Organic Chemistry: Structure and Function
Organic Chemistry: Structure and Function
8th Edition
ISBN: 9781319079451
Author: K. Peter C. Vollhardt, Neil E. Schore
Publisher: W. H. Freeman
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Chapter 1, Problem 50P

(a)

Interpretation Introduction

Interpretation: The hybridization of the orbitals having unshared pair of electrons in CH3CH2 , H2C=CH and HCC needs to be determined.

Concept Introduction: The hybridization is defined as mixing of atomic orbitals. The new hybrid orbitals are formed equal in the number of atomic orbitals involved in the mixing.

(b)

Interpretation Introduction

Interpretation: The relative abilities of CH3CH2 , H2C=CH and HCC to accommodate a negative charge needs to be explained.

Concept Introduction: The hybridization is defined as mixing of atomic orbitals. The new hybrid orbitals are formed equal in the number of atomic orbitals involved in the mixing.

(c)

Interpretation Introduction

Interpretation: The given species needs to be ranked in order of the acid strength.

Concept Introduction: The species which can form stable negative charge will be most acidic because it will readily donate hydrogen atom to attain stability.

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For each statement, indicate whether it is true or false. (a) The greater the orbital overlap in a bond, the weaker the bond. [b] The greater the orbital overlap in a bond, the shorter the bond. [c] To create a hybrid orbital, you could use the s orbital on one atom with a p orbital on another atom. [d] Nonbonding electron pairs cannot occupy a hybrid orbital.
The compound 2,6-dimethylpyrazine(below)gives choco-late its odor and is used in flavorings.(a) Which atomic orbitals mix to form the hybrid orbitals of N? (b) In what type of hybrid orbital do the lone pairs of N reside? (c) Is C in CH₃ hy-bridized the same as any C in the ring? Explain.
The compound 2,6-dimethylpyrazine (below) gives chocolate its odor and is used in flavorings. (a) Which atomic orbitals mix to form the hybrid orbitals of N? (b) In what type of hybrid orbital do the lone pairs of N reside? (c) Is C in CH3 hybridized the same as any C in the ring? Explain.
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