Each carbocation in below figure should be labelled as 3 o allylic carbocation. Concept introduction: Organic compounds are covalent in nature that undergoes a reaction by heterolytic cleavage or homolytic cleavage. In heterolytic cleavage, shared pair of electrons is taken away by one of the atoms which result in charged species. In homolytic cleavage, shared pair of electrons are equally distributed between two atom that results in free radicals. Carbocation is a general term employed for a postively charged carbon irrespective of valency of carbon. In carbocation, carbon is bonded to 3 atoms or groups and has only sextet of electrons so it behaves as an electron-deficient species. It is s p 2 hybridized with a vacant p orbital and has a planar geometry.

Question

Use the information in the pK table below to determine which side of the equilibrium is favored for each of the reactions in the second table. acid pKa acid pKa CHA 50 CHÍNH, 45 CH2=CH2 36 CH-C=CH 25 15.9 CHÍNH 10.6 OH OH 10.0 NH 5.3 -2 -2.4 CH -OH OH, OH i OH -6.1 -7 CH,SH₂ CH2=CH2 + C NH + CHÍNH, ° + CH-C=CH Equilibrium Equation CH-S-OH CH2=CH + + CHÍNH, OH + CH-C=C OH, + CH SH он + CH SH₂ 0 о Left Favored Equal Right Favored 0 ° °

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Question

Chapter 8, Problem 8CTQ

Interpretation Introduction

Interpretation: Each carbocation in below figure should be labelled as 3o allylic carbocation.

Concept introduction: Organic compounds are covalent in nature that undergoes a reaction by heterolytic cleavage or homolytic cleavage.

In heterolytic cleavage, shared pair of electrons is taken away by one of the atoms which result in charged species. In homolytic cleavage, shared pair of electrons are equally distributed between two atom that results in free radicals.

Carbocation is a general term employed for a postively charged carbon irrespective of valency of carbon. In carbocation, carbon is bonded to 3 atoms or groups and has only sextet of electrons so it behaves as an electron-deficient species. It is sp2 hybridized with a vacant p orbital and has a planar geometry.

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Use the information in the pK table below to determine which side of the equilibrium is favored for each of the reactions in the second table. acid pKa acid pKa CHA 50 CHÍNH, 45 CH2=CH2 36 CH-C=CH 25 15.9 CHÍNH 10.6 OH OH 10.0 NH 5.3 -2 -2.4 CH -OH OH, OH i OH -6.1 -7 CH,SH₂ CH2=CH2 + C NH + CHÍNH, ° + CH-C=CH Equilibrium Equation CH-S-OH CH2=CH + + CHÍNH, OH + CH-C=C OH, + CH SH он + CH SH₂ 0 о Left Favored Equal Right Favored 0 ° °

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