Foundations of Materials Science and Engineering
6th Edition
ISBN: 9781259696558
Author: SMITH
Publisher: MCG
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Chapter 6.13, Problem 73SEP
When manufacturing complex shapes using cold forging or shape rolling operations, the
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Do you expect a material's stiffness to increase or decrease if there is more than one deformation mechanism occuring? Why?
A 20 foot long x 4 feet wide x ½ inch thick sheet of an aluminum alloy is cold rolled to a thickness of ¼ inch. During the rolling operation the with of the sheet increases by 10%. The strength coefficient (K) and the strain hardening coefficient (n ) for the aluminum alloy are 25,500 psi and 0.3, respectively
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Chapter 6 Solutions
Foundations of Materials Science and Engineering
Ch. 6.13 - (a) How are metal alloys made by the casting...Ch. 6.13 - Why are cast metal sheet ingots hot-rolled first...Ch. 6.13 - What type of heat treatment is given to the rolled...Ch. 6.13 - Describe and illustrate the following types of...Ch. 6.13 - Describe the forging process. What is the...Ch. 6.13 - What is the difference between open-die and...Ch. 6.13 - Describe the wire-drawing process. Why is it...Ch. 6.13 - Distinguish between elastic and plastic...Ch. 6.13 - Define (a) engineering stress and strain and (b)...Ch. 6.13 - Define (a) modulus of elasticity, (b) yield...
Ch. 6.13 - (a) Define the hardness of a metal. (b) How is the...Ch. 6.13 - What types of indenters are used in (a) the...Ch. 6.13 - What are slipbands and slip lines? What causes the...Ch. 6.13 - Describe the slip mechanism that enables a metal...Ch. 6.13 - (a) Why does slip in metals usually take place on...Ch. 6.13 - Prob. 16KCPCh. 6.13 - What other types of slip planes are important...Ch. 6.13 - Define the critical resolved shear stress for a...Ch. 6.13 - Describe the deformation twinning process that...Ch. 6.13 - What is the difference between the slip and...Ch. 6.13 - Prob. 21KCPCh. 6.13 - Prob. 22KCPCh. 6.13 - What experimental evidence shows that grain...Ch. 6.13 - (a) Describe the grain shape changes that occur...Ch. 6.13 - How is the ductility of a metal normally affected...Ch. 6.13 - (a) What is solid-solution strengthening? Describe...Ch. 6.13 - What are the three main metallurgical stages that...Ch. 6.13 - Describe the microstructure of a heavily...Ch. 6.13 - Describe what occurs microscopically when a...Ch. 6.13 - When a cold-worked metal is heated into the...Ch. 6.13 - Describe what occurs microscopically when a...Ch. 6.13 - When a cold-worked metal is heated into the...Ch. 6.13 - Prob. 33KCPCh. 6.13 - Prob. 34KCPCh. 6.13 - Prob. 35KCPCh. 6.13 - Prob. 36KCPCh. 6.13 - Prob. 37KCPCh. 6.13 - Why are nanocrystalline materials stronger? Answer...Ch. 6.13 - A 70% Cu30% Zn brass sheet is 0.0955 cm thick and...Ch. 6.13 - A sheet of aluminum alloy is cold-rolled 30% to a...Ch. 6.13 - Calculate the percent cold reduction when an...Ch. 6.13 - Prob. 42AAPCh. 6.13 - What is the relationship between engineering...Ch. 6.13 - A tensile specimen of cartridge brass sheet has a...Ch. 6.13 - A 0.505-in.-diameter rod of an aluminum alloy is...Ch. 6.13 - In Figure 6.23, estimate the toughness of SAE 1340...Ch. 6.13 - The following engineering stress-strain data were...Ch. 6.13 - Prob. 49AAPCh. 6.13 - A 0.505-in.-diameter aluminum alloy test bar is...Ch. 6.13 - A 20-cm-long rod with a diameter of 0.250 cm is...Ch. 6.13 - Prob. 52AAPCh. 6.13 - Prob. 53AAPCh. 6.13 - Prob. 54AAPCh. 6.13 - Prob. 55AAPCh. 6.13 - Prob. 56AAPCh. 6.13 - A specimen of commercially pure titanium has a...Ch. 6.13 - Prob. 58AAPCh. 6.13 - Prob. 59AAPCh. 6.13 - Prob. 60AAPCh. 6.13 - Prob. 61AAPCh. 6.13 - Prob. 62AAPCh. 6.13 - Prob. 63AAPCh. 6.13 - Prob. 64AAPCh. 6.13 - Prob. 65SEPCh. 6.13 - Prob. 66SEPCh. 6.13 - A 20-mm-diameter, 350-mm-long rod made of an...Ch. 6.13 - Prob. 68SEPCh. 6.13 - Prob. 69SEPCh. 6.13 - Consider casting a cube and a sphere on the same...Ch. 6.13 - When manufacturing complex shapes using cold...Ch. 6.13 - Prob. 74SEPCh. 6.13 - Draw a generic engineering stress-strain diagram...Ch. 6.13 - (a) Draw a generic engineering stress-strain...Ch. 6.13 - Prob. 77SEPCh. 6.13 - Prob. 78SEPCh. 6.13 - Prob. 79SEPCh. 6.13 - The material for a rod of cross-sectional area...Ch. 6.13 - What do E, G, v, Ur, and toughness tell you about...Ch. 6.13 - A cylindrical component is loaded in tension until...Ch. 6.13 - Referring to Figures 6.20 and 6.21 (read the...Ch. 6.13 - (a) Show, using the definition of the Poissons...Ch. 6.13 - A one-inch cube of tempered stainless steel (alloy...Ch. 6.13 - Prob. 87SEPCh. 6.13 - Prob. 88SEPCh. 6.13 - Prob. 89SEPCh. 6.13 - Prob. 90SEPCh. 6.13 - Prob. 91SEPCh. 6.13 - Prob. 92SEPCh. 6.13 - Prob. 93SEPCh. 6.13 - Prob. 94SEPCh. 6.13 - Starting with a 2-in.-diameter rod of brass, we...Ch. 6.13 - Prob. 96SEPCh. 6.13 - Prob. 97SEPCh. 6.13 - Prob. 98SEPCh. 6.13 - The cupro-nickel substitutional solid solution...Ch. 6.13 - Prob. 100SEP
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- The tensile strength for cold-rolled magnesium alloy AZ31B plate is approximately 160 MPa for specimens tested either parallel or perpendicular to the rolling direction. When similarly oriented specimens are compressed, the yield strength is only 90 MPa. Why? (Hint: Consider the possible deformation mechanisms available in the magnesium alloy and any crystallographic texture that might exist in the wrought plate.)arrow_forwardAn open die forging operation is performed to produce a steel cylinder with a diameter of 9.7mm and a height of 1.7mm. The strength coefficient for this steel is 500MPA, and the strain hardening exponent is 0.25. Coefficient of friction at the die-work interface is 0.12. The initial stock of raw material has a diameter of 5mm. (a) What height/length of stock is needed to provide sufficient volume of material for this forging operation? (b) Compute the maximum force that the punch must apply to form the head in this open- die operation.arrow_forward5) A steel specimen of rectangular cross section with 120 mm width, 180 mm thickness and 90 mm height was upset at room temperature by open-die forging to a height of 55 mm. If the strength coefficient and strain hardening exponent of this material were 1015 MPa and 0.17 respectively, the coefficient of friction is 0.2, and assuming that the thickness would not change during forging; determine the required upsetting force at the end of stroke.arrow_forward
- What is the difference between drawing and extrusion?arrow_forwardA square bar with an initial size of 13.2 mm is reduced by cold work to 10.7 mm (still square). If the radius of a cylindrical specimen, same material, was reduced by cold work also to 27 mm, what was its initial radius (mm) if the mechanical properties turns out to be similar to the square bar specimen?arrow_forwardIn a typical engineering stress-strain diagram, stress keeps on increasing after yield point due to strain hardening. In a few words or in a single short sentence explain what causes strain hardening?arrow_forward
- A sheet of aluminium alloy is reduced in thickness by 25% following a rolling operation. Tensile test specimens were cut from the sheet before and after rolling. Sketch the tensile test curves for both specimens, making reference to the differences if any, in Young’s modulus, the elastic limit and the level of ductilityarrow_forwardWhat is “Necking”? How does it lead to reduction in engineering stress as true stress increases?arrow_forwardWhy are the deformations that take place within a body are almostinfinitesimal?arrow_forward
- Why the cupping test may not predict well the formability of sheet metals in actual forming processes? Cupping test uses square or rectangular specimens only. Strain in some forming operations is not axi-symmetric. Cupping test is mainly for compression Stress is rarely uni-directional in sheet metal forming.arrow_forwardQuestion 3. 120 mm diameter and 600 mm long copper material will be produced by direct extrusion process as follows. Strength coefficient for copper is 300 MPa and plyumization base The pattern angle constants are 0.5. Accordingly, it is not the case. a) The rate of extrusion, b) The shape factor, c) While the remaining material in the cylinder is 500 mm, the force required to ensure the forward movement of the ram during extrusion, d) At the end of the process, if the volume of the last part of the cylinder is 0.4 dm3 find the length of the extruded part. 2,7 mm 55 mmarrow_forwardYou have been asked to work on some design problems and technically support the team working on extrusion and forging operations: 1) The team are extruding a billet that is 80 mm long with diameter of 40 mm is directly to a diameter of 20 mm. The extrusion die has a die angle of 75°, see Figure 1. For the work metal, K = 600 MPa and n = 0.25. In the Johnson extrusion strain equation, a = 0.8 and b = 1.4. Remaining billet length 75 Ram pressure, p D. Dr Figure 1: Extrusion process. Determine the following design parameters: (a) Extrusion ratio. (b) True strain (homogeneous deformation). (c) Extrusion strain. (d) Ram pressure at L= 80, 40, and 10 mm. (e) Draw the relationship between the ram pressure and billet length and discuss the results. What are your recommendations to dccrcase the required ram pressure?arrow_forward
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