Chapter 24, Problem 101A

To determine

A physics problem for which $v=\frac{60\text{ N}}{\left(1.6\times {10}^{-19}\text{}\text{ C}\right)\left(2.3\text{ T}\right)}$ is the solution.

Explanation of Solution

Introduction:

When a moving charge is placed in an external magnetic field, it experiences force. Fleming’s left-hand rule helps to know the direction of the force experienced by the charge when current flows through it in a magnetic field.

The force experience by a charge moving with a velocity in a magnetic field is determined by the formula $F_B=qvB$ .

Determine the velocity of a proton in a magnetic field of strength $2.3\text{ T}$ experiencing a force of $60\text{ N}$ .

The solution would be:

  $v=\frac{60\text{ N}}{\left(1.6\times {10}^{-19}\text{}\text{ C}\right)\left(2.3\text{ T}\right)}$

Conclusion:

To determine the velocity of a proton in a magnetic field of strength $2.3\text{ T}$ experiencing a force of $60\text{ N}$ .