Foundations of Materials Science and Engineering
6th Edition
ISBN: 9781259696558
Author: SMITH
Publisher: MCG
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Chapter 6.13, Problem 54AAP
To determine
To determine the difference between the highest yield strength of a single crystal of copper and polycrystalline form of copper.
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Chapter 6 Solutions
Foundations of Materials Science and Engineering
Ch. 6.13 - (a) How are metal alloys made by the casting...Ch. 6.13 - Why are cast metal sheet ingots hot-rolled first...Ch. 6.13 - What type of heat treatment is given to the rolled...Ch. 6.13 - Describe and illustrate the following types of...Ch. 6.13 - Describe the forging process. What is the...Ch. 6.13 - What is the difference between open-die and...Ch. 6.13 - Describe the wire-drawing process. Why is it...Ch. 6.13 - Distinguish between elastic and plastic...Ch. 6.13 - Define (a) engineering stress and strain and (b)...Ch. 6.13 - Define (a) modulus of elasticity, (b) yield...
Ch. 6.13 - (a) Define the hardness of a metal. (b) How is the...Ch. 6.13 - What types of indenters are used in (a) the...Ch. 6.13 - What are slipbands and slip lines? What causes the...Ch. 6.13 - Describe the slip mechanism that enables a metal...Ch. 6.13 - (a) Why does slip in metals usually take place on...Ch. 6.13 - Prob. 16KCPCh. 6.13 - What other types of slip planes are important...Ch. 6.13 - Define the critical resolved shear stress for a...Ch. 6.13 - Describe the deformation twinning process that...Ch. 6.13 - What is the difference between the slip and...Ch. 6.13 - Prob. 21KCPCh. 6.13 - Prob. 22KCPCh. 6.13 - What experimental evidence shows that grain...Ch. 6.13 - (a) Describe the grain shape changes that occur...Ch. 6.13 - How is the ductility of a metal normally affected...Ch. 6.13 - (a) What is solid-solution strengthening? Describe...Ch. 6.13 - What are the three main metallurgical stages that...Ch. 6.13 - Describe the microstructure of a heavily...Ch. 6.13 - Describe what occurs microscopically when a...Ch. 6.13 - When a cold-worked metal is heated into the...Ch. 6.13 - Describe what occurs microscopically when a...Ch. 6.13 - When a cold-worked metal is heated into the...Ch. 6.13 - Prob. 33KCPCh. 6.13 - Prob. 34KCPCh. 6.13 - Prob. 35KCPCh. 6.13 - Prob. 36KCPCh. 6.13 - Prob. 37KCPCh. 6.13 - Why are nanocrystalline materials stronger? Answer...Ch. 6.13 - A 70% Cu30% Zn brass sheet is 0.0955 cm thick and...Ch. 6.13 - A sheet of aluminum alloy is cold-rolled 30% to a...Ch. 6.13 - Calculate the percent cold reduction when an...Ch. 6.13 - Prob. 42AAPCh. 6.13 - What is the relationship between engineering...Ch. 6.13 - A tensile specimen of cartridge brass sheet has a...Ch. 6.13 - A 0.505-in.-diameter rod of an aluminum alloy is...Ch. 6.13 - In Figure 6.23, estimate the toughness of SAE 1340...Ch. 6.13 - The following engineering stress-strain data were...Ch. 6.13 - Prob. 49AAPCh. 6.13 - A 0.505-in.-diameter aluminum alloy test bar is...Ch. 6.13 - A 20-cm-long rod with a diameter of 0.250 cm is...Ch. 6.13 - Prob. 52AAPCh. 6.13 - Prob. 53AAPCh. 6.13 - Prob. 54AAPCh. 6.13 - Prob. 55AAPCh. 6.13 - Prob. 56AAPCh. 6.13 - A specimen of commercially pure titanium has a...Ch. 6.13 - Prob. 58AAPCh. 6.13 - Prob. 59AAPCh. 6.13 - Prob. 60AAPCh. 6.13 - Prob. 61AAPCh. 6.13 - Prob. 62AAPCh. 6.13 - Prob. 63AAPCh. 6.13 - Prob. 64AAPCh. 6.13 - Prob. 65SEPCh. 6.13 - Prob. 66SEPCh. 6.13 - A 20-mm-diameter, 350-mm-long rod made of an...Ch. 6.13 - Prob. 68SEPCh. 6.13 - Prob. 69SEPCh. 6.13 - Consider casting a cube and a sphere on the same...Ch. 6.13 - When manufacturing complex shapes using cold...Ch. 6.13 - Prob. 74SEPCh. 6.13 - Draw a generic engineering stress-strain diagram...Ch. 6.13 - (a) Draw a generic engineering stress-strain...Ch. 6.13 - Prob. 77SEPCh. 6.13 - Prob. 78SEPCh. 6.13 - Prob. 79SEPCh. 6.13 - The material for a rod of cross-sectional area...Ch. 6.13 - What do E, G, v, Ur, and toughness tell you about...Ch. 6.13 - A cylindrical component is loaded in tension until...Ch. 6.13 - Referring to Figures 6.20 and 6.21 (read the...Ch. 6.13 - (a) Show, using the definition of the Poissons...Ch. 6.13 - A one-inch cube of tempered stainless steel (alloy...Ch. 6.13 - Prob. 87SEPCh. 6.13 - Prob. 88SEPCh. 6.13 - Prob. 89SEPCh. 6.13 - Prob. 90SEPCh. 6.13 - Prob. 91SEPCh. 6.13 - Prob. 92SEPCh. 6.13 - Prob. 93SEPCh. 6.13 - Prob. 94SEPCh. 6.13 - Starting with a 2-in.-diameter rod of brass, we...Ch. 6.13 - Prob. 96SEPCh. 6.13 - Prob. 97SEPCh. 6.13 - Prob. 98SEPCh. 6.13 - The cupro-nickel substitutional solid solution...Ch. 6.13 - Prob. 100SEP
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.Similar questions
- Question The yield strength for an aluminum alloy that has an average grain diameter of 10 um is 400 MPa. As the grain diameter is increased to 80 um, the yield strength decreases to 260 MPa. When the grain diameter is 2 um, its yield strength is close to 760 MPa 668 MPa 566 MPa 419 MPaarrow_forwardConsider a single crystal of some hypothetical metal that has the BCC crystal structure and is oriented such that a tensile stress is applied along a [2 2 1] direction. If slip occurs on a (2 1 1) plane and in a [-1 1 1] direction, compute the stress at which the crystal yields if its critical resolved shear stress is 2.4 MPa.arrow_forwardWhich can cross-slip––an edge dislocation, a screw dislocation, or a mixed dislocation? Why?arrow_forward
- Help me pleasearrow_forwardAfter a dislocation has passed through a crystal, thereby causing plastic deformation, what does the inside of the crystal look like? Contrast this with the appearance of the interior of a crystal that has deformed by twinning.arrow_forwardIn order to find out the effects of the grain sizes on the mechanical strength of a metal, three different grain sizes of 10 µm, 500 nm and 10 nm were produced. What will be the yield stresses of these same metals at different average grain sizes? The yield strength for a grain or reference point is 78 MPa, while the material proportional constant is 29.2 MPa-mm1/2.arrow_forward
- Calculate the dislocation spacing of a low-angle tilt boundary in aluminumfor θ = 0.5◦. Take G = 26.1 GPa, v = 0.345, and rAl = 0.143 nm.arrow_forward4. Calculate the theoretical yield strength of aluminum. The Young's modulus of aluminum is 70 GPa, and Poisson's ratio is 0.3. You may assume a simple cubic lattice for aluminum crystals. Compare your result with the measured yield strength of pure aluminum (~40 MPa), and explain the main cause of the difference.arrow_forwardExplain the differences in the grain structure between a metal which has been cold worked and another same cold worked piece but has been fully re-crystallised. Why are small angle grain boundaries not as effective in interfering with the motion of dislocation as high angle grain boundaries?arrow_forward
- (b) The yield stress for a metal changes from 450 Nmm-2to 610 Nmm-2 when the average grain diameter decrease from 0.043 mm to 0.022 mm. Determine the yield stressfor the same metal with an average grain diameter of 0.030 mm.arrow_forward1. Two iron samples with different grain sizes are tensile tested. The grain size of sample A is 0.37 um and the grain size of sample B is 1.10 μm. (a) Sketch stress-strain curves of both samples on the same graph. (b) Compare the yield strength, tensile strength, ductility and elastic modulus. (c) Explain the effect of grain size on tensile properties.arrow_forwardHelp me pleasearrow_forward
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