Chapter 24, Problem 105A

To determine

Work done to move a charge through a given potential difference.

Answer to Problem 105A

The work done to move the charge through the given potential difference is $16\text{ J}$

Explanation of Solution

Given:

A $6.4\times {10}^{-3}\text{ C}$ charge is moved through a potential difference of 2500 V

Formula used:

The work done in moving a charge through a potential difference is the product of the potential difference and the magnitude of the charge. It can be expressed mathematically as,

  $W=q\Delta V$

Calculation:

For a given potential difference of 2500 V, the work done to move the charge of magnitude $q=6.4\times {10}^{-3}\text{ C}$ is obtained by

  $\begin{array}{c}W=6.4\times {10}^{-3}\times 2500\\ =16\text{ J}\end{array}$

Conclusion:

The work done to move the given charge through the potential difference is 16 J.