. 2 - Prob. 27PCh. 2 - Prob. 28PCh. 2 - Prob. 31PCh. 2 - Prob. 32PCh. 2 - Prob. 33PCh. 2 - Prob. 34PCh. 2 - Prob. 35PCh. 2 - Prob. 36PCh. 2 - Prob. 37PCh. 2 - Prob. 38PCh. 2 - Prob. 39PCh. 2 - Prob. 40PCh. 2 - Prob. 41PCh. 2 - Prob. 42PCh. 2 - Prob. 43PCh. 2 - Prob. 44PCh. 2 - Prob. 44.1PCh. 2 - Prob. 44.2PCh. 2 - Prob. 44.3PCh. 2 - Prob. 44.4PCh. 2 - Prob. 44.5PCh. 2 - Prob. 44.6PCh. 2 - Prob. 44.7PCh. 2 - Prob. 44.8PCh. 2 - Prob. 44.9PCh. 2 - Prob. 44.10PCh. 2 - Prob. 44.11PCh. 2 - Prob. 44.12PCh. 2 - Prob. 44.13PCh. 2 - Prob. 44.14PCh. 2 - Prob. 44.15PCh. 2 - Prob. 45PCh. 2 - Prob. 47PCh. 2 - Prob. 48PCh. 2 - Prob. 49PCh. 2 - Prob. 50PCh. 2 - Prob. 51PCh. 2 - Prob. 52PCh. 2 - Prob. 53PCh. 2 - Prob. 56PCh. 2 - Prob. 57PCh. 2 - Prob. 58PCh. 2 - Prob. 59PCh. 2 - Prob. 60PCh. 2 - Prob. 61PCh. 2 - Prob. 62PCh. 2 - Prob. 63PCh. 2 - Prob. 64PCh. 2 - Prob. 65PCh. 2 - Prob. 66PCh. 2 - Prob. 67PCh. 2 - Prob. 68PCh. 2 - Prob. 69PCh. 2 - Prob. 70PCh. 2 - Prob. 71PCh. 2 - Prob. 72PCh. 2 - Prob. 73PCh. 2 - Prob. 74PCh. 2 - Prob. 75PCh. 2 - Prob. 76PCh. 2 - Prob. 77PCh. 2 - Prob. 78PCh. 2 - Prob. 79P
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- Examine the following pedigrees. Which is the most likely mode of inheritance of each disorder? (a) autosomal recessive (b) autosomal dominant (c) X-linked recessive (d) a, b, or c (e) a or c 9.arrow_forward1. If a man, dominant homozygote for tongue rolling, is expecting a child with a woman that is heterozygotic for the trait – what is the probability for their firstborn to be a daughter being dominant homozygotic for tongue rolling? 2. A color-blind female is expecting with a color seeing male – what is the probability of a male child to see color? 3. In Sweden 1/500 are born with an autosomal recessive disorder called thalassemia. What is the carrier frequency within the population?arrow_forwardA Father and Mother are both carriers of the autosomal recessive condition known as albinism. They have one child, and a second child two years later. Their first child was not albino. Knowing this, you can say that the probability of the second child having albinism is Note Albinism is the result of a lack of pigmentation in skin and other cells. O a. 100% b. dependent on the the genotype of the first child O C. 50% O d. 25%arrow_forward
- 1. An albino man whose parents are both normal marries a woman one of whose parents is normal and the other albino. She has an albino sister. The couple has a normal son. a. Is albinism a dominant or a recessive trait? Explain your answer. b. Give the genotypes of all the persons involved. c.The couple plans to have more kids. What is the probability of their second child being normal?arrow_forwardShaded in black-white trait (Glucose-6-phosphate dehydrogenase deficiency) 1. What type of x-linked inheritance is shown in the chart above? a. X-linked Dominant b. X-linked Recessive c. Autosomal Dominance d. Autosomal Recessive 2. What is the genotype of individual 1 at generation I? a. XGXG b. XGXg c. XX d. XOarrow_forward12. A. B. C. A certain type of migraine headache (M) is dominant to no migraines (m). What is the genotype of a man who has migraine headaches if his father did not have them? What is the genotype of a man who has migraine headaches if his mother did not have them? If a woman without migraines marries a man who is heterozygous for migraines, what would you expect for the genotypes and phenotypes of their children? If two people who are heterozygous for migraines marry and have children, what would you expect for the genotypes and phenotypes of the children.arrow_forward
- re ||| E 6. Label the genotypes for this pedigree of an X-linked recessive disorder (red- green colorblindness). (a) 2 2 3 1 3 a. How do you know? b. Label the genotypes. 4 O To 2 4 5 5 6 6 7. Is the following pedigree autosomal recessive, autosomal dominant or X-linked recessive? 2 8 O T 58arrow_forward1. Mary and Joe are both healthy individuals. Joe has a mother who suffered from cystic fibrosis, an autosomal recessive disorder. Mary has been genetically tested in order to find out if she has the allele responsible for this disease and her tests came out positive. They are planning on having two children together in the near future. What is the probability that she and Joe will have either 2 boys who have the disorder, OR that they have one boy who has the disorder and one boy who does not? (in other words, what is the probability that any of these two outcomes takes place? a) 1/8 b) 1/16 c) 3/32 d) 1/64 e) 9/64arrow_forward17. Parents Jacob and Emma have had two children, Samuel and Matthew. Baby Samuel died at the age of nine days. When baby Matthew has trouble feeding, his parents take him in to the doctor. He is diagnosed with Maple Syrup Urine Disease (MSUD), a life-threatening condition in which the patient is not able to break down proteins from 19 their food. As Matthew receives treatment, Jacob and Emma are referred to a genetic counselor. The genetic counselor collects information about their family. Neither of Jacob's parents were affected by MSUD. Jacob had one brother and three sisters. One of these sisters died shortly after birth. Similarly, neither of Emma's parents were affected by MSUD. Emma had four brothers, and two of these died shortly after birth. a. Given what you know about Jacob and Emma's family, construct a pedigree that includes all three generations.arrow_forward
- . Assuming no involvement of the Bombay phenotype(in case you’ve already read ahead to Section 3.2):a. If a girl has blood type O, what could be the genotypes and corresponding phenotypes of her parents?b. If a girl has blood type B and her mother has bloodtype A, what genotype(s) and correspondingphenotype(s) could the other parent have?c. If a girl has blood type AB and her mother is alsoAB, what are the genotype(s) and correspondingphenotype(s) of any male who could not be thegirl’s father?arrow_forwardO 999 O c. A male with a female sibling d. A female with an identical twin who is male 978 e. A female with a non-identical twin who is male 9 10-13 Consider the pedigree illustrated above (i.e., Figure D in the supplemental file). Individual III-8 can best be described as... a. A female with no siblings b. A male with an identical twin who is female 10arrow_forwardWhile studying of the family tree with history of hypertrichosis (hyper hirsutism of the ear) this sign was founded only in the men and it was inherited from father to the son. Define the type of hypertrichosis inheritance? Select one: a. Y-linked b. Autosomal-recessive O c. Autosomal-dominant d. Recessive, X-linked e. Dominant, X-linkedarrow_forward
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