EBK MANUFACTURING PROCESSES FOR ENGINEE
6th Edition
ISBN: 9780134425115
Author: Schmid
Publisher: YUZU
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 6, Problem 6.45Q
To determine
The reason for in hydrostatic extrusion complex seals used between the ram and the container but not between the extrusion and die.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
A cylindrical billet that is 80 mm long and 32 mm diameter is reduced by
backward extrusion to a 12 mm diameter. Half die angle is 90°. If the
Johnson equation has a= 0.8 and b= 1.2 , and the flow curve for the work
material has strength coefficient is 500 MPa, and strain hardening
exponent is 0.8, Determine (a) extrusion ration, (b) true strain, (c)
extrusion strain, (d) ram pressure, and (e) ram force.
During a direct extrusion process for a billet with 5 in long and diameter
2.5 in to 1.6 in. For the work metal, strength coefficient is 75000 Ib/in,
and strain hardening exponent is 0.4, also the die angle of extrusion is
90. In Johnson extrusion strain equation a = 0.8, and b= 1.5. Determine:
(a) extrusion ratio (b) true strain (c) extrusion strain, and (d) ram pressure
at length 5, 4.2, 2.3,1.5,and 0 in.
A 3in long and 1in diameter billet is extruded in a direct extrusion operation with an rx = 4.0. The extrusion has a cross section. The angle of the die (half angle) is 90o. The work metal has a resistance coefficient of 60ksi and a strain hardening exponent of 0.18. Use Johnston's formula with a = 0.8 and b = 1.5 to estimate the extrusion stress. Determine the pressure applied to the end of the billet when the piston moves forward.
Chapter 6 Solutions
EBK MANUFACTURING PROCESSES FOR ENGINEE
Ch. 6 - Prob. 6.1QCh. 6 - Prob. 6.2QCh. 6 - Prob. 6.3QCh. 6 - Prob. 6.4QCh. 6 - Prob. 6.5QCh. 6 - Prob. 6.6QCh. 6 - Prob. 6.7QCh. 6 - Prob. 6.8QCh. 6 - Prob. 6.9QCh. 6 - Prob. 6.10Q
Ch. 6 - Prob. 6.11QCh. 6 - Prob. 6.12QCh. 6 - Prob. 6.13QCh. 6 - Prob. 6.14QCh. 6 - Prob. 6.15QCh. 6 - Prob. 6.16QCh. 6 - Prob. 6.17QCh. 6 - Prob. 6.18QCh. 6 - Prob. 6.19QCh. 6 - Prob. 6.20QCh. 6 - Prob. 6.21QCh. 6 - Prob. 6.22QCh. 6 - Prob. 6.23QCh. 6 - Prob. 6.24QCh. 6 - Prob. 6.25QCh. 6 - Prob. 6.26QCh. 6 - Prob. 6.27QCh. 6 - Prob. 6.28QCh. 6 - Prob. 6.29QCh. 6 - Prob. 6.30QCh. 6 - Prob. 6.31QCh. 6 - Prob. 6.32QCh. 6 - Prob. 6.33QCh. 6 - Prob. 6.34QCh. 6 - Prob. 6.35QCh. 6 - Prob. 6.36QCh. 6 - Prob. 6.37QCh. 6 - Prob. 6.38QCh. 6 - Prob. 6.39QCh. 6 - Prob. 6.40QCh. 6 - Prob. 6.41QCh. 6 - Prob. 6.42QCh. 6 - Prob. 6.43QCh. 6 - Prob. 6.44QCh. 6 - Prob. 6.45QCh. 6 - Prob. 6.46QCh. 6 - Prob. 6.47QCh. 6 - Prob. 6.48QCh. 6 - Prob. 6.49QCh. 6 - Prob. 6.50QCh. 6 - Prob. 6.51QCh. 6 - Prob. 6.52QCh. 6 - Prob. 6.53QCh. 6 - Prob. 6.54QCh. 6 - Prob. 6.55QCh. 6 - Prob. 6.56QCh. 6 - Prob. 6.57QCh. 6 - Prob. 6.58QCh. 6 - Prob. 6.59QCh. 6 - Prob. 6.60QCh. 6 - Prob. 6.61QCh. 6 - Prob. 6.62QCh. 6 - Prob. 6.63QCh. 6 - Prob. 6.64QCh. 6 - Prob. 6.65QCh. 6 - Prob. 6.66QCh. 6 - Prob. 6.67QCh. 6 - Prob. 6.68QCh. 6 - Prob. 6.69QCh. 6 - Prob. 6.70QCh. 6 - Prob. 6.71QCh. 6 - Prob. 6.72QCh. 6 - Prob. 6.73PCh. 6 - Prob. 6.74PCh. 6 - Prob. 6.75PCh. 6 - Prob. 6.76PCh. 6 - Prob. 6.77PCh. 6 - Prob. 6.78PCh. 6 - Prob. 6.79PCh. 6 - Prob. 6.80PCh. 6 - Prob. 6.81PCh. 6 - Prob. 6.82PCh. 6 - Prob. 6.83PCh. 6 - Prob. 6.84PCh. 6 - Prob. 6.85PCh. 6 - Prob. 6.86PCh. 6 - Prob. 6.87PCh. 6 - Prob. 6.88PCh. 6 - Prob. 6.89PCh. 6 - Prob. 6.90PCh. 6 - Prob. 6.91PCh. 6 - Prob. 6.92PCh. 6 - Prob. 6.93PCh. 6 - Prob. 6.94PCh. 6 - Prob. 6.95PCh. 6 - Prob. 6.96PCh. 6 - Prob. 6.97PCh. 6 - Prob. 6.98PCh. 6 - Prob. 6.99PCh. 6 - Prob. 6.100PCh. 6 - Prob. 6.101PCh. 6 - Prob. 6.102PCh. 6 - Prob. 6.103PCh. 6 - Prob. 6.104PCh. 6 - Prob. 6.105PCh. 6 - Prob. 6.106PCh. 6 - Prob. 6.107PCh. 6 - Prob. 6.108PCh. 6 - Prob. 6.109PCh. 6 - Prob. 6.110PCh. 6 - Prob. 6.111PCh. 6 - Prob. 6.112PCh. 6 - Prob. 6.113PCh. 6 - Prob. 6.114PCh. 6 - Prob. 6.115PCh. 6 - Prob. 6.116PCh. 6 - Prob. 6.117PCh. 6 - Prob. 6.118PCh. 6 - Prob. 6.119PCh. 6 - Prob. 6.120PCh. 6 - Prob. 6.121PCh. 6 - Prob. 6.122PCh. 6 - Prob. 6.123PCh. 6 - Prob. 6.124PCh. 6 - Prob. 6.125PCh. 6 - Prob. 6.126PCh. 6 - Prob. 6.127PCh. 6 - Prob. 6.128PCh. 6 - Prob. 6.129PCh. 6 - Prob. 6.130PCh. 6 - Prob. 6.131PCh. 6 - Prob. 6.132PCh. 6 - Prob. 6.133PCh. 6 - Prob. 6.134PCh. 6 - Prob. 6.135PCh. 6 - Prob. 6.136PCh. 6 - Prob. 6.137PCh. 6 - Prob. 6.138PCh. 6 - Prob. 6.139PCh. 6 - Prob. 6.140PCh. 6 - Prob. 6.142DCh. 6 - Prob. 6.143DCh. 6 - Prob. 6.144DCh. 6 - Prob. 6.145DCh. 6 - Prob. 6.146DCh. 6 - Prob. 6.147DCh. 6 - Prob. 6.149D
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.Similar questions
- A direct extrusion operation produces a product with a 20 mm x 60 mm cross sectional area from a brass billet whose diameter = 125 mm and length = 350 mm. The flow curve parameters of the brass are K = 700 MPa and n = 0.35. In the Johnson strain equation, a = 0.7 and b = 1.4. Determine (a) the extrusion ratio, (b) the shape factor, (c) the force required to drive the ram forward during extrusion at the point in the process when the billet length remaining in the container = 300 mm, and (d) the length of the extruded section at the end of the operation if the volume of the butt left in the container is 600,000 mm3arrow_forwardIn open-die forging, a disc of diameter 200 mm and height 60 mm is compressed without any barreling effect. The final diameter of the disc is 400 mm calculate the true strain.arrow_forwardThe process of extrusion is usually described as a semi-continuous operation. Explain it?arrow_forward
- A cylindrical billet that is 100 mm long and 50 mm in diameter is reduced by indirect (backward) extrusion to a 20 mm diameter. The die angle is 90°. In the Johnson equation, a = 0.8 and b = 1.4. In the flow curve for the work metal, the strength coefficient = 800 MPa and strain hardening exponent = 0.13. Determine (a) extrusion ratio, (b) true strain (homogeneous deformation), (c) extrusion strain, (d) ram pressure, and (e) ram force Please answer d and e (a) Calculate the extrusion ratio. r=6.25 (b) Calculate the true strain. εtrue=1.8333 (c) Calculate the extrusion strain by using Johnson's equation. εext =3.366arrow_forwardA cylindrical billet that is 100 mm long and 50 mm in diameter is reduced by indirect (backward) extrusion to a 20 mm diameter. The die angle is 90°. In the Johnson equation, a = 0.8 and b = 1.4. In the flow curve for the work metal, the strength coefficient = 800 MPa and strain hardening exponent = 0.13. Determine (a) extrusion ratio, (b) true strain (homogeneous deformation), (c) extrusion strain, (d) ram pressure, and (e) ram forcearrow_forwardAn open die forging operation is performed to produce a steel cylinder with a diameter of 9.7mm and a height of 1.7mm. The strength coefficient for this steel is 500MPA, and the strain hardening exponent is 0.25. Coefficient of friction at the die-work interface is 0.12. The initial stock of raw material has a diameter of 5mm. (a) What height/length of stock is needed to provide sufficient volume of material for this forging operation? (b) Compute the maximum force that the punch must apply to form the head in this open- die operation.arrow_forward
- A billet 75mmlong and 25mmin diameter is to be extruded in a direct extrusion operation with extrusion ratio rx = 4.0. The extrudate has a round cross section. The die angle (half angle) = 90° The work metal has a strength coefficient = 415 MPa, and strainhardening exponent = 0.18. Use the Johnson formula with a = 0.8 and b = 1.5 to estimate extrusion strain. Determine the pressure applied to the end of the billet as the ram moves forwardarrow_forwardCalculate the ram pressure during indirect extrusion process when a cylindrical billet is 300 mm long and 150 mm in diameter used to produce a 45 mm diameter. In this process: a=0.8, b=1.4, K=275MPA, n=0.12.arrow_forwardA upset forging operation is performed in an open die. The initial size of the workpart is: Do = 63 mm, and ho = 100 mm. The part is upset to a diameter = 70 mm. The work metal has a flow curve with strength coefficient = 600 MPa and strain hardening exponent= 0.22. Coefficient of friction at the die-work interface = 0.40. Determine (a) final height of the part, and (b) maximum force in the operationarrow_forward
- A cylindrical part is warm upset forged in an open die. The initial diameter is 50 mm and the initial height is 40 mm. The height after forging is 30 mm. The coefficient of friction at the die-work interface is 0.25. The yield strength of the work material is 285 MPa, and its flow curve is defined by a strength coefficient of 600 MPa and a strain-hardening exponent of 0.12. Calculate the strain at yield point.arrow_forwardA billet 100 mm long and 30 mm in diameter is to be extruded in a direct extrusion operation with extrusion ratio r, = 3.5. The extrudate has a round cross section. The die angle (half angle) = 60°. The work metal has a strength coefficient = 720 MPa, and strain hardening exponent = 0.17. Use the Johnson formula with a = 0.8 andb= 1.2 to estimate extrusion strain. Determine the following: 1. Diameter of the extrudate = mm 2. Butt volume = mm3 3. Actual extrudate length = mm 4. The pressure applied to perform the extrusion process = MPa 5. Ram force = N.arrow_forwardIn open-die forging, a disc of diameter 200 mm and height 60 mm is compressed without any barreling effect. The final diameter of the disc is 400 mm. The true strain isarrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Elements Of ElectromagneticsMechanical EngineeringISBN:9780190698614Author:Sadiku, Matthew N. O.Publisher:Oxford University PressMechanics of Materials (10th Edition)Mechanical EngineeringISBN:9780134319650Author:Russell C. HibbelerPublisher:PEARSONThermodynamics: An Engineering ApproachMechanical EngineeringISBN:9781259822674Author:Yunus A. Cengel Dr., Michael A. BolesPublisher:McGraw-Hill Education
- Control Systems EngineeringMechanical EngineeringISBN:9781118170519Author:Norman S. NisePublisher:WILEYMechanics of Materials (MindTap Course List)Mechanical EngineeringISBN:9781337093347Author:Barry J. Goodno, James M. GerePublisher:Cengage LearningEngineering Mechanics: StaticsMechanical EngineeringISBN:9781118807330Author:James L. Meriam, L. G. Kraige, J. N. BoltonPublisher:WILEY
Elements Of Electromagnetics
Mechanical Engineering
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Oxford University Press
Mechanics of Materials (10th Edition)
Mechanical Engineering
ISBN:9780134319650
Author:Russell C. Hibbeler
Publisher:PEARSON
Thermodynamics: An Engineering Approach
Mechanical Engineering
ISBN:9781259822674
Author:Yunus A. Cengel Dr., Michael A. Boles
Publisher:McGraw-Hill Education
Control Systems Engineering
Mechanical Engineering
ISBN:9781118170519
Author:Norman S. Nise
Publisher:WILEY
Mechanics of Materials (MindTap Course List)
Mechanical Engineering
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Cengage Learning
Engineering Mechanics: Statics
Mechanical Engineering
ISBN:9781118807330
Author:James L. Meriam, L. G. Kraige, J. N. Bolton
Publisher:WILEY
Types of Manufacturing Process | Manufacturing Processes; Author: Magic Marks;https://www.youtube.com/watch?v=koULXptaBTs;License: Standard Youtube License