Foundations of Materials Science and Engineering
6th Edition
ISBN: 9781259696558
Author: SMITH
Publisher: MCG
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 6.13, Problem 35KCP
a)
To determine
Generalize recrystallization temperature with respect to degree of deformation.
b)
To determine
Generalize recrystallization temperature with respect to temperature.
c)
To determine
Generalize recrystallization temperature with respect to time duration.
d)
To determine
Generalize recrystallization temperature with respect to grain size.
e)
To determine
Generalize recrystallization temperature with respect to Purity of metal.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
Question 2
a) Briefly explain why HCP metals are typically more brittle than FCC and BCC
metals.
b) Two previously undeformed specimens of the same metal are to be plastically
deformed by reducing their cross-sectional areas (cold work). One has a
circular cross section, and the other is rectangular; during deformation the
circular cross section is to remain circular, and the rectangular is to remain as
such. Their original and deformed dimensions are as follows:
Circular (diameter, mm)
Rectangular (mm)
Original dim ensions
15.2
125 x 175
Deformed dimensions
11.4
75 x 200
Which of these specimens will be the hardest after plastic deformation, and
why?
a) Briefly explain why HCP metals are typically more brittle than FCC and BCC
metals.
b) Two previously undeformed specimens of the same metal are to be plastically
deformed by reducing their cross-sectional areas (cold work). One has a
circular cross section, and the other is rectangular; during deformation the
circular cross section is to remain circular, and the rectangular is to remain as
such. Their original and deformed dimensions are as follows:
Circular (diameter, mm)
Rectangular (mm)
125 x 175
Original dimensions
15.2
Deformed dimensions
11.4
75 x 200
Which of these specimens will be the hardest after plastic deformation, and
why?
2.) Two previously undeformed specimens of the same metal are to be plastically deformed by
reducing their cross-sectional areas. One has a circular cross section, and the other is
rectangular; during deformation the circular cross section is to remain circular, and the
rectangular is to remain as such. Their original and deformed dimensions are as follows:
Circular
Rectangular
(diameter, mm)
(тm)
Original dimensions
Deformed dimensions
18.0
20 x 50
15.9
13.7 × 55.1
Which of these specimens will be the hardest after the plastic deformation?
a) The deformed circular specimen will be harder
b) The deformed rectangular specimen will be harder
c) Both will have the same hardness
d) Both would brake
e) No estimation can be made for such process
Chapter 6 Solutions
Foundations of Materials Science and Engineering
Ch. 6.13 - (a) How are metal alloys made by the casting...Ch. 6.13 - Why are cast metal sheet ingots hot-rolled first...Ch. 6.13 - What type of heat treatment is given to the rolled...Ch. 6.13 - Describe and illustrate the following types of...Ch. 6.13 - Describe the forging process. What is the...Ch. 6.13 - What is the difference between open-die and...Ch. 6.13 - Describe the wire-drawing process. Why is it...Ch. 6.13 - Distinguish between elastic and plastic...Ch. 6.13 - Define (a) engineering stress and strain and (b)...Ch. 6.13 - Define (a) modulus of elasticity, (b) yield...
Ch. 6.13 - (a) Define the hardness of a metal. (b) How is the...Ch. 6.13 - What types of indenters are used in (a) the...Ch. 6.13 - What are slipbands and slip lines? What causes the...Ch. 6.13 - Describe the slip mechanism that enables a metal...Ch. 6.13 - (a) Why does slip in metals usually take place on...Ch. 6.13 - Prob. 16KCPCh. 6.13 - What other types of slip planes are important...Ch. 6.13 - Define the critical resolved shear stress for a...Ch. 6.13 - Describe the deformation twinning process that...Ch. 6.13 - What is the difference between the slip and...Ch. 6.13 - Prob. 21KCPCh. 6.13 - Prob. 22KCPCh. 6.13 - What experimental evidence shows that grain...Ch. 6.13 - (a) Describe the grain shape changes that occur...Ch. 6.13 - How is the ductility of a metal normally affected...Ch. 6.13 - (a) What is solid-solution strengthening? Describe...Ch. 6.13 - What are the three main metallurgical stages that...Ch. 6.13 - Describe the microstructure of a heavily...Ch. 6.13 - Describe what occurs microscopically when a...Ch. 6.13 - When a cold-worked metal is heated into the...Ch. 6.13 - Describe what occurs microscopically when a...Ch. 6.13 - When a cold-worked metal is heated into the...Ch. 6.13 - Prob. 33KCPCh. 6.13 - Prob. 34KCPCh. 6.13 - Prob. 35KCPCh. 6.13 - Prob. 36KCPCh. 6.13 - Prob. 37KCPCh. 6.13 - Why are nanocrystalline materials stronger? Answer...Ch. 6.13 - A 70% Cu30% Zn brass sheet is 0.0955 cm thick and...Ch. 6.13 - A sheet of aluminum alloy is cold-rolled 30% to a...Ch. 6.13 - Calculate the percent cold reduction when an...Ch. 6.13 - Prob. 42AAPCh. 6.13 - What is the relationship between engineering...Ch. 6.13 - A tensile specimen of cartridge brass sheet has a...Ch. 6.13 - A 0.505-in.-diameter rod of an aluminum alloy is...Ch. 6.13 - In Figure 6.23, estimate the toughness of SAE 1340...Ch. 6.13 - The following engineering stress-strain data were...Ch. 6.13 - Prob. 49AAPCh. 6.13 - A 0.505-in.-diameter aluminum alloy test bar is...Ch. 6.13 - A 20-cm-long rod with a diameter of 0.250 cm is...Ch. 6.13 - Prob. 52AAPCh. 6.13 - Prob. 53AAPCh. 6.13 - Prob. 54AAPCh. 6.13 - Prob. 55AAPCh. 6.13 - Prob. 56AAPCh. 6.13 - A specimen of commercially pure titanium has a...Ch. 6.13 - Prob. 58AAPCh. 6.13 - Prob. 59AAPCh. 6.13 - Prob. 60AAPCh. 6.13 - Prob. 61AAPCh. 6.13 - Prob. 62AAPCh. 6.13 - Prob. 63AAPCh. 6.13 - Prob. 64AAPCh. 6.13 - Prob. 65SEPCh. 6.13 - Prob. 66SEPCh. 6.13 - A 20-mm-diameter, 350-mm-long rod made of an...Ch. 6.13 - Prob. 68SEPCh. 6.13 - Prob. 69SEPCh. 6.13 - Consider casting a cube and a sphere on the same...Ch. 6.13 - When manufacturing complex shapes using cold...Ch. 6.13 - Prob. 74SEPCh. 6.13 - Draw a generic engineering stress-strain diagram...Ch. 6.13 - (a) Draw a generic engineering stress-strain...Ch. 6.13 - Prob. 77SEPCh. 6.13 - Prob. 78SEPCh. 6.13 - Prob. 79SEPCh. 6.13 - The material for a rod of cross-sectional area...Ch. 6.13 - What do E, G, v, Ur, and toughness tell you about...Ch. 6.13 - A cylindrical component is loaded in tension until...Ch. 6.13 - Referring to Figures 6.20 and 6.21 (read the...Ch. 6.13 - (a) Show, using the definition of the Poissons...Ch. 6.13 - A one-inch cube of tempered stainless steel (alloy...Ch. 6.13 - Prob. 87SEPCh. 6.13 - Prob. 88SEPCh. 6.13 - Prob. 89SEPCh. 6.13 - Prob. 90SEPCh. 6.13 - Prob. 91SEPCh. 6.13 - Prob. 92SEPCh. 6.13 - Prob. 93SEPCh. 6.13 - Prob. 94SEPCh. 6.13 - Starting with a 2-in.-diameter rod of brass, we...Ch. 6.13 - Prob. 96SEPCh. 6.13 - Prob. 97SEPCh. 6.13 - Prob. 98SEPCh. 6.13 - The cupro-nickel substitutional solid solution...Ch. 6.13 - Prob. 100SEP
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.Similar questions
- We wish to produce a 0.3 inch thick plate of 3105 aluminum having a tensile strength of at least 25,000 psi and an elongation of at least 5%. The original thickness of the plate is 3 inches. The maximum cold work in each step is 85%. Which of the following procedures would achieve the correct final properties (more than one answer is possible!)? Group of answer choices Hot work from 3 in to 0.7 in; cold work from 0.7 in to 0.3 in Cold work from 3 in to 0.7 in; do an anneal to recrystallize the material; cold work from 0.7 in to 0.3 in Cold work from 3 inches to 0.3 inches Cold work from 3 in to 0.7 in; cold work from 0.7 to 0.5 in; do an anneal to recrystallize the material; cold work from 0.5 in to 0.3 in Hot work from 3 in to 0.5 in; do an anneal to recrystallize the material; hot work from 0.5 to 0.3 in Hot work from 3 in to 0.7 in; do an anneal to recrystallize the material; hot work from 0.7 to 0.3 in Cold work from 3 in to 0.5 in; do an anneal to recrystallize the…arrow_forwardWhich one of the following materials would plastic deformation through twinning be the most likely to occur? O a material with a BCC crystal structure a material with an HCP crystal structure O an amorphous material (no crystal structure) none, twinning does not occur in regular materials Question 2 What is the resolved shear stress in the (111)[110] slip system due to a normal stress of 10 MPa applied in the [010] direction? O -2.31 MPa O -5.35 MPa -4.08 MPa -6.35 MPaarrow_forwardConsider a metal single crystal oriented such that the normal to the slip plane and the slip direction are at angles of 35.5° and 25.4° , respectively, with the tensile axis. If the critical resolved shear stress is 25 MPa, will an applied stress of 30 MPa cause the single crystal to yield? If not, what stress will be necessary? (1)Yes it is enough to yield (2)No it is not enough to yield, 31 Mpa will be enoug (3)No it is not enough to yield, 32 Mpa will be enough (4)No it is not enough to yield, 33 Mpa will be enough (5)No it is too much to yield, 24 Mpa or smaller should it bearrow_forward
- The average grain diameter and yield strength for a brass material were measured as a function of time at 650°C. Given the following yield strengths for the two specimens, compute the heat treatment time required at 650°C to give a yield strength of 100 MPa. Assume a value of 2 for n, the grain diameter exponent. Time (min) 30 90 Yield Strength (MPa) 90 75 min Grain Diameter (mm) 3.9 x 10-2 6.6 x 10-2arrow_forwardHelp me pleasearrow_forward2a: How a material can be mechanically strengthened by designing the grain size after thermomechanical treatments? 2b: How can the extent of cold work be defined? 2c: Specimen A (1008 steel) has an ASTM grain size number of 8 and specimen B (1008 steel) has a grain size number of 4. Which specimen will be having larger grains? A or B 2d: How increasing grain size can play role in decreasing the Toughness? 2e: Is EBSD without using specimen stage tilting is possible?arrow_forward
- (b) The yield stress for a metal changes from 450 Nmm-2to 610 Nmm-2 when the average grain diameter decrease from 0.043 mm to 0.022 mm. Determine the yield stressfor the same metal with an average grain diameter of 0.030 mm.arrow_forwardWhich method do we use to monitor dislocation movements in tensile testing? How monitoring is done in this method, explain the working mechanism of the system in detail.arrow_forwardHelp me pleasearrow_forward
- Help me pleasearrow_forwardQuestions to Consider: 1- What are the drawbacks of the parallel lines method? 2- What is the effect of heat treatment on the average grain size? And what is the influence of the grain size on the mechanical properties of materials 3- Mention another procedure that the inspector can use to determine the average grain size?arrow_forwardA single crystal of aluminum is oriented for a tensile test such that its slip plane normal makes an angle of 28.1° with the tensile axis. Three possible slip directions make angles of 62.4°, 72.0°, and 81.1° with the same tensile axis. (a) Which of these three slip directions is most favored? (b) If plastic deformation begins at a tensile stress of 1.95 MPa (280 psi), determine the critical resolved shear stress for aluminum.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Elements Of ElectromagneticsMechanical EngineeringISBN:9780190698614Author:Sadiku, Matthew N. O.Publisher:Oxford University PressMechanics of Materials (10th Edition)Mechanical EngineeringISBN:9780134319650Author:Russell C. HibbelerPublisher:PEARSONThermodynamics: An Engineering ApproachMechanical EngineeringISBN:9781259822674Author:Yunus A. Cengel Dr., Michael A. BolesPublisher:McGraw-Hill Education
- Control Systems EngineeringMechanical EngineeringISBN:9781118170519Author:Norman S. NisePublisher:WILEYMechanics of Materials (MindTap Course List)Mechanical EngineeringISBN:9781337093347Author:Barry J. Goodno, James M. GerePublisher:Cengage LearningEngineering Mechanics: StaticsMechanical EngineeringISBN:9781118807330Author:James L. Meriam, L. G. Kraige, J. N. BoltonPublisher:WILEY
Elements Of Electromagnetics
Mechanical Engineering
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Oxford University Press
Mechanics of Materials (10th Edition)
Mechanical Engineering
ISBN:9780134319650
Author:Russell C. Hibbeler
Publisher:PEARSON
Thermodynamics: An Engineering Approach
Mechanical Engineering
ISBN:9781259822674
Author:Yunus A. Cengel Dr., Michael A. Boles
Publisher:McGraw-Hill Education
Control Systems Engineering
Mechanical Engineering
ISBN:9781118170519
Author:Norman S. Nise
Publisher:WILEY
Mechanics of Materials (MindTap Course List)
Mechanical Engineering
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Cengage Learning
Engineering Mechanics: Statics
Mechanical Engineering
ISBN:9781118807330
Author:James L. Meriam, L. G. Kraige, J. N. Bolton
Publisher:WILEY
Dislocations and Plastic Deformation; Author: LearnChemE;https://www.youtube.com/watch?v=cpvTwYAUeA8;License: Standard Youtube License