Foundations of Materials Science and Engineering
Foundations of Materials Science and Engineering
6th Edition
ISBN: 9781259696558
Author: SMITH
Publisher: MCG
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Chapter 9.13, Problem 20KCP

(a) Define the hardenability of a steel. (b) Define the hardness of a steel. (c) Describe the Jominy hardenability test. (d) Explain how the data for the plotting of the Jominy hardenability curve arc obtained and how the curve is constructed. (e) Of what industrial use arc Jominy hardenability curves?

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Q1: Austenitized 40 mm diameter 5140 alloy steel bar is quenched in agitated oil. Predict what is the Rockwell hardness of this bar will be at (a) its surface and (b) its center (c) What do you think about the difference in hardness number between the center and surface (d) Differentiate between hardness and hardenability (e) Rank the steels in the figure below from lowest to highest hardenability and explain why. Cooling rate at 700°C (°C/sec) 300 150 011/3 55 100 600 Bar diameter (mm) 80 60 40 20 0 OLL 0 0 ww 25 12.5 8 5 S -------------- M-R 10 3/4-R Agitated oil 15 20 1/4 3/4 Distance from quenched end. De (Jominy distance) 5.5 4 3 Bar diameter (in.) 0 25 mm 1 in. Hardness (Rockwell C) Where (C = center, S = surface, M-R mid-radius) 65 60 55 50 45 40 35 30 25 20 15 10 0 10 1 20 Distance from quenched end (mm) 5140 1 30 L 2 4 6 8 10 12 14 16 18 20 22 24 26 28 30 32 Distance from quenched end (sixteenths of an inch) 4340 40 9840 4140 8640 50
The figure shows two work pieces of steel of 0.15 %C and 1.2 %C with different dimensions. Compare between them regarding:- 1- The existed phases and the expected mechanical properties of each. 2- Give 5 important applications for each alloy. 3- The stages of Normalizing treatments for each one. 900 800 1 Aj = 727°C 0.0218 0.77 700 Dimensions of (1.5*1.5*1.5) inch Dimensions of (1*1*1) inch 0.2 0.4 0.6 0.8 1.0 1.2 1.4 6.67 Weight percent carbon Temperature ("C)
What is the tensile curve of a steel material containing 0.6 carbon after water quenching, tempering (500°C+30 min) and normalization (800°C+1 hour) annealing? Show and explain the tensile test curve.

Chapter 9 Solutions

Foundations of Materials Science and Engineering

Ch. 9.13 - Describe the process-annealing heat treatment for...Ch. 9.13 - What is the normalizing heat treatment for steel...Ch. 9.13 - Describe the tempering process for a plain-carbon...Ch. 9.13 - (a) Describe the martempering (marquenching)...Ch. 9.13 - (a) Describe the austempering process for a...Ch. 9.13 - (a) Explain the numbering system used by the AISI...Ch. 9.13 - (a) What arc some of the limitations of...Ch. 9.13 - (a) What compounds docs aluminum form in steels?...Ch. 9.13 - Prob. 19KCPCh. 9.13 - (a) Define the hardenability of a steel. (b)...Ch. 9.13 - Prob. 21KCPCh. 9.13 - Prob. 22KCPCh. 9.13 - Prob. 23KCPCh. 9.13 - What is the difference between a coherent...Ch. 9.13 - Prob. 25KCPCh. 9.13 - Prob. 26KCPCh. 9.13 - Prob. 27KCPCh. 9.13 - (a) Describe the three principal casting processes...Ch. 9.13 - Prob. 29KCPCh. 9.13 - Prob. 30KCPCh. 9.13 - Prob. 31KCPCh. 9.13 - Prob. 32KCPCh. 9.13 - Prob. 33KCPCh. 9.13 - Prob. 34KCPCh. 9.13 - Prob. 35KCPCh. 9.13 - (a) What are the cast irons? (b) What is their...Ch. 9.13 - Prob. 37KCPCh. 9.13 - Prob. 38KCPCh. 9.13 - Prob. 39KCPCh. 9.13 - Prob. 40KCPCh. 9.13 - Prob. 41KCPCh. 9.13 - Prob. 42KCPCh. 9.13 - Prob. 43KCPCh. 9.13 - Prob. 44KCPCh. 9.13 - Prob. 45KCPCh. 9.13 - (a) Why arc titanium and its alloys of special...Ch. 9.13 - Prob. 47KCPCh. 9.13 - Prob. 48KCPCh. 9.13 - Prob. 49KCPCh. 9.13 - Prob. 50KCPCh. 9.13 - Prob. 51KCPCh. 9.13 - Prob. 52KCPCh. 9.13 - Describe the structural changes that take place...Ch. 9.13 - Describe the structural changes that take place...Ch. 9.13 - If a thin sample of a eutectoid plain-carbon steel...Ch. 9.13 - If a thin sample of a eutectoid plain-carbon steel...Ch. 9.13 - (a) What types of microstructures arc produced by...Ch. 9.13 - A 0.65 % C hypoeutectoid plain-carbon steel is...Ch. 9.13 - A 0.25% C hypoeutectoid plain-carbon steel is...Ch. 9.13 - A plain-carbon steel contains 93 wt % ferrite7 wt%...Ch. 9.13 - A plain-carbon steel contains 45 wt% proeutectoid...Ch. 9.13 - A plain-carbon steel contains 5.9 wt%...Ch. 9.13 - A 0.90% C hypereutectoid plain-carbon steel is...Ch. 9.13 - A 1.10% C hypereutectoid plain-carbon steel is...Ch. 9.13 - If a hypereutectoid plain-carbon steel contains...Ch. 9.13 - A hypereutectoid plain-carbon steel contains 10.7...Ch. 9.13 - A plain-carbon steel contains 20.0 wt%...Ch. 9.13 - A 0.55% C hypoeutectoid plain-carbon steel is...Ch. 9.13 - A hypoeutectoid steel contains 44.0 wt% eutectoid...Ch. 9.13 - A hypoeutectoid steel contains 24.0 wt% eutectoid...Ch. 9.13 - A 1.10 % C hypereutectoid plain-carbon steel is...Ch. 9.13 - Draw timetemperature cooling paths for a 1080...Ch. 9.13 - Draw timetemperature cooling paths for a 1080...Ch. 9.13 - Thin pieces of 0.3-mm-thick hot-rolled strips of...Ch. 9.13 - Prob. 75AAPCh. 9.13 - Prob. 76AAPCh. 9.13 - Prob. 77AAPCh. 9.13 - Prob. 78AAPCh. 9.13 - Prob. 79AAPCh. 9.13 - Prob. 80AAPCh. 9.13 - Prob. 81AAPCh. 9.13 - Prob. 82AAPCh. 9.13 - An austenitized 40-mm-diameter 4340 steel bar is...Ch. 9.13 - Prob. 84AAPCh. 9.13 - Prob. 85AAPCh. 9.13 - Prob. 86AAPCh. 9.13 - Prob. 87AAPCh. 9.13 - Prob. 88AAPCh. 9.13 - Prob. 89AAPCh. 9.13 - Prob. 90AAPCh. 9.13 - Prob. 91AAPCh. 9.13 - Prob. 92AAPCh. 9.13 - (a) For a plain-carbon steel with 1 wt % carbon...Ch. 9.13 - Prob. 94SEPCh. 9.13 - Prob. 95SEPCh. 9.13 - Prob. 96SEPCh. 9.13 - Prob. 97SEPCh. 9.13 - Prob. 98SEPCh. 9.13 - Prob. 99SEPCh. 9.13 - Prob. 100SEPCh. 9.13 - Prob. 101SEPCh. 9.13 - Prob. 102SEPCh. 9.13 - Prob. 103SEPCh. 9.13 - Both 4140 and 4340 steel alloys may be tempered to...Ch. 9.13 - Prob. 105SEPCh. 9.13 - Aircraft fuselage is made of aluminum alloys 2024...Ch. 9.13 - Prob. 107SEPCh. 9.13 - Prob. 108SEPCh. 9.13 - Prob. 109SEPCh. 9.13 - (a) What makes austenitic stainless steels that...Ch. 9.13 - Prob. 111SEPCh. 9.13 - Prob. 112SEPCh. 9.13 - Prob. 113SEPCh. 9.13 - (a) Give examples of components or products that...Ch. 9.13 - Prob. 115SEPCh. 9.13 - Prob. 116SEPCh. 9.13 - Prob. 117SEP
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How to make metal stronger by heat treating, alloying and strain hardening; Author: Billy Wu;https://www.youtube.com/watch?v=7lM-Y4XndsE;License: Standard Youtube License