Foundations of Materials Science and Engineering
6th Edition
ISBN: 9781259696558
Author: SMITH
Publisher: MCG
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Chapter 6.13, Problem 40AAP
A sheet of aluminum alloy is cold-rolled 30% to a thickness of 0.080 in. If the sheet is then cold-rolled to a final thickness of 0.064 in., what is the total percent cold work done?
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Question 4
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You do a series of tensile tests on plates of a magnesium alloy that have been subjected to prior cold rolling to true plastic
strains of 0.1, 0.2 and 0.3. The resulting true stress-true strain curves are shown below (including a zoomed in version
expanding on the small strain region). It is reasonable to approximate the the 0.2% offset yield strength of the magnesium as
✓ MPa for 0.2 and ✓ MPa for 0.3. Assuming the yield strength is
✓ MPa for 0.1 plastic strain,
proportional to the square root of the prior true plastic strain results in a hardening coefficient of approximately k=
MPa. Hence, we can predict that we need a prior plastic strain of approximately
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Question-1
A 70% Cu-30% Zn brass wire is cold-drawn 20 percent to a diameter of 2.80 mm. The wire is then further cold-
drawn to a diameter of 2.45 mm.
(a) Calculate the total percent cold work that the wire undergoes.
(b) Estimate the wire's tensile and yield strengths and elongation.
An 0.29 inch diameter copper bar is to be cold worked 57%. Find the final diameter in inches.
Chapter 6 Solutions
Foundations of Materials Science and Engineering
Ch. 6.13 - (a) How are metal alloys made by the casting...Ch. 6.13 - Why are cast metal sheet ingots hot-rolled first...Ch. 6.13 - What type of heat treatment is given to the rolled...Ch. 6.13 - Describe and illustrate the following types of...Ch. 6.13 - Describe the forging process. What is the...Ch. 6.13 - What is the difference between open-die and...Ch. 6.13 - Describe the wire-drawing process. Why is it...Ch. 6.13 - Distinguish between elastic and plastic...Ch. 6.13 - Define (a) engineering stress and strain and (b)...Ch. 6.13 - Define (a) modulus of elasticity, (b) yield...
Ch. 6.13 - (a) Define the hardness of a metal. (b) How is the...Ch. 6.13 - What types of indenters are used in (a) the...Ch. 6.13 - What are slipbands and slip lines? What causes the...Ch. 6.13 - Describe the slip mechanism that enables a metal...Ch. 6.13 - (a) Why does slip in metals usually take place on...Ch. 6.13 - Prob. 16KCPCh. 6.13 - What other types of slip planes are important...Ch. 6.13 - Define the critical resolved shear stress for a...Ch. 6.13 - Describe the deformation twinning process that...Ch. 6.13 - What is the difference between the slip and...Ch. 6.13 - Prob. 21KCPCh. 6.13 - Prob. 22KCPCh. 6.13 - What experimental evidence shows that grain...Ch. 6.13 - (a) Describe the grain shape changes that occur...Ch. 6.13 - How is the ductility of a metal normally affected...Ch. 6.13 - (a) What is solid-solution strengthening? Describe...Ch. 6.13 - What are the three main metallurgical stages that...Ch. 6.13 - Describe the microstructure of a heavily...Ch. 6.13 - Describe what occurs microscopically when a...Ch. 6.13 - When a cold-worked metal is heated into the...Ch. 6.13 - Describe what occurs microscopically when a...Ch. 6.13 - When a cold-worked metal is heated into the...Ch. 6.13 - Prob. 33KCPCh. 6.13 - Prob. 34KCPCh. 6.13 - Prob. 35KCPCh. 6.13 - Prob. 36KCPCh. 6.13 - Prob. 37KCPCh. 6.13 - Why are nanocrystalline materials stronger? Answer...Ch. 6.13 - A 70% Cu30% Zn brass sheet is 0.0955 cm thick and...Ch. 6.13 - A sheet of aluminum alloy is cold-rolled 30% to a...Ch. 6.13 - Calculate the percent cold reduction when an...Ch. 6.13 - Prob. 42AAPCh. 6.13 - What is the relationship between engineering...Ch. 6.13 - A tensile specimen of cartridge brass sheet has a...Ch. 6.13 - A 0.505-in.-diameter rod of an aluminum alloy is...Ch. 6.13 - In Figure 6.23, estimate the toughness of SAE 1340...Ch. 6.13 - The following engineering stress-strain data were...Ch. 6.13 - Prob. 49AAPCh. 6.13 - A 0.505-in.-diameter aluminum alloy test bar is...Ch. 6.13 - A 20-cm-long rod with a diameter of 0.250 cm is...Ch. 6.13 - Prob. 52AAPCh. 6.13 - Prob. 53AAPCh. 6.13 - Prob. 54AAPCh. 6.13 - Prob. 55AAPCh. 6.13 - Prob. 56AAPCh. 6.13 - A specimen of commercially pure titanium has a...Ch. 6.13 - Prob. 58AAPCh. 6.13 - Prob. 59AAPCh. 6.13 - Prob. 60AAPCh. 6.13 - Prob. 61AAPCh. 6.13 - Prob. 62AAPCh. 6.13 - Prob. 63AAPCh. 6.13 - Prob. 64AAPCh. 6.13 - Prob. 65SEPCh. 6.13 - Prob. 66SEPCh. 6.13 - A 20-mm-diameter, 350-mm-long rod made of an...Ch. 6.13 - Prob. 68SEPCh. 6.13 - Prob. 69SEPCh. 6.13 - Consider casting a cube and a sphere on the same...Ch. 6.13 - When manufacturing complex shapes using cold...Ch. 6.13 - Prob. 74SEPCh. 6.13 - Draw a generic engineering stress-strain diagram...Ch. 6.13 - (a) Draw a generic engineering stress-strain...Ch. 6.13 - Prob. 77SEPCh. 6.13 - Prob. 78SEPCh. 6.13 - Prob. 79SEPCh. 6.13 - The material for a rod of cross-sectional area...Ch. 6.13 - What do E, G, v, Ur, and toughness tell you about...Ch. 6.13 - A cylindrical component is loaded in tension until...Ch. 6.13 - Referring to Figures 6.20 and 6.21 (read the...Ch. 6.13 - (a) Show, using the definition of the Poissons...Ch. 6.13 - A one-inch cube of tempered stainless steel (alloy...Ch. 6.13 - Prob. 87SEPCh. 6.13 - Prob. 88SEPCh. 6.13 - Prob. 89SEPCh. 6.13 - Prob. 90SEPCh. 6.13 - Prob. 91SEPCh. 6.13 - Prob. 92SEPCh. 6.13 - Prob. 93SEPCh. 6.13 - Prob. 94SEPCh. 6.13 - Starting with a 2-in.-diameter rod of brass, we...Ch. 6.13 - Prob. 96SEPCh. 6.13 - Prob. 97SEPCh. 6.13 - Prob. 98SEPCh. 6.13 - The cupro-nickel substitutional solid solution...Ch. 6.13 - Prob. 100SEP
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- ASAParrow_forwardQuestion 4 You do a series of tensile tests on plates of a magnesium alloy that have been subjected to prior cold rolling to true plastic strains of 0.1, 0.2 and 0.3. The resulting true stress-true strain curves are shown below (including a zoomed in version expanding on the small strain region). It is reasonable to approximate the the 0.2% offset yield strength of the magnesium as ✓ MPa for 0.1 plastic strain, ✓ MPa for 0.2 and ✓ MPa for 0.3. Assuming the yield strength is proportional to the square root of the prior true plastic strain results in a hardening coefficient of approximately k= ✓ MPa. Hence, we can predict that we need a prior plastic strain of approximately ✓to obtain a hgth of 120 MPa True Stress (MPa) 250 200 100 85 95 50 105 115 125 135 145 300 350 0.12 0.14 150 0.16 0.18 155 165 175 200 250 0.1 True Stress (MPa) Ep = 0.1 Zoomed version of left plotarrow_forward2.) An S-five ninety alloy specimen nine hundred mm long will be subjected to eighty MPa tensile stress at eight hundred and fifteen degrees celcius. Later after five thousand of hours, compute its elongation. Consider a sum of one point five mm in the both immediate and main creep elongations.arrow_forward
- Consider the graph below for 3 metals which have been cold-worked. From the graphs, which of the following statements are true? Stress o Select one or more: □ c. Strain & A e. B a. B and C have similar hardness; C has greater brittleness b. B is softer than C and has nearly similar ductility A is harder than C and is more ductile C d. B is harder than C but has nearly similar ductility A is harder than C and is less ductile f. A and B have similar hardness; A has greater brittlenessarrow_forwardA 20 foot long x 4 feet wide x ½ inch thick sheet of an aluminum alloy is cold rolled to a thickness of ¼ inch. During the rolling operation the with of the sheet increases by 10%. The strength coefficient (K) and the strain hardening coefficient (n ) for the aluminum alloy are 25,500 psi and 0.3, respectively. Calculate the length of the sheet after the rolling operation in feet.arrow_forwardb) A metal wire is cold drawn from a radius of 5.75 mm to a radius of 3.25 mm. Compute the percent of the cold reduction in this process. (Ans: 68.05% c) A certain metal has a modulus of elasticity of 115 GPa, and its plastic deformation begins at a stress of 275 MPa. Calculate the maximum elongation to which it can be stretched without plastic deformation, if the metal has a length of 120 mm.arrow_forward
- A 20 foot long x 4 feet wide x ½ inch thick sheet of an aluminum alloy is cold rolled to a thickness of ¼ inch. During the rolling operation the with of the sheet increases by 10%. The strength coefficient (K) and the strain hardening coefficient (n ) for the aluminum alloy are 25,500 psi and 0.3, respectively Calculate the true strain at the end of the rolling process.arrow_forwardpart made from AISI 1212 steel undergoes a 20 percent cold-work operation. (a) Obtain the yield strength and ultimate strength before and after the cold-work operation. Determine the percent increase in each strength. (b) Determine the ratios of ultimate strength to yield strength before and after the cold work operation. What does the result indicate about the change of ductility of the part?arrow_forwardNo wrong answer please , i could downvote The piece of suture is tested for its stress relaxation properties after cutting 3 cm long sample with a diameter of 1mm. The initial force recorded after stretching 0.1 cm between grips was 5 Newtons. Assume the suture material behave as if it has one relaxation time. The gage length was 1 cm. a. Calculate the initial stress. b. Calculate the initial strain. c. Calculate the modulus of elasticity of the suture if the initial stretching can be considered as linear and elastic. d. Calculate the relaxation time if the force recorded after 10 hours is 4 Newtons.arrow_forward
- A 2.0-inch diameter 4140 steel bar is austenized and tempered in oil without Agitation, determine the resulting hardness at 0.6 inches below the surface, present all the Procedure to arrive at the answer (include sketch of the piece and graph used with steps Using word forms)arrow_forwardConsider the graph below for 3 metals which have been cold-worked. From the graphs, which of the following statements are true? Stress & Strain & O c. A B Select one or more: O a. B and C have similar hardness; C has greater brittleness O f. b. A and B have similar hardness; A has greater brittleness C A is harder than C and is less ductile Od. B is harder than C but has nearly similar ductility O e. B is softer than C and has nearly similar ductility A is harder than C and is more ductilearrow_forwardHelp me pleasearrow_forward
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