Introduction to Genetic Analysis
11th Edition
ISBN: 9781464109485
Author: Anthony J.F. Griffiths, Susan R. Wessler, Sean B. Carroll, John Doebley
Publisher: W. H. Freeman
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Chapter 2, Problem 44.2P
Summary Introduction
To determine: The representation of hereditary pattern of galactosemia through a Punnett square.
Introduction. The genes are the sequence of
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Salim and Sara are contemplating having children, but Salimās brother has galactosemia and Saraās great-grandmother also had galactosemia. Sara has a sister who has three children, none of whom is affected.
What is the probability that Salim and Saraās first child will have galactosemia? Explain your calculations.
Galactosemia is an autosomal recessive human disease that is treatable by restricting lactose and glucose in the diet.
If two individuals who are both heterozygous for the recessive galactosemia allele haveĀ threeĀ children, what is the probability thatĀ two of the children will have galactosemia and one will not?
Type your answer as a fraction (not a decimal), with no spaces (e.g. 1/16).
Kate and her husband are both heterozygous for galactosemia gene. If Kate and her husband have four children, how many of their children are likely to have galactosemia?
Chapter 2 Solutions
Introduction to Genetic Analysis
Ch. 2 - Prob. 1PCh. 2 - Prob. 2PCh. 2 - Prob. 3PCh. 2 - Prob. 4PCh. 2 - Prob. 6PCh. 2 - Prob. 7PCh. 2 - Prob. 8PCh. 2 - Prob. 9PCh. 2 - Prob. 10PCh. 2 - Prob. 11P
Ch. 2 - Prob. 12PCh. 2 - Prob. 13PCh. 2 - Prob. 14PCh. 2 - Prob. 15PCh. 2 - Prob. 16PCh. 2 - Prob. 17PCh. 2 - Prob. 18PCh. 2 - Prob. 19PCh. 2 - Prob. 20PCh. 2 - Prob. 21PCh. 2 - Prob. 22PCh. 2 - Prob. 23PCh. 2 - Prob. 24PCh. 2 - Prob. 25PCh. 2 - Prob. 26PCh. 2 - Prob. 27PCh. 2 - Prob. 28PCh. 2 - Prob. 31PCh. 2 - Prob. 32PCh. 2 - Prob. 33PCh. 2 - Prob. 34PCh. 2 - Prob. 35PCh. 2 - Prob. 36PCh. 2 - Prob. 37PCh. 2 - Prob. 38PCh. 2 - Prob. 39PCh. 2 - Prob. 40PCh. 2 - Prob. 41PCh. 2 - Prob. 42PCh. 2 - Prob. 43PCh. 2 - Prob. 44PCh. 2 - Prob. 44.1PCh. 2 - Prob. 44.2PCh. 2 - Prob. 44.3PCh. 2 - Prob. 44.4PCh. 2 - Prob. 44.5PCh. 2 - Prob. 44.6PCh. 2 - Prob. 44.7PCh. 2 - Prob. 44.8PCh. 2 - Prob. 44.9PCh. 2 - Prob. 44.10PCh. 2 - Prob. 44.11PCh. 2 - Prob. 44.12PCh. 2 - Prob. 44.13PCh. 2 - Prob. 44.14PCh. 2 - Prob. 44.15PCh. 2 - Prob. 45PCh. 2 - Prob. 47PCh. 2 - Prob. 48PCh. 2 - Prob. 49PCh. 2 - Prob. 50PCh. 2 - Prob. 51PCh. 2 - Prob. 52PCh. 2 - Prob. 53PCh. 2 - Prob. 56PCh. 2 - Prob. 57PCh. 2 - Prob. 58PCh. 2 - Prob. 59PCh. 2 - Prob. 60PCh. 2 - Prob. 61PCh. 2 - Prob. 62PCh. 2 - Prob. 63PCh. 2 - Prob. 64PCh. 2 - Prob. 65PCh. 2 - Prob. 66PCh. 2 - Prob. 67PCh. 2 - Prob. 68PCh. 2 - Prob. 69PCh. 2 - Prob. 70PCh. 2 - Prob. 71PCh. 2 - Prob. 72PCh. 2 - Prob. 73PCh. 2 - Prob. 74PCh. 2 - Prob. 75PCh. 2 - Prob. 76PCh. 2 - Prob. 77PCh. 2 - Prob. 78PCh. 2 - Prob. 79P
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- Along with the trait in the pedigree, individual IV-6 and the woman are also both heterozygous for the autosomal dominant allele causing Huntington's disease. If they have a child, what is the probability that it will be affected byĀ at least one of these traits? Remember to include both the trait in the pedigree and Huntington's disease in your calculations. Enter your answer to two decimal places (e.g., 0.55).arrow_forwardA couple seeks advice from a genetic counselor because they know that they are both carriers for cystic fibrosis (which is autosomal recessive), and the woman is a carrier for Duchenne muscular dystrophy (which is sex-linked recessive).Ā For each of their future sons and daughters (calculate separately), what is the probability that they will be affected for: Both cystic fibrosis and nuscular dystrophy If the coupleās first born son has both cystic fibrosis and muscular dystrophy, what is the probability that their second born son will have both diseases?arrow_forwardA couple seeks advice from a genetic counselor because they know that they are both carriers for cystic fibrosis (which is autosomal recessive), and the woman is a carrier for Duchenne muscular dystrophy (which is sex-linked recessive). For each of their future sons and daughters (calculate separately), what is the probability that they will be affected for: Cystic fibrosis Duchenne muscular dystrophyarrow_forward
- Phenylketonuria (PKU) is a disorder caused by a recessive allele. Two carrier individuals have progeny. Answer the following questions in order and show solutions whenever relevant. 1. If they have a normal child, what is the probability that he or she will be heterozygous? 2. If they have three children, what is the probability of having 2 affected children and one normal child?arrow_forwardKelly and Sam are both unaffected carriers for two autosomal recessive disorders, PKU (chromosome 12) and cystic fibrosis (chromosome 7). They are expecting a daughter. What is the probability that she will be unaffected by PKU, but effected by cystic fibrosis? O 1/16 O 3/16 O 1/2 Š 3/4 O 9/16arrow_forwardThe three genes X, Y, and Z are linked on an autosomal chromosome in humans (X to Y is 15 cM, and Y to Z is 18 cM). If an individual that is heterozygous at all three loci (XYZ/xyz) has children with an individual that is homozygous recessive at all three loci (xyz/xyz), what is the probability that they will have a child that is phenotypically identical to either parent (X-Y-Z- or xxyyzz)? Assume there is no genetic interference to double crossover events at this site.arrow_forward
- *Cystic fibrosis is a rare autosomal recessive condition. phenotypically normal man whose father had cystic fibrosis marries a phenotypically normal woman from outside the family.Ā² a) Draw the pedigree as far as described. b) If the frequency of heterozygotes in the general population is 1/50, what is the probability that the couple's first child will have cystic fibrosis? c) If the first child does have cystic fibrosis, what is the probability that the second child will be normal?arrow_forwardSalim and Sara are contemplating having children, but Salimās brother has galactosemia and Sara has a sister who has three children, none of whom is affected. Sara dad has no history in his family of any sign of the diease and it is assumed to be homozygous normal. What is the probability that salim and saras first child will have galactosemia?arrow_forwardA young couple went to see a genetic counselor because each had a sibling affected with cystic fibrosis. (Cystic fibrosis is a recessive disease and neither member of the couple nor any of their four parents is affected).Ā What is the probability that the female of this couple is a carrier and what are the chances that their child will be affected with cystic fibrosis?arrow_forward
- Salim and Sara are contemplating having children, but Salimās brother has galactosemia and Sara has a sister who has three children, one of whom is affected. Sara dad has no history in his family of any sign of the diease and it is assumed to be homozygous normal. What is the probability that salim and saras first child will have galactosemia?arrow_forwardThe accompanying pedigree shows a family in which one child (II-1) has an autosomal recessive condition. On the basis of this fact alone, provide the following information.Ā Ā Ā 1) What is the chance that among the three children in generation II who have the dominant phenotype, one of them isĀ AAAAĀ and two of them areĀ AaAa? (Hint: Consider all possible orders of genotypes.) Express your answer to two decimal places.arrow_forwardSalim and Sara are contemplating having children, but Salimās brother has galactosemia and Saraās great-grandmother also had galactosemia. Sara has a sister who has three children, none of whom is affected.a.Ā Ā Ā Ā Construct a genetic pedigree for this family showing the possible genotype of each member.b.Ā Ā Ā What is the probability that Salim and Saraās first child will have galactosemia? Explain your calculations.arrow_forward
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