Foundations of Materials Science and Engineering
6th Edition
ISBN: 9781259696558
Author: SMITH
Publisher: MCG
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Chapter 6.13, Problem 34KCP
To determine
Factor affecting the recrystallization process.
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During the recrystallization of a cold-worked material, which of the following statement(s) is (are) true?
O There is some reduction in the number of dislocations.
O Some of the internal strain energy is relieved.
O The metal becomes more ductile, as in its precold-worked state.
O Grains with high strains are replaced with new, unstrained grains.
O There is a significant reduction in the number of dislocations, to approximately the number found in the precold-worked
state,
O The thermal conductivity is recovered to its precold-worked state.
O All of the internal strain energy is relieved.
O The electrical conductivity is recovered to its precold-worked state.
summarize the way in which fine _grain microstructure behave with regard to low temperature and room temperature strength and toughness.why not make all metals as small_grained as possible?
What is the effect of strain hardening on the material?
Chapter 6 Solutions
Foundations of Materials Science and Engineering
Ch. 6.13 - (a) How are metal alloys made by the casting...Ch. 6.13 - Why are cast metal sheet ingots hot-rolled first...Ch. 6.13 - What type of heat treatment is given to the rolled...Ch. 6.13 - Describe and illustrate the following types of...Ch. 6.13 - Describe the forging process. What is the...Ch. 6.13 - What is the difference between open-die and...Ch. 6.13 - Describe the wire-drawing process. Why is it...Ch. 6.13 - Distinguish between elastic and plastic...Ch. 6.13 - Define (a) engineering stress and strain and (b)...Ch. 6.13 - Define (a) modulus of elasticity, (b) yield...
Ch. 6.13 - (a) Define the hardness of a metal. (b) How is the...Ch. 6.13 - What types of indenters are used in (a) the...Ch. 6.13 - What are slipbands and slip lines? What causes the...Ch. 6.13 - Describe the slip mechanism that enables a metal...Ch. 6.13 - (a) Why does slip in metals usually take place on...Ch. 6.13 - Prob. 16KCPCh. 6.13 - What other types of slip planes are important...Ch. 6.13 - Define the critical resolved shear stress for a...Ch. 6.13 - Describe the deformation twinning process that...Ch. 6.13 - What is the difference between the slip and...Ch. 6.13 - Prob. 21KCPCh. 6.13 - Prob. 22KCPCh. 6.13 - What experimental evidence shows that grain...Ch. 6.13 - (a) Describe the grain shape changes that occur...Ch. 6.13 - How is the ductility of a metal normally affected...Ch. 6.13 - (a) What is solid-solution strengthening? Describe...Ch. 6.13 - What are the three main metallurgical stages that...Ch. 6.13 - Describe the microstructure of a heavily...Ch. 6.13 - Describe what occurs microscopically when a...Ch. 6.13 - When a cold-worked metal is heated into the...Ch. 6.13 - Describe what occurs microscopically when a...Ch. 6.13 - When a cold-worked metal is heated into the...Ch. 6.13 - Prob. 33KCPCh. 6.13 - Prob. 34KCPCh. 6.13 - Prob. 35KCPCh. 6.13 - Prob. 36KCPCh. 6.13 - Prob. 37KCPCh. 6.13 - Why are nanocrystalline materials stronger? Answer...Ch. 6.13 - A 70% Cu30% Zn brass sheet is 0.0955 cm thick and...Ch. 6.13 - A sheet of aluminum alloy is cold-rolled 30% to a...Ch. 6.13 - Calculate the percent cold reduction when an...Ch. 6.13 - Prob. 42AAPCh. 6.13 - What is the relationship between engineering...Ch. 6.13 - A tensile specimen of cartridge brass sheet has a...Ch. 6.13 - A 0.505-in.-diameter rod of an aluminum alloy is...Ch. 6.13 - In Figure 6.23, estimate the toughness of SAE 1340...Ch. 6.13 - The following engineering stress-strain data were...Ch. 6.13 - Prob. 49AAPCh. 6.13 - A 0.505-in.-diameter aluminum alloy test bar is...Ch. 6.13 - A 20-cm-long rod with a diameter of 0.250 cm is...Ch. 6.13 - Prob. 52AAPCh. 6.13 - Prob. 53AAPCh. 6.13 - Prob. 54AAPCh. 6.13 - Prob. 55AAPCh. 6.13 - Prob. 56AAPCh. 6.13 - A specimen of commercially pure titanium has a...Ch. 6.13 - Prob. 58AAPCh. 6.13 - Prob. 59AAPCh. 6.13 - Prob. 60AAPCh. 6.13 - Prob. 61AAPCh. 6.13 - Prob. 62AAPCh. 6.13 - Prob. 63AAPCh. 6.13 - Prob. 64AAPCh. 6.13 - Prob. 65SEPCh. 6.13 - Prob. 66SEPCh. 6.13 - A 20-mm-diameter, 350-mm-long rod made of an...Ch. 6.13 - Prob. 68SEPCh. 6.13 - Prob. 69SEPCh. 6.13 - Consider casting a cube and a sphere on the same...Ch. 6.13 - When manufacturing complex shapes using cold...Ch. 6.13 - Prob. 74SEPCh. 6.13 - Draw a generic engineering stress-strain diagram...Ch. 6.13 - (a) Draw a generic engineering stress-strain...Ch. 6.13 - Prob. 77SEPCh. 6.13 - Prob. 78SEPCh. 6.13 - Prob. 79SEPCh. 6.13 - The material for a rod of cross-sectional area...Ch. 6.13 - What do E, G, v, Ur, and toughness tell you about...Ch. 6.13 - A cylindrical component is loaded in tension until...Ch. 6.13 - Referring to Figures 6.20 and 6.21 (read the...Ch. 6.13 - (a) Show, using the definition of the Poissons...Ch. 6.13 - A one-inch cube of tempered stainless steel (alloy...Ch. 6.13 - Prob. 87SEPCh. 6.13 - Prob. 88SEPCh. 6.13 - Prob. 89SEPCh. 6.13 - Prob. 90SEPCh. 6.13 - Prob. 91SEPCh. 6.13 - Prob. 92SEPCh. 6.13 - Prob. 93SEPCh. 6.13 - Prob. 94SEPCh. 6.13 - Starting with a 2-in.-diameter rod of brass, we...Ch. 6.13 - Prob. 96SEPCh. 6.13 - Prob. 97SEPCh. 6.13 - Prob. 98SEPCh. 6.13 - The cupro-nickel substitutional solid solution...Ch. 6.13 - Prob. 100SEP
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.Similar questions
- Which method do we use to monitor dislocation movements in tensile testing? How monitoring is done in this method, explain the working mechanism of the system in detail.arrow_forwardCold working of metals will give better final properties than hot working. Select one: True Falsearrow_forwardQuestion 2 a) Briefly explain why HCP metals are typically more brittle than FCC and BCC metals. b) Two previously undeformed specimens of the same metal are to be plastically deformed by reducing their cross-sectional areas (cold work). One has a circular cross section, and the other is rectangular; during deformation the circular cross section is to remain circular, and the rectangular is to remain as such. Their original and deformed dimensions are as follows: Circular (diameter, mm) Rectangular (mm) Original dim ensions 15.2 125 x 175 Deformed dimensions 11.4 75 x 200 Which of these specimens will be the hardest after plastic deformation, and why?arrow_forward
- How does point defect affect properties of materials? Please answer within 10 mins. 5-10 sentences. Thank youarrow_forwardMetal y (mJ/m)n Slip Character (a) Discuss why Planar slip is associated with a small stacking fault energy, as shown in the table below. (b) Sketch the shape of a single-crystal shear stress-strain curve for Al and Stainless Steel, (1label) stage I, II and III portions of deformation, which one end stage II and begin stage III sooner?. S.Steel <10 -0.45 Planar Cu -90 -0.3 Planar/ wayy Al -250 -0.15 wayyarrow_forwardDoes the failure of materials occur due to creep and fatigue?arrow_forward
- 1. Explain in 1-3 bullets how as a practicing engineer you determine the yield strength of a metal from a tensile stress-strain curve. 2. Explain what is happening at the yield strength for a metal from a physical standpoint in 1-3 bullets. (e.g. what are the atoms doing?)arrow_forwardWhat is the difference between the microstructure and the macrostructure of a material?arrow_forwardeffect of the cooling rate on the microstructure and hardness of a materialarrow_forward
- summarize the way in which fine_grain microstructures behave with regard to low temperature and room temperature strength and toughnesd.why not make all metals as small_grained as possible?arrow_forwarda) Briefly explain why HCP metals are typically more brittle than FCC and BCC metals. b) Two previously undeformed specimens of the same metal are to be plastically deformed by reducing their cross-sectional areas (cold work). One has a circular cross section, and the other is rectangular; during deformation the circular cross section is to remain circular, and the rectangular is to remain as such. Their original and deformed dimensions are as follows: Circular (diameter, mm) Rectangular (mm) 125 x 175 Original dimensions 15.2 Deformed dimensions 11.4 75 x 200 Which of these specimens will be the hardest after plastic deformation, and why?arrow_forwardUnder room temperature, why grain boundaries are beneficial for improving materials strength? How grain boundaries affect material’s high temperature creep property?arrow_forward
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