Foundations of Materials Science and Engineering
6th Edition
ISBN: 9781259696558
Author: SMITH
Publisher: MCG
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Chapter 6.13, Problem 74SEP
a)
To determine
The Assumption used to develop the equation 6.15 has to be stated.
b)
To determine
The assumption is valid throughout the engineering stress-strain curve has to be check.
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Students have asked these similar questions
If material A is observed to have twice the modulus of rigidity but the same Poisson's ratio and yield shear stress than that of material B, then which of
the following comparisons is always true?
Select one:
Material A can resist higher normal stresses than material B can before permanent normal deformations occur.
O b
For the same load that brings the materials to plastic behavior, material A will experience larger permanent shear deformations than material B.
Material A can resist higher shear stresses than material B before permanent shear deformations occur.
O d. Material B is has a lower ultimate stress than material A.
In True stress-true-strain curve in tension of solid metal cylinder 45 mm high and 8 mm in diameter, two
pairs of values of stress and strain were given for the specimen metal after it had yielded (1) true stress =
217 MPa, and true strain = 0.35; and (2) true stress = 259 MPa, and true strain = 0.68. Based on these data
points, determine the following:
a) The average flow stress that the metal experiences if it is subjected to a stress that is equal to its
strength coefficient K.
b) The work done that the metal experiences if it is subjected to elongation in height of 45%
c) If during the deformation the relative speed = 20 mm/s, determine the strain rate at h = 50 mm and
h = 70 mm.
Which predicts the lower yield strength for most combinations of applied stress––the Tresca or the von Mises yield criterion? Under what stress conditions are the predictions equal?
Chapter 6 Solutions
Foundations of Materials Science and Engineering
Ch. 6.13 - (a) How are metal alloys made by the casting...Ch. 6.13 - Why are cast metal sheet ingots hot-rolled first...Ch. 6.13 - What type of heat treatment is given to the rolled...Ch. 6.13 - Describe and illustrate the following types of...Ch. 6.13 - Describe the forging process. What is the...Ch. 6.13 - What is the difference between open-die and...Ch. 6.13 - Describe the wire-drawing process. Why is it...Ch. 6.13 - Distinguish between elastic and plastic...Ch. 6.13 - Define (a) engineering stress and strain and (b)...Ch. 6.13 - Define (a) modulus of elasticity, (b) yield...
Ch. 6.13 - (a) Define the hardness of a metal. (b) How is the...Ch. 6.13 - What types of indenters are used in (a) the...Ch. 6.13 - What are slipbands and slip lines? What causes the...Ch. 6.13 - Describe the slip mechanism that enables a metal...Ch. 6.13 - (a) Why does slip in metals usually take place on...Ch. 6.13 - Prob. 16KCPCh. 6.13 - What other types of slip planes are important...Ch. 6.13 - Define the critical resolved shear stress for a...Ch. 6.13 - Describe the deformation twinning process that...Ch. 6.13 - What is the difference between the slip and...Ch. 6.13 - Prob. 21KCPCh. 6.13 - Prob. 22KCPCh. 6.13 - What experimental evidence shows that grain...Ch. 6.13 - (a) Describe the grain shape changes that occur...Ch. 6.13 - How is the ductility of a metal normally affected...Ch. 6.13 - (a) What is solid-solution strengthening? Describe...Ch. 6.13 - What are the three main metallurgical stages that...Ch. 6.13 - Describe the microstructure of a heavily...Ch. 6.13 - Describe what occurs microscopically when a...Ch. 6.13 - When a cold-worked metal is heated into the...Ch. 6.13 - Describe what occurs microscopically when a...Ch. 6.13 - When a cold-worked metal is heated into the...Ch. 6.13 - Prob. 33KCPCh. 6.13 - Prob. 34KCPCh. 6.13 - Prob. 35KCPCh. 6.13 - Prob. 36KCPCh. 6.13 - Prob. 37KCPCh. 6.13 - Why are nanocrystalline materials stronger? Answer...Ch. 6.13 - A 70% Cu30% Zn brass sheet is 0.0955 cm thick and...Ch. 6.13 - A sheet of aluminum alloy is cold-rolled 30% to a...Ch. 6.13 - Calculate the percent cold reduction when an...Ch. 6.13 - Prob. 42AAPCh. 6.13 - What is the relationship between engineering...Ch. 6.13 - A tensile specimen of cartridge brass sheet has a...Ch. 6.13 - A 0.505-in.-diameter rod of an aluminum alloy is...Ch. 6.13 - In Figure 6.23, estimate the toughness of SAE 1340...Ch. 6.13 - The following engineering stress-strain data were...Ch. 6.13 - Prob. 49AAPCh. 6.13 - A 0.505-in.-diameter aluminum alloy test bar is...Ch. 6.13 - A 20-cm-long rod with a diameter of 0.250 cm is...Ch. 6.13 - Prob. 52AAPCh. 6.13 - Prob. 53AAPCh. 6.13 - Prob. 54AAPCh. 6.13 - Prob. 55AAPCh. 6.13 - Prob. 56AAPCh. 6.13 - A specimen of commercially pure titanium has a...Ch. 6.13 - Prob. 58AAPCh. 6.13 - Prob. 59AAPCh. 6.13 - Prob. 60AAPCh. 6.13 - Prob. 61AAPCh. 6.13 - Prob. 62AAPCh. 6.13 - Prob. 63AAPCh. 6.13 - Prob. 64AAPCh. 6.13 - Prob. 65SEPCh. 6.13 - Prob. 66SEPCh. 6.13 - A 20-mm-diameter, 350-mm-long rod made of an...Ch. 6.13 - Prob. 68SEPCh. 6.13 - Prob. 69SEPCh. 6.13 - Consider casting a cube and a sphere on the same...Ch. 6.13 - When manufacturing complex shapes using cold...Ch. 6.13 - Prob. 74SEPCh. 6.13 - Draw a generic engineering stress-strain diagram...Ch. 6.13 - (a) Draw a generic engineering stress-strain...Ch. 6.13 - Prob. 77SEPCh. 6.13 - Prob. 78SEPCh. 6.13 - Prob. 79SEPCh. 6.13 - The material for a rod of cross-sectional area...Ch. 6.13 - What do E, G, v, Ur, and toughness tell you about...Ch. 6.13 - A cylindrical component is loaded in tension until...Ch. 6.13 - Referring to Figures 6.20 and 6.21 (read the...Ch. 6.13 - (a) Show, using the definition of the Poissons...Ch. 6.13 - A one-inch cube of tempered stainless steel (alloy...Ch. 6.13 - Prob. 87SEPCh. 6.13 - Prob. 88SEPCh. 6.13 - Prob. 89SEPCh. 6.13 - Prob. 90SEPCh. 6.13 - Prob. 91SEPCh. 6.13 - Prob. 92SEPCh. 6.13 - Prob. 93SEPCh. 6.13 - Prob. 94SEPCh. 6.13 - Starting with a 2-in.-diameter rod of brass, we...Ch. 6.13 - Prob. 96SEPCh. 6.13 - Prob. 97SEPCh. 6.13 - Prob. 98SEPCh. 6.13 - The cupro-nickel substitutional solid solution...Ch. 6.13 - Prob. 100SEP
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.Similar questions
- Why do we define engineering and true stresses for tension/compression loading but not for shear loading?arrow_forward1. What are the elastic modulus (E) and the Poisson's ratio () used to indicate? 2. Illustrate the differences between actual stress and engineered stress with strain, and also describe their underlying physical concepts. 3. If the engineering strain is 2% for a specific state of uniaxial stress, what is the real strain? Please solve for all in full detail and step by steparrow_forwardHaving stress-strain relationship of ductile materials in your mind, highlight the differences between factor of safety to yield stress, and factor of safety to ultimate stress. Which one is more important in your opinion? Q1 (a)arrow_forward
- The ultimate tensile strength of a material is 400 MPa and the elongation up to maximum load is 35%. If the material obeys power law of hardening, then the true stress-true strain relation (stress in MPa) in the plastic deformation range is (b) o = 775 ɛ0.30 (d) o = 775 ɛ0.35 (a) o = 540ɛ0.30 %3D (c) o = 540 ɛ0.35 %3D %3Darrow_forward"The maximum principal stress yield criterion is an appropriate choice for ductile materials but the maximum principal strain criterion is preferable". Is this true or false?arrow_forwardYour boss is convinced and decided that the customers will save a lot of energy in processing material ifthe molecular weight of the polymethyl methacrylate (PMMA) manufactured is lower from 250,000g/mol to 150,000 g/mol. As a chief engineer in charge of mechanical properties, how will this affect thefracture energy (area under the stress strain curve)? Do you agree with this decision?arrow_forward
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- Q3a. The stress-strain characteristic curves for materials A, B and C are shown below. Which one statement most accurately describes the relative strength and toughness for materials A, B & C? Material A Material B Material C Strain Select one: a. Material A has low toughness, Material B has high strength and Material C has low toughness b. Material A has low strength, Material B has low toughness and Material C has high toughness c. Material A has high strength, Material B has low toughness and Material C has high toughness. O d. Material A has low strength, Material B has high toughness and Material C has high strength. Stressarrow_forwardTrue strain is based upon (A) Original c/s area (B) Final c/s area (C) Average c/s area (D) Instantaneous c/s areaarrow_forward3 1.5 1.5. Ө 2 2 1.5 1.5 3 Using a Factor of Safety (FoS) of 1.4, estimate the yield strength of a material to be selected to withstand the above stress state, using (i) the Tresca yield criterion, and the von Mises yield criterion. (ii)arrow_forward
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