Foundations of Materials Science and Engineering
6th Edition
ISBN: 9781259696558
Author: SMITH
Publisher: MCG
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Chapter 9.13, Problem 117SEP
(a)
To determine
Explain why the threads of a cylinder do not fit with the threads of the nut after the process of heat-treatment.
(b)
To determine
How to avoid the problem where the threads of a cylinder do not fit with the threads of the nut after the process of heat-treatment.
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A cylindrical brass rod with a minimum tensile strength of 450 MPa, a ductility of at least 13% EL (elongation), and a final diameter of 12.7mm is required. You have in your inventory some 19.0mm diameter brass stock that has been cold worked to 35%. Assuming that the cross section of the rod is still circular after being cold worked, and that brass experiences cracking at 65% CW, describe the necessary working steps in order to achieve the final product. Take the expression for % cold work to be = (Ao - Af)/ Ao x 100%, where Ao and Af are the original and final circular cross-sectional areas of the rod.
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part made from AISI 1212 steel undergoes a 20 percent cold-work operation.
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(b) Determine the ratios of ultimate strength to yield strength before and after the cold work operation.
What does the result indicate about the change of ductility of the part?
Chapter 9 Solutions
Foundations of Materials Science and Engineering
Ch. 9.13 - (a) How is raw pig iron extracted from iron oxide...Ch. 9.13 - (a) Why is the FeFe3C phase diagram a metastable...Ch. 9.13 - (a) What is the structure of pearlite? (b) Draw a...Ch. 9.13 - Distinguish between the following three types of...Ch. 9.13 - Prob. 5KCPCh. 9.13 - (a) Define an FeC martensite. (b) Describe the...Ch. 9.13 - (a) What is an isothermal transformation in the...Ch. 9.13 - How does the isothermal transformation diagram for...Ch. 9.13 - Draw a continuous-cooling transformation diagram...Ch. 9.13 - (a) Describe the full-annealing heat treatment for...
Ch. 9.13 - Describe the process-annealing heat treatment for...Ch. 9.13 - What is the normalizing heat treatment for steel...Ch. 9.13 - Describe the tempering process for a plain-carbon...Ch. 9.13 - (a) Describe the martempering (marquenching)...Ch. 9.13 - (a) Describe the austempering process for a...Ch. 9.13 - (a) Explain the numbering system used by the AISI...Ch. 9.13 - (a) What arc some of the limitations of...Ch. 9.13 - (a) What compounds docs aluminum form in steels?...Ch. 9.13 - Prob. 19KCPCh. 9.13 - (a) Define the hardenability of a steel. (b)...Ch. 9.13 - Prob. 21KCPCh. 9.13 - Prob. 22KCPCh. 9.13 - Prob. 23KCPCh. 9.13 - What is the difference between a coherent...Ch. 9.13 - Prob. 25KCPCh. 9.13 - Prob. 26KCPCh. 9.13 - Prob. 27KCPCh. 9.13 - (a) Describe the three principal casting processes...Ch. 9.13 - Prob. 29KCPCh. 9.13 - Prob. 30KCPCh. 9.13 - Prob. 31KCPCh. 9.13 - Prob. 32KCPCh. 9.13 - Prob. 33KCPCh. 9.13 - Prob. 34KCPCh. 9.13 - Prob. 35KCPCh. 9.13 - (a) What are the cast irons? (b) What is their...Ch. 9.13 - Prob. 37KCPCh. 9.13 - Prob. 38KCPCh. 9.13 - Prob. 39KCPCh. 9.13 - Prob. 40KCPCh. 9.13 - Prob. 41KCPCh. 9.13 - Prob. 42KCPCh. 9.13 - Prob. 43KCPCh. 9.13 - Prob. 44KCPCh. 9.13 - Prob. 45KCPCh. 9.13 - (a) Why arc titanium and its alloys of special...Ch. 9.13 - Prob. 47KCPCh. 9.13 - Prob. 48KCPCh. 9.13 - Prob. 49KCPCh. 9.13 - Prob. 50KCPCh. 9.13 - Prob. 51KCPCh. 9.13 - Prob. 52KCPCh. 9.13 - Describe the structural changes that take place...Ch. 9.13 - Describe the structural changes that take place...Ch. 9.13 - If a thin sample of a eutectoid plain-carbon steel...Ch. 9.13 - If a thin sample of a eutectoid plain-carbon steel...Ch. 9.13 - (a) What types of microstructures arc produced by...Ch. 9.13 - A 0.65 % C hypoeutectoid plain-carbon steel is...Ch. 9.13 - A 0.25% C hypoeutectoid plain-carbon steel is...Ch. 9.13 - A plain-carbon steel contains 93 wt % ferrite7 wt%...Ch. 9.13 - A plain-carbon steel contains 45 wt% proeutectoid...Ch. 9.13 - A plain-carbon steel contains 5.9 wt%...Ch. 9.13 - A 0.90% C hypereutectoid plain-carbon steel is...Ch. 9.13 - A 1.10% C hypereutectoid plain-carbon steel is...Ch. 9.13 - If a hypereutectoid plain-carbon steel contains...Ch. 9.13 - A hypereutectoid plain-carbon steel contains 10.7...Ch. 9.13 - A plain-carbon steel contains 20.0 wt%...Ch. 9.13 - A 0.55% C hypoeutectoid plain-carbon steel is...Ch. 9.13 - A hypoeutectoid steel contains 44.0 wt% eutectoid...Ch. 9.13 - A hypoeutectoid steel contains 24.0 wt% eutectoid...Ch. 9.13 - A 1.10 % C hypereutectoid plain-carbon steel is...Ch. 9.13 - Draw timetemperature cooling paths for a 1080...Ch. 9.13 - Draw timetemperature cooling paths for a 1080...Ch. 9.13 - Thin pieces of 0.3-mm-thick hot-rolled strips of...Ch. 9.13 - Prob. 75AAPCh. 9.13 - Prob. 76AAPCh. 9.13 - Prob. 77AAPCh. 9.13 - Prob. 78AAPCh. 9.13 - Prob. 79AAPCh. 9.13 - Prob. 80AAPCh. 9.13 - Prob. 81AAPCh. 9.13 - Prob. 82AAPCh. 9.13 - An austenitized 40-mm-diameter 4340 steel bar is...Ch. 9.13 - Prob. 84AAPCh. 9.13 - Prob. 85AAPCh. 9.13 - Prob. 86AAPCh. 9.13 - Prob. 87AAPCh. 9.13 - Prob. 88AAPCh. 9.13 - Prob. 89AAPCh. 9.13 - Prob. 90AAPCh. 9.13 - Prob. 91AAPCh. 9.13 - Prob. 92AAPCh. 9.13 - (a) For a plain-carbon steel with 1 wt % carbon...Ch. 9.13 - Prob. 94SEPCh. 9.13 - Prob. 95SEPCh. 9.13 - Prob. 96SEPCh. 9.13 - Prob. 97SEPCh. 9.13 - Prob. 98SEPCh. 9.13 - Prob. 99SEPCh. 9.13 - Prob. 100SEPCh. 9.13 - Prob. 101SEPCh. 9.13 - Prob. 102SEPCh. 9.13 - Prob. 103SEPCh. 9.13 - Both 4140 and 4340 steel alloys may be tempered to...Ch. 9.13 - Prob. 105SEPCh. 9.13 - Aircraft fuselage is made of aluminum alloys 2024...Ch. 9.13 - Prob. 107SEPCh. 9.13 - Prob. 108SEPCh. 9.13 - Prob. 109SEPCh. 9.13 - (a) What makes austenitic stainless steels that...Ch. 9.13 - Prob. 111SEPCh. 9.13 - Prob. 112SEPCh. 9.13 - Prob. 113SEPCh. 9.13 - (a) Give examples of components or products that...Ch. 9.13 - Prob. 115SEPCh. 9.13 - Prob. 116SEPCh. 9.13 - Prob. 117SEP
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.Similar questions
- Example Problem-2 A cylindrical rod of non cold-worked brass having an initial diameter of 6.4 mm (0.25 in.) is to be cold worked by drawing such that the cross-sectional area is reduced. It is required to have a cold-worked yield strength of at least 345 Mpa (50,000 psi) and a ductility in excess of 20%EL; in addition, a final diameter of 5.1 mm (0.20 in.) is necessary. Describe the solution.arrow_forwardAn electric car manufacturer is looking to utilize some stock AISI 8740, hot rolled steel bars that are around 2 inches in diameter for their conveyor system that is being set up to start producing their own batteries. The data sheet shows the the bars to have 132,000 psi tensile strength, 87,500 psi yield strength, and 16.7% elongation. A hardness of 262 Bhn allows it to be finish machined after heat treatment. They keep their workspace at 70°F. What is the working endurance strength, Se? 39,750 psi 28,562 psi 42,500 psi 33,400 psiarrow_forwardWith respect to the S-N diagram shown below, answer the following questions:(a) for Gray cast iron, what is the projected number of cycles to failure for an induced stress of 20,000 psi?(b) What is the endurance limit and associated stress for a 0.47% heat treated carbon steel? (c) What is the endurance limit for the Aluminum-copper alloy?(d) What is the endurance strength for heat treated Alloy Steel at 400,000 cycles?arrow_forward
- A mild steel material is subjected to a Brinell hardness test with an applied force of 7459 N using a hardened steel ball indentor of 11 mm and it is found that the Brinell Hardness Number as 954. Determine the surface area of indentation and indentation diameter. (NOTE: Please Solve the problem in a paper and upload in the separate submission link provided and also fill the answers without the unit in the box below) i) Surface Area of Indentation (in mm?) -- ( ii) Indentation Diameter (in mm)arrow_forwardA low-carbon steel alloy was loaded in tension until just after yielding took place. A few Luders bands were visible on the surface. The bar can either be reloaded (a) immediately, (b) after a brief and moderate temperature aging treatment, or (c) after several weeks without any exposure to elevated temperature. In each of the three cases, how is the yield strength of the reloaded bar likely to compare to that of the original test?arrow_forward1. Please draw a typical tensile test curve for low carbon steels and mark the four stages and list their names (use critical points on the curve to help you identify the start and end points of the four stages). 2. Show the yield, ultimate tensile strength and fracture points, as well as yield and ultimate tensile strength on the curve. 3. Please draw the load and unload curve for a stress level causing the low carbon steels to experience elastic deformation only. 4. Please draw the load and unload curve for a stress level causing the low carbon steel to experience permerment deformation, and identify both elastic and plastic strain on the drawing after unloading.arrow_forward
- A part made from hot-rolled AISI 1212 steel undergoes a certain amount of cold-work operation. If the ultimate strength of the material after cold work operation was 80 kpsi. (a) Determine the percentage of cold work (b) Obtain the yield strength after the cold work (c) Determine the hardness of the material before and after the cold work operationarrow_forwardAn application requires ultimate tensile strength and yield strength ofa steel at 110 ksi and 91 ksi, respectively. Answer the following 4 questions: Can SAE 1040 steel be selected for this application? If “no” is the answer in Part I, the following Part II, III, and IV can beignored. If “yes” is the answer in Part I, which condition of SAE 1040 shouldbe selected? Why is that steel with the condition in part II selected? Is the selected steel brittle or ductile? and Why?arrow_forwardA shear pin made from a 4340 steel (0.4% C) fails by ductile fracture. It was supposed to be initially normalised, austenitised, quenched and tempered to 100% martensite to give a hardness of 5.5 GPa. The hardness was measured to be 4.5 GPa. Which of the following summaries most accurately accounts for what may have gone wrong? O Insufficiently heating the steel would result in partial austenitisation, leading to only partial martensite after quenching and a reduction in final hardness. The temper could still occur at the correct conditions and still lead to an insufficient strength and encouraging ductile failure. O Performing a full austenitisation but then cooling slower than the critical cooling rate for the alloy would allow some ferrite/pearlite to form after the martensite reaction has finished. This would be softer than the tempered martensite and so reduce the final hardness. O Assuming a full austenitisation and then cooling faster than the critical cooling rate, the hardness…arrow_forward
- Which material (i.e., C1045-CF, Cast Iron, AL7075-T6) was more ductile? Explain the effect of carbon content and finishing process on ductility.arrow_forwardThe lower yield point for a certain plain carbon steelbar is found to be 135 MPa, while a second bar of the samecomposition yields at 260 MPa. Metallographic analysisshows that the average grain diameter is 50μm in the firstbar and 8μm in the second bar.a. Predict the grain diameter needed to cause a loweryield point of 205 MPa.b. If the steel could be fabricated to form a stablegrain structure of 500 nm grains, what strengthwould be predicted?c. Why might you expect the upper yield point to bemore alike in the first two bars than the lower yieldpoint?arrow_forwardHow is Ductility specified?arrow_forward
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