Organic Chemistry: Structure and Function
Organic Chemistry: Structure and Function
8th Edition
ISBN: 9781319079451
Author: K. Peter C. Vollhardt, Neil E. Schore
Publisher: W. H. Freeman
bartleby

Concept explainers

Question
Book Icon
Chapter 3, Problem 31P

(a)

Interpretation Introduction

Interpretation: Major organic product of monobromination of pentane at 125 °C should be identified.

Concept introduction: The monobromination performed with ultraviolet light proceeds via radical chain mechanism.

Tertiary C – H bonds react in halogenations more readily than secondary those in turn are faster to react than primary. This can be attributed to stability of radical formed upon C – H bond cleavage via hyperconjugation.

The phenomenon of hyperconjugation refers to donation of σ electrons into the partly vacant p orbital lobes of radical carbon. More will be number of σ orbital capable of donation of electrons more is the stabilization.

(b)

Interpretation Introduction

Interpretation: All Newman projections of major brominated products in staggered conformations should be drawn.

Concept introduction: Various interconvertible forms that result from rotation around the C–C bind in ethane are termed as conformer. To depict such conformation Newman projections are written. These are obtained by conversion of hashed-wedged line structure simply when molecule is viewed in a plane along the C–C as illustrated as follows:

  Organic Chemistry: Structure and Function, Chapter 3, Problem 31P , additional homework tip  1

Thus in Newman's projection of simple ethane molecule the “front” C is depicted as intersection of three bonds with three attached H . The other three bonds connect to the large circle corresponding to “back” carbon in C–C bond.

(c)

Interpretation Introduction

Interpretation: Qualitative plot of potential energy against torsional angle for C2C3 rotation in this molecule should be drawn.

Concept introduction: As rotation is carried out along C – C axis, energy changes occur due to bond rotation from staggered to eclipsed conformation. This change amounts to torsional strain. Energy difference between eclipsed and staggered conformations corresponds to barrier that must be overcome for rotation. This is also termed as activation energy.

The potential energy shows peaks and falls. This corresponds to transition from staggered and eclipsed conformation molecule adopts with each 60 ° rotation as illustrated in lateral view below:

  Organic Chemistry: Structure and Function, Chapter 3, Problem 31P , additional homework tip  2

Staggered conformation that has substituents on both carbons farthest apart is regarded most stable due to least torsional strain, whereas the eclipsed has large amount of torsional strain due to steric repulsions. Therefore in potential-energy diagram, peak corresponds to eclipsed while the valley corresponds to stable staggered conformation.

Blurred answer
Students have asked these similar questions
Biphenyl has the following structure.(a) Is biphenyl a (fused) polynuclear aromatic hydrocarbon?(b) How many pi electrons are there in the two aromatic rings of biphenyl? How does this number compare with that for naphthalene?(c) The heat of hydrogenation for biphenyl is about 418 kJ>mol (100 kcal>mol). Calculate theresonance energy of biphenyl.(d) Compare the resonance energy of biphenyl with that of naphthalene and with that of two benzene rings. Explain thedifference in the resonance energies of naphthalene and biphenyl.
The skeletal line formula for a branched alkene is shown below. (i) What is the molecular formula of this compound? (ii) How many carbon atoms are in the longest chain, ignoring the double bond? (iii) What is the longest chain incorporating both carbons of the double bond? (iv) How many substituents are on this chain? (v) Give the IUPAC name for this compound. [6]
Chlorination of 2-butanone yields two isomeric products, each having the molecular formula C4H7ClO. (a) What are these two compounds? (b) Write structural formulas for the enol intermediates that lead to each of these compounds. (c) Using curved arrows, show the flow of electrons in the reaction of each of the enols with Cl2.
Knowledge Booster
Background pattern image
Chemistry
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
  • Text book image
    Organic Chemistry
    Chemistry
    ISBN:9781305580350
    Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
    Publisher:Cengage Learning
Text book image
Organic Chemistry
Chemistry
ISBN:9781305580350
Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Publisher:Cengage Learning