(a) What is the approximate ductility (%EL) of a brass that has a yield strength of 350 MPa (50760 psi)? i %Elongation
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- 7.32 (a) What is the approximate ductility (%EL) e of a brass that has a yield strength of 345 MPa (50,000 psi)? (b) What is the approximate Brinell hardness of a 1040 steel having a yield strength of 620 MPa (90,000 psi)?Question 1 You are working on a design team at a small orthopaedic firm. You have been asked to select a cobalt- chrome-molybdenum (CoCr) material that will not experience plastic deformation under a specific mechanical test, as follows... A tensile stress is applied along the long axis of a solid cylindrical rod that has a diameter of 10 mm. An applied load of some magnitude F produces a 7x10³ mm change in diameter (see figure below, original shape is blue, elongated shape is unshaded). Q1F: How would the "new alloy" material (with different properties as shown below) behave, assuming it has the same initial diameter (10mm) and applied load (F) in the tensile test? That is, would it experience plastic deformation (yield) under the conditions of this problem?O The following engineering stress-strain data were obtained for a 0.2% C plain-carbon steel. (i) Plot the engineering stress-strain curve. (ii) Determine the ultimate tensile strength of the alloy. (iii) Determine the percent elongation at fracture. Engineering Engineering Engineering Engineering Stress Strain Stress Strain (ksi) (in./in.) (ksi) (in./in.) 76 0.08 30 0.001 75 0.10 55 0.002 73 0.12 60 0.005 69 0.14 68 0.010 65 0.16 72 0.020 56 0.18 74 0.040 51 0.19 75 0.060 (Fracture)
- A shear pin made from a 4340 steel (0.4% C) fails by ductile fracture. It was supposed to be initially normalised, austenitised, quenched and tempered to 100% martensite to give a hardness of 5.5 GPa. The hardness was measured to be 4.5 GPa. Which of the following summaries most accurately accounts for what may have gone wrong? O Insufficiently heating the steel would result in partial austenitisation, leading to only partial martensite after quenching and a reduction in final hardness. The temper could still occur at the correct conditions and still lead to an insufficient strength and encouraging ductile failure. O Performing a full austenitisation but then cooling slower than the critical cooling rate for the alloy would allow some ferrite/pearlite to form after the martensite reaction has finished. This would be softer than the tempered martensite and so reduce the final hardness. O Assuming a full austenitisation and then cooling faster than the critical cooling rate, the hardness…The lower yield point for a certain plain carbon steelbar is found to be 135 MPa, while a second bar of the samecomposition yields at 260 MPa. Metallographic analysisshows that the average grain diameter is 50μm in the firstbar and 8μm in the second bar.a. Predict the grain diameter needed to cause a loweryield point of 205 MPa.b. If the steel could be fabricated to form a stablegrain structure of 500 nm grains, what strengthwould be predicted?c. Why might you expect the upper yield point to bemore alike in the first two bars than the lower yieldpoint?3. An uncold-worked brass specimen of average grain size 0.01 mm has a yield strength of 150 MPa (21,750 psi). Estimate the yield strength of this alloy after it has been heated to 500°C for 1000 s, if it is known that the value of σo is 25 MPa. (Note that the axis has logarithmic scale). Grain diameter (mm) (Logarithmic scale) 1.0 0.1 0.01 1 10 850°C 800°C 700°C 102 Time (min) (Logarithmic scale) 600°C 500°C 103 104
- Question 1 You are working on a design team at a small orthopaedic firm. You have been asked to select a cobalt- chrome-molybdenum (CoCr) material that will not experience plastic deformation under a specific mechanical test, as follows... A tensile stress is applied along the long axis of a solid cylindrical rod that has a diameter of 10 mm. An applied load of some magnitude F produces a 7x10-³ mm change in diameter (see figure below, original shape is blue, elongated shape is unshaded). Q1A-B: Calculate the transverse strain in the x-direction (Ex) associated with the reduction in diameter. Calculate the axial strain in the z-direction (₂) associated with the length increase.An application requires ultimate tensile strength and yield strength ofa steel at 110 ksi and 91 ksi, respectively. Answer the following 4 questions: Can SAE 1040 steel be selected for this application? If “no” is the answer in Part I, the following Part II, III, and IV can beignored. If “yes” is the answer in Part I, which condition of SAE 1040 shouldbe selected? Why is that steel with the condition in part II selected? Is the selected steel brittle or ductile? and Why?A low-nickel steel in the heat-treated condition had an 'engineering' tensile strength of 708 N/mm2. The reduction in area of cross-section at the fracture was 44%. What was the true tensile strength of the steel?
- Q3 contd. (d) The yield strength values of pure aluminium (Al) and pure copper (Cu) are 25 MPa and 20 MPa, respectively; whereas the yield strength values of cold rolled Al-Mn-Mg alloy and cast 60-40 Brass (60% Cu, 40% Zn) are 200 MPa and 105 MPa, respectively. With aid of schematics, explain the main mechanisms account for the increases in the strengths. (e) A cylindrical tie rod with a diameter of 18.4 mm is subjected to cyclic loading. The stress range is +/- 200 kN. Figure Q3.3 shows the S-N curve of the material of which the rod is made, how many cycles will this rod survive? Stress amplitude O₂ (MPa) 1500 1400 1300 1200 1100 1000 900 800 700 600 500 400 10² 10³ 104 4340 low-alloy steel Stress ratio = -1 Fig. Q3.3 105 106 Number of cycles to failure, Nf 107 108HEY MAY YOU PLEASE HELP ME WITH THE FOLLOWING QUESTIONS Which one of the alloys given below will have the highest hardness. Give a brief explanation and illustrate your answer with an applicable calculation. 98% Pb + 2% Mg (RPb = 0.175nm, RMg = 0.160nm) 98% Pb + 2% Sn (RPb = 0.175nm, RSn = 0.151nm)Problems 1. A Rockwell hardness measurement is made on a ductile iron (80-55-06 as cast) and the obtained Rockwell hardness R scale is 13 HRC. Predict the tensile and yield strengths of this material. 2. A Brinell hardness measurement is made on a ductile iron (120-90-02, Oil-quenched) using a 10-mm-diameter sphere of tungsten carbide. A load of 3,000 kg produces a 3.52-mm- diameter impression in the iron surface. a. Calculate the BHN of this alloy. (The correct units for the Brinell equation are kilograms for load and millimeters for diameters.) b. Predict the tensile and yield strengths 3. Suppose that a ductile iron (100-70-03, air-quenched) has a tensile strength of 800 MPa. What diameter impression would you expect the 3,000-kg load to produce with the 10-mm- diameter ball? Search LO W SE