Foundations of Materials Science and Engineering
6th Edition
ISBN: 9781259696558
Author: SMITH
Publisher: MCG
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Textbook Question
Chapter 9.13, Problem 71AAP
A 1.10 % C hypereutectoid plain-carbon steel is slowly cooled from 900°C to a temperature just slightly below 727°C.
- a. Calculate the weight percent proeutectoid cementite present in the steel.
- b. Calculate the weight percent eutectoid cementite and the weight percent eutectoid ferrite present in the steel.
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Problem 1
A 0.65 percent C hypoeutectoid plain-carbon steel is slowly cooled from about 950°C to a temperature
just slightly above 723°C. Calculate the weight percent austenite and weight percent proeutectoid
ferrite in this steel.
a +y
a
a
0.02% C
0.65% C
0.80% C
A 0.25% C hypoeutectoid plain-carbon steel is slowly cooled from 950°C to a temperature just slightly below 723°C.(a) Calculate the weight percent proeutectoid ferrite in the steel.(b) Calculate the weight percent eutectoid ferrite and weight percent eutectoid cementite in the steel.
A steel contains 18% pearlite and 82%primary ferrite at room temperature. Esti-mate the carbon content of the steel. Is thesteel hypoeutectoid or hypereutectoid?
Chapter 9 Solutions
Foundations of Materials Science and Engineering
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