Introduction to Genetic Analysis
11th Edition
ISBN: 9781464109485
Author: Anthony J.F. Griffiths, Susan R. Wessler, Sean B. Carroll, John Doebley
Publisher: W. H. Freeman
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Chapter 2, Problem 39P
Summary Introduction
To determine: The deduction of the inheritance of the three cotyledons.
Introduction: When the two or more alleles equally expressed themselves through the
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A variety of opium poppy (Papaver somniferum L.) with lacerate leaves was crossed with a variety that has normal leaves. All the F1 had lacerate leaves. Two F1 plants were interbred to produce the F2. Of the F2, 249 had lacerate leaves and 16 had normal leaves. Give genotypes for all the plants in the P, F1, and F2 generations. Explain how lacerate leaves are determined in the opium poppy.
Mendelian ratios are modified in crosses involving autotetraploids.Assume that one plant expresses the dominant trait greenseeds and is homozygous (WWWW). This plant is crossed to onewith white seeds that is also homozygous (wwww). If only onedominant allele is sufficient to produce green seeds, predict theF1 and F2 results of such a cross. Assume that synapsis betweenchromosome pairs is random during meiosis.
A homozygous strain of corn that produces yellow kernels is crossed with another homozygous strain that produces purple kernels. When the F1 are interbred, 197 of the F2 are yellow and 153 are prurple. Give the genotypes of the yellow and purple F2 and propose a genetic model that explains the inheritance of these kernel colors in corn.
Chapter 2 Solutions
Introduction to Genetic Analysis
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- In a variety of tomato plant ,the leaves maybe pure green,pure white,or variegated (mixture). a)when 2 variegated plants were crossed,87 offspring were produced,of these 20 were green,46 were variegated and 21 remain died soon after germination.Draw a genetic diagram to explain these results,why did 21 of them diedarrow_forwardA homozygous variety of opium poppy (Papaver somniferum Laciniatum) with lacerate leaves was crossed with another homozygous variety with normal leaves. All the F₁ had lacerate leaves (jagged-edged leaves). Two F₁ plants were crossed to produce the F2. Of the F2, 249 had lacerate leaves and 16 had normal leaves. How are lacerate leaves determined in the opium poppy? two genes, with a dominant allele at both loci two genes, where one allele at a single locus is recessive lethal one gene, with codominant alleles at a single locus two genes, with a dominant allele at either or both loci Give genotypes for all the plants in the P, F₁, and F2 generations. Some generations will have more than one genotype. P F₁ F₂ (lacerate) F₂ (normal) aabb A_B_ Answer Bank aaB AaBb A_bb AABBarrow_forwardYou carry out a trihybrid cross (a cross in which the parental plants differ for three characters) between a tall pea plant with round, yellow seeds (TT RR YY) and a short pea plant with wrinkled, green seeds (tt rr yy). The parental plants are homozygous for all of the three characters. They are crossed to produce the F1 generation. Tall, round, and yellow are the dominant traits for each character. What will be the phenotypes of the F1 generation?arrow_forward
- J.W. McKay crossed a stock (true-breeding) melon plant that produced tan seeds with a plant that only produced red seeds and obtained the following results (J.W. McKay. 1936. Journal of Heredity 27:110-112). Cross F1 F2 Tan x red 13 tan 93 tan, 24 red a) Explain the inheritance of tan seeds and red seeds in this plant. b) Assign symbols for the alleles in this cross and draw out the Punnett Squares for the initial cross and the F1 cross.arrow_forwardIn an intra-species cross performed in mustard plants of two different species (Brassica juncea and Brassica oleracea), a tall plant (TT) was crossed with a dwarf (tt) variety in each of the two species. The members of the F1 generation were crossed to produce the F2 generation. Of the F2 plants, Brassica juncea had 60 tall and 20 dwarf plants, while Brassica oleracea had 100 tall and 20 dwarf plants. Use chi-square analysis to analyze these results.arrow_forwardA pure breeding strain of squash that produced disk-shaped fruits was crossed with a pure- breeding strain having long fruits. The first filial generation had disk fruits, but the second filial generation showed a new phenotype, sphere, and was composed of the following proportions: disk 270, sphere 178, long 32. Propose an explanation for these results, and show the genotypes of P, First filial generation and second filial generation.arrow_forward
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