Foundations of Materials Science and Engineering
6th Edition
ISBN: 9781259696558
Author: SMITH
Publisher: MCG
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Chapter 6.13, Problem 13KCP
What are slipbands and slip lines? What causes the formation of slipbands on a metal surface?
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Magnesium oxide is cubic (having the same structure as NaCl). The slip planes and directions are [110] and <110>, respectively. Along which directions, if any, can a tensile (or compressive) stress be applied without producing slip?
Consider a metal single crystal oriented such that the normal to the slip plane and the slip direction are at angles of 43.1° and 47.9°, respectively, with the tensile axis. If the critical resolved shear stress is 20.7 MPa (3000 psi), will an applied stress of 45 MPa (6500 psi) cause the single crystal to yield? If not, what stress will be necessary?
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Chapter 6 Solutions
Foundations of Materials Science and Engineering
Ch. 6.13 - (a) How are metal alloys made by the casting...Ch. 6.13 - Why are cast metal sheet ingots hot-rolled first...Ch. 6.13 - What type of heat treatment is given to the rolled...Ch. 6.13 - Describe and illustrate the following types of...Ch. 6.13 - Describe the forging process. What is the...Ch. 6.13 - What is the difference between open-die and...Ch. 6.13 - Describe the wire-drawing process. Why is it...Ch. 6.13 - Distinguish between elastic and plastic...Ch. 6.13 - Define (a) engineering stress and strain and (b)...Ch. 6.13 - Define (a) modulus of elasticity, (b) yield...
Ch. 6.13 - (a) Define the hardness of a metal. (b) How is the...Ch. 6.13 - What types of indenters are used in (a) the...Ch. 6.13 - What are slipbands and slip lines? What causes the...Ch. 6.13 - Describe the slip mechanism that enables a metal...Ch. 6.13 - (a) Why does slip in metals usually take place on...Ch. 6.13 - Prob. 16KCPCh. 6.13 - What other types of slip planes are important...Ch. 6.13 - Define the critical resolved shear stress for a...Ch. 6.13 - Describe the deformation twinning process that...Ch. 6.13 - What is the difference between the slip and...Ch. 6.13 - Prob. 21KCPCh. 6.13 - Prob. 22KCPCh. 6.13 - What experimental evidence shows that grain...Ch. 6.13 - (a) Describe the grain shape changes that occur...Ch. 6.13 - How is the ductility of a metal normally affected...Ch. 6.13 - (a) What is solid-solution strengthening? Describe...Ch. 6.13 - What are the three main metallurgical stages that...Ch. 6.13 - Describe the microstructure of a heavily...Ch. 6.13 - Describe what occurs microscopically when a...Ch. 6.13 - When a cold-worked metal is heated into the...Ch. 6.13 - Describe what occurs microscopically when a...Ch. 6.13 - When a cold-worked metal is heated into the...Ch. 6.13 - Prob. 33KCPCh. 6.13 - Prob. 34KCPCh. 6.13 - Prob. 35KCPCh. 6.13 - Prob. 36KCPCh. 6.13 - Prob. 37KCPCh. 6.13 - Why are nanocrystalline materials stronger? Answer...Ch. 6.13 - A 70% Cu30% Zn brass sheet is 0.0955 cm thick and...Ch. 6.13 - A sheet of aluminum alloy is cold-rolled 30% to a...Ch. 6.13 - Calculate the percent cold reduction when an...Ch. 6.13 - Prob. 42AAPCh. 6.13 - What is the relationship between engineering...Ch. 6.13 - A tensile specimen of cartridge brass sheet has a...Ch. 6.13 - A 0.505-in.-diameter rod of an aluminum alloy is...Ch. 6.13 - In Figure 6.23, estimate the toughness of SAE 1340...Ch. 6.13 - The following engineering stress-strain data were...Ch. 6.13 - Prob. 49AAPCh. 6.13 - A 0.505-in.-diameter aluminum alloy test bar is...Ch. 6.13 - A 20-cm-long rod with a diameter of 0.250 cm is...Ch. 6.13 - Prob. 52AAPCh. 6.13 - Prob. 53AAPCh. 6.13 - Prob. 54AAPCh. 6.13 - Prob. 55AAPCh. 6.13 - Prob. 56AAPCh. 6.13 - A specimen of commercially pure titanium has a...Ch. 6.13 - Prob. 58AAPCh. 6.13 - Prob. 59AAPCh. 6.13 - Prob. 60AAPCh. 6.13 - Prob. 61AAPCh. 6.13 - Prob. 62AAPCh. 6.13 - Prob. 63AAPCh. 6.13 - Prob. 64AAPCh. 6.13 - Prob. 65SEPCh. 6.13 - Prob. 66SEPCh. 6.13 - A 20-mm-diameter, 350-mm-long rod made of an...Ch. 6.13 - Prob. 68SEPCh. 6.13 - Prob. 69SEPCh. 6.13 - Consider casting a cube and a sphere on the same...Ch. 6.13 - When manufacturing complex shapes using cold...Ch. 6.13 - Prob. 74SEPCh. 6.13 - Draw a generic engineering stress-strain diagram...Ch. 6.13 - (a) Draw a generic engineering stress-strain...Ch. 6.13 - Prob. 77SEPCh. 6.13 - Prob. 78SEPCh. 6.13 - Prob. 79SEPCh. 6.13 - The material for a rod of cross-sectional area...Ch. 6.13 - What do E, G, v, Ur, and toughness tell you about...Ch. 6.13 - A cylindrical component is loaded in tension until...Ch. 6.13 - Referring to Figures 6.20 and 6.21 (read the...Ch. 6.13 - (a) Show, using the definition of the Poissons...Ch. 6.13 - A one-inch cube of tempered stainless steel (alloy...Ch. 6.13 - Prob. 87SEPCh. 6.13 - Prob. 88SEPCh. 6.13 - Prob. 89SEPCh. 6.13 - Prob. 90SEPCh. 6.13 - Prob. 91SEPCh. 6.13 - Prob. 92SEPCh. 6.13 - Prob. 93SEPCh. 6.13 - Prob. 94SEPCh. 6.13 - Starting with a 2-in.-diameter rod of brass, we...Ch. 6.13 - Prob. 96SEPCh. 6.13 - Prob. 97SEPCh. 6.13 - Prob. 98SEPCh. 6.13 - The cupro-nickel substitutional solid solution...Ch. 6.13 - Prob. 100SEP
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.Similar questions
- Help me pleasearrow_forwardSlip in Single Crystals 2. Consider a metal single crystal oriented such that the normal to the slip plane and the slip direction are at angles of $ and λ, respectively, with the tensile axis. If the critical resolved shear stress is TCRSS, will an applied stress of σ cause the single crystal to yield? If not, what stress will be necessary? Use = 43.1° ; λ = 47.9° ; TCRSS = 20.7 MPa ; σ = 45 MPaarrow_forwardWhat does the slip being between 0,1-1 mean?arrow_forward
- Consider a metal single crystal oriented such that the normal to the slip plane and the slip direction are at angles of 35.5° and 25.4° , respectively, with the tensile axis. If the critical resolved shear stress is 25 MPa, will an applied stress of 30 MPa cause the single crystal to yield? If not, what stress will be necessary? (1)Yes it is enough to yield (2)No it is not enough to yield, 31 Mpa will be enoug (3)No it is not enough to yield, 32 Mpa will be enough (4)No it is not enough to yield, 33 Mpa will be enough (5)No it is too much to yield, 24 Mpa or smaller should it bearrow_forwardWhat must be true about the dimensions of a plate in order for plane-strain conditions to apply?arrow_forwardConsider a single crystal oriented such that the slip direction and normal to the slip plane are at angles 42.7° and 48.3°, respectively, with the tensile axis. If the critical resolved shear stress is 27.1 MPa, what applied stress (in MPa) will be necessary to cause the single crystal to yield?arrow_forward
- 2.) Two previously undeformed specimens of the same metal are to be plastically deformed by reducing their cross-sectional areas. One has a circular cross section, and the other is rectangular; during deformation the circular cross section is to remain circular, and the rectangular is to remain as such. Their original and deformed dimensions are as follows: Circular Rectangular (diameter, mm) (тm) Original dimensions Deformed dimensions 18.0 20 x 50 15.9 13.7 × 55.1 Which of these specimens will be the hardest after the plastic deformation? a) The deformed circular specimen will be harder b) The deformed rectangular specimen will be harder c) Both will have the same hardness d) Both would brake e) No estimation can be made for such processarrow_forwardHelp me pleasearrow_forwarda) Briefly explain why HCP metals are typically more brittle than FCC and BCC metals. b) Two previously undeformed specimens of the same metal are to be plastically deformed by reducing their cross-sectional areas (cold work). One has a circular cross section, and the other is rectangular; during deformation the circular cross section is to remain circular, and the rectangular is to remain as such. Their original and deformed dimensions are as follows: Circular (diameter, mm) Rectangular (mm) 125 x 175 Original dimensions 15.2 Deformed dimensions 11.4 75 x 200 Which of these specimens will be the hardest after plastic deformation, and why?arrow_forward
- Which of these cracks will lead to failure first from the table in the picture? And present your findings in a table format and comment briefly.arrow_forwardHelp me pleasearrow_forwardWhich one of the following materials would plastic deformation through twinning be the most likely to occur? O a material with a BCC crystal structure a material with an HCP crystal structure O an amorphous material (no crystal structure) none, twinning does not occur in regular materials Question 2 What is the resolved shear stress in the (111)[110] slip system due to a normal stress of 10 MPa applied in the [010] direction? O -2.31 MPa O -5.35 MPa -4.08 MPa -6.35 MPaarrow_forward
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