(a)
The currentthroughR5 with and without ammeter for the given valuesof the resistor.
Answer to Problem 2.78HP
The current through resistor:
With meter in circuit:
Without meter in circuit:
Explanation of Solution
Given information:
The given circuit is shown below.
Also,
Calculation:
First, find an expression for the current through
And
Therefore,
Hence for given values of R5
The current through resistor:
With meter in circuit,
Without meter in circuit,
(b)
The current through R5 with and without ammeter for the given values of the resistor.
Answer to Problem 2.78HP
The current through resistor:
With meter in circuit:
Without meter in circuit:
Explanation of Solution
Given information:
The given circuit is shown below.
Also,
Calculation:
First, find an expression for the current through
And
Therefore,
Hence for given values of R5
The current through resistor:
With meter in circuit,
Without meter in circuit,
(c)
The current through R5 with and without ammeter for the given values of the resistor.
Answer to Problem 2.78HP
The current through resistor:
With meter in circuit:
Without meter in circuit:
Explanation of Solution
Given information:
The given circuit is shown below.
Also,
Calculation:
First, find an expression for the current through
And
Therefore,
Hence for given values of R5
The current through resistor:
With meter in circuit,
Without meter in circuit,
(d)
The current through R5 with and without ammeter for the given values of the resistor.
Answer to Problem 2.78HP
The current through resistor:
With meter in circuit:
Without meter in circuit:
Explanation of Solution
Given information:
The given circuit is shown below.
Also,
Calculation:
First, find an expression for the current through
And
Therefore,
Hence for given values of R5
The current through resistor:
With meter in circuit,
Without meter in circuit,
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Chapter 2 Solutions
Principles and Applications of Electrical Engineering
- Determine the values of vx and iy in the circuit of Figure Q2 (b) and determine the number of branches and nodes in the circuit shown in Figure Q2 (b).arrow_forwardAn ammeter is used as shown in Figure P2.78. Theammeter model consists of an ideal ammeter in serieswith a resistance. The ammeter model is placed in thebranch as shown in the figure. Find the current throughR5 both with and without the ammeter in the circuit for the following values, assuming that RS = 20 ,R1 = 800 , R2 = 600 , R3 = 1.2 k, R4 = 150 ,and VS = 24 V.a. R5 = 1 kb. R5 = 100 c. R5 = 10 d. R5 = 1arrow_forwardFor the circuit shown in Figure P2.43, finda. The equivalent resistance seen by the source.b. The current i.c. The power delivered by the source.d. The voltages v1, v2.e. The minimum power rating required for R1.arrow_forward
- Consider the circuit shown in Figure P2.24. Suppose that the value of vs is adjusted until v2=5 V.Determine the new value of vs.[Hint: Start at the right-hand side of the circuit and compute currents and voltages, moving to the left until you reach the source.]arrow_forwardIn the circuit of Figure P2.61, the power absorbed by the 20- resistor is 20W. Find R. Given: VS = 50 V, R1 = 20 , R2 = 5 , R3 = 2 , R4 = 8 , R5 = 8 , R6 = 30 .arrow_forwardConnect a 1-V voltage source across the terminals of the network shown in Figure P2.1(a). Then, solve the network by the mesh-current technique to find the current through the source. Finally, divide the source voltage by the current to determine the equivalent resistance looking into the terminals. Check your answer by combining resistances in series and parallel.arrow_forward
- In the circuit of Figure P2.36, if v1 = v/4 and thepower delivered by the source is 40 mW, find R, v, v1,and i. Given: R1 = 8 k, R2 = 10 k, R3 = 12 k.arrow_forwardAssuming R0 = 2 , R1 = 1 , R2 = 4/3 , R3 = 6 , and VS = 12 V in the circuit of Figure P2.55, use Kirchhoff’s voltage law and Ohm’s law to finda. ia, ib, and ic.b. The current through each resistance.arrow_forwardFind the equivalent resistance seen by the sourceand the current i in the circuit of Figure P2.60. Given:VS = 12 V, R0 = 4 , R1 = 2 , R2 = 50 ,R3 = 8 , R4 = 10 , R5 = 12 , R6 = 6 .arrow_forward
- For the circuit shown in Figure P2.37, finda. The equivalent resistance seen by the source.b. The current i.c. The power delivered by the source.d. The voltages v1 and v2.e. The minimum power rating required for R1.Given: v = 24 V, R0 = 8 , R1 = 10 , R2 = 2 .arrow_forwardFind the equivalent resistance for the infinite network shown in Figure P2.12(a). Because of its form, this network is called a semi-infinite ladder. [Hint: If another section is added to the ladder as shown in Figure P2.12(b), the equivalent resistance is the same. Thus, working from Figure P2.12(b), we can write an expression for Req in terms of Req.Then, we can solve for Req.arrow_forwardDetermine the value of v2 and the power delivered by the source in the circuit of Figure P2.24 by using mesh-current analysis.arrow_forward
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