Introduction to Genetic Analysis
11th Edition
ISBN: 9781464109485
Author: Anthony J.F. Griffiths, Susan R. Wessler, Sean B. Carroll, John Doebley
Publisher: W. H. Freeman
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Chapter 2, Problem 44.14P
Summary Introduction
To determine: The method of solving the problems related to the pedigree chart of a family.
Introduction: The pedigree chart of the family can be used to study the different genotypes or the trait carried by different individuals.
Summary Introduction
To determine: The difference in the problems with the other ones.
Introduction: Each family has its own different pedigree chart related to any disease. In some cases, the parents are the carriers, whereas in some cases the parents are not infected.
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Students have asked these similar questions
Kate and her husband are both heterozygous for galactosemia gene. If Kate and her husband have four children, how many of their children are likely to have galactosemia?
Annabeth and Percy are concerned about having a
child with Niemann - Pick disease, which causes
abnormal accumulation of fat in cells. This condition,
which is very rare, has affected Annabeth's niece (her
brother's daughter) and Percy's aunt (his father's sister
). No one else in either family has the condition. What is
the probability Annabeth and Percy's first child will have
the disease? What is the probability Annabeth and
Percy's first child will have the disease?
1/64 1/32 1/24 1/18 1/12 1/9 1/4 None of these above
Phenylketonuria (PKU) is a disorder caused by a recessive allele. Two carrier individuals have progeny. Answer the following questions in order and show solutions whenever relevant.
1. If they have a normal child, what is the probability that he or she will be heterozygous?
2. If they have three children, what is the probability of having 2 affected children and one normal child?
Chapter 2 Solutions
Introduction to Genetic Analysis
Ch. 2 - Prob. 1PCh. 2 - Prob. 2PCh. 2 - Prob. 3PCh. 2 - Prob. 4PCh. 2 - Prob. 6PCh. 2 - Prob. 7PCh. 2 - Prob. 8PCh. 2 - Prob. 9PCh. 2 - Prob. 10PCh. 2 - Prob. 11P
Ch. 2 - Prob. 12PCh. 2 - Prob. 13PCh. 2 - Prob. 14PCh. 2 - Prob. 15PCh. 2 - Prob. 16PCh. 2 - Prob. 17PCh. 2 - Prob. 18PCh. 2 - Prob. 19PCh. 2 - Prob. 20PCh. 2 - Prob. 21PCh. 2 - Prob. 22PCh. 2 - Prob. 23PCh. 2 - Prob. 24PCh. 2 - Prob. 25PCh. 2 - Prob. 26PCh. 2 - Prob. 27PCh. 2 - Prob. 28PCh. 2 - Prob. 31PCh. 2 - Prob. 32PCh. 2 - Prob. 33PCh. 2 - Prob. 34PCh. 2 - Prob. 35PCh. 2 - Prob. 36PCh. 2 - Prob. 37PCh. 2 - Prob. 38PCh. 2 - Prob. 39PCh. 2 - Prob. 40PCh. 2 - Prob. 41PCh. 2 - Prob. 42PCh. 2 - Prob. 43PCh. 2 - Prob. 44PCh. 2 - Prob. 44.1PCh. 2 - Prob. 44.2PCh. 2 - Prob. 44.3PCh. 2 - Prob. 44.4PCh. 2 - Prob. 44.5PCh. 2 - Prob. 44.6PCh. 2 - Prob. 44.7PCh. 2 - Prob. 44.8PCh. 2 - Prob. 44.9PCh. 2 - Prob. 44.10PCh. 2 - Prob. 44.11PCh. 2 - Prob. 44.12PCh. 2 - Prob. 44.13PCh. 2 - Prob. 44.14PCh. 2 - Prob. 44.15PCh. 2 - Prob. 45PCh. 2 - Prob. 47PCh. 2 - Prob. 48PCh. 2 - Prob. 49PCh. 2 - Prob. 50PCh. 2 - Prob. 51PCh. 2 - Prob. 52PCh. 2 - Prob. 53PCh. 2 - Prob. 56PCh. 2 - Prob. 57PCh. 2 - Prob. 58PCh. 2 - Prob. 59PCh. 2 - Prob. 60PCh. 2 - Prob. 61PCh. 2 - Prob. 62PCh. 2 - Prob. 63PCh. 2 - Prob. 64PCh. 2 - Prob. 65PCh. 2 - Prob. 66PCh. 2 - Prob. 67PCh. 2 - Prob. 68PCh. 2 - Prob. 69PCh. 2 - Prob. 70PCh. 2 - Prob. 71PCh. 2 - Prob. 72PCh. 2 - Prob. 73PCh. 2 - Prob. 74PCh. 2 - Prob. 75PCh. 2 - Prob. 76PCh. 2 - Prob. 77PCh. 2 - Prob. 78PCh. 2 - Prob. 79P
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- Salim and Sara are contemplating having children, but Salim’s brother has galactosemia and Sara has a sister who has three children, one of whom is affected. Sara dad has no history in his family of any sign of the diease and it is assumed to be homozygous normal. What is the probability that salim and saras first child will have galactosemia?arrow_forwardSalim and Sara are contemplating having children, but Salim’s brother has galactosemia and Sara has a sister who has three children, none of whom is affected. Sara dad has no history in his family of any sign of the diease and it is assumed to be homozygous normal. What is the probability that salim and saras first child will have galactosemia?arrow_forwardA young couple went to see a genetic counselor because each had a sibling affected with cystic fibrosis. (Cystic fibrosis is a recessive disease and neither member of the couple nor any of their four parents is affected). What is the probability that the female of this couple is a carrier and what are the chances that their child will be affected with cystic fibrosis?arrow_forward
- Galactosemia is an autosomal recessive human disease that is treatable by restricting lactose and glucose in the diet. If two individuals who are both heterozygous for the recessive galactosemia allele have three children, what is the probability that two of the children will have galactosemia and one will not? Type your answer as a fraction (not a decimal), with no spaces (e.g. 1/16).arrow_forwardA recently married couple are both heterozygous for cystic fibrosis, a recessive genetic disorder. They would like to start a family and would like to have two children. What is the probability that both their first and second child would have cystic fibrosis?arrow_forwardSalim and Sara are contemplating having children, but Salim’s brother has galactosemia and Sara’s great-grandmother also had galactosemia. Sara has a sister who has three children, none of whom is affected.a. Construct a genetic pedigree for this family showing the possible genotype of each member.b. What is the probability that Salim and Sara’s first child will have galactosemia? Explain your calculations.arrow_forward
- Phenylketonuria (PKU) is a disorder caused by a recessive allele. Two carrier individuals have progeny. If they have three children, what is the probability of having 2 affected children and one normal child?arrow_forwardPhenylketonuria (PKU) is a disorder caused by a recessive allele. Two carrier individuals have progeny. If they have a normal child, what is the probability that he or she will be heterozygous? Show solutions.arrow_forwardwhat is the probability that a couple (both heterozygous for the same recessive mutation) will have two children with the disease if the couple plans to have four children in total?arrow_forward
- Phenylketonuria (PKU) is a disorder caused by a recessive allele. Two carrier individuals have progeny. Answer the following questions in order and show solutions whenever relevant. If they have three children, what is the probability of having 2 affected children and one normal child?arrow_forwardBob and Joan know from a blood test that they are each heterozygous (carriers) for the autosomal recessive gene that causes sickle cell disease. If their first three children are healthy, what is the probability that their fourth child will have the disease?arrow_forwardA recently married couple are both heterozygous for cystic fibrosis, a recessive genetic disorder. They would like to start a family and would like to have two children. a.) What is the probability that their second pregnancy would result in a child with cystic fibrosis? b.) What is the probability that their second pregnancy would result in a child with cystic fibrosis?arrow_forward
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