EBK MANUFACTURING PROCESSES FOR ENGINEE
6th Edition
ISBN: 9780134425115
Author: Schmid
Publisher: YUZU
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Chapter 6, Problem 6.92P
To determine
The force required for the height to be reduced by
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A force of 1100 KN is applied to punch a 40-mm-diameter hole in a plate. If the shear strength is limited to 700MPa then what thickness of the plate is required?
2. A metal alloy has been tested in a tensile test with the following results for the flow curve
parameters: strength coefficient = 620.5 MPa and strain-hardening exponent 0.26. The
same metal is now tested in a compression test in which the starting height of the specimen
= 62.5 mm and its diameter = 25 mm. Assuming that the cross section increases uniformly,
determine the load required to compress the specimen to a height of (a) 50 mm and (b) 37.5
mm.
3. The starting length of a shaft is 25.00 mm. This shaft is to be inserted into a hole in an
expansion fit assembly operation. To be readily inserted, the shaft must be reduced in length
by cooling. Determine the temperature to which the shaft must be reduced from room
temperature (20° C) in order to reduce its length to 24.98 mm. Refer to the Table below.
Volumetric properties in U.S. customary units for selected engineering materials.
Coefficient of Thermal
Expansion, a
Density, p
Ib/in
Melting Point, T
Material
g/cm
C'x 10
F'x 10 6…
2. The flow curve parameters for a certain stainless steel are strength coefficient = 1100 MPa
and strain-hardening exponent = 0.35. A cylindrical specimen of starting cross-sectional area
= 1000 mm? and height = 75 mm is compressed to a height of 58 mm. Determine the force
required to achieve this compression, assuming that the cross section increases uniformly.
Chapter 6 Solutions
EBK MANUFACTURING PROCESSES FOR ENGINEE
Ch. 6 - Prob. 6.1QCh. 6 - Prob. 6.2QCh. 6 - Prob. 6.3QCh. 6 - Prob. 6.4QCh. 6 - Prob. 6.5QCh. 6 - Prob. 6.6QCh. 6 - Prob. 6.7QCh. 6 - Prob. 6.8QCh. 6 - Prob. 6.9QCh. 6 - Prob. 6.10Q
Ch. 6 - Prob. 6.11QCh. 6 - Prob. 6.12QCh. 6 - Prob. 6.13QCh. 6 - Prob. 6.14QCh. 6 - Prob. 6.15QCh. 6 - Prob. 6.16QCh. 6 - Prob. 6.17QCh. 6 - Prob. 6.18QCh. 6 - Prob. 6.19QCh. 6 - Prob. 6.20QCh. 6 - Prob. 6.21QCh. 6 - Prob. 6.22QCh. 6 - Prob. 6.23QCh. 6 - Prob. 6.24QCh. 6 - Prob. 6.25QCh. 6 - Prob. 6.26QCh. 6 - Prob. 6.27QCh. 6 - Prob. 6.28QCh. 6 - Prob. 6.29QCh. 6 - Prob. 6.30QCh. 6 - Prob. 6.31QCh. 6 - Prob. 6.32QCh. 6 - Prob. 6.33QCh. 6 - Prob. 6.34QCh. 6 - Prob. 6.35QCh. 6 - Prob. 6.36QCh. 6 - Prob. 6.37QCh. 6 - Prob. 6.38QCh. 6 - Prob. 6.39QCh. 6 - Prob. 6.40QCh. 6 - Prob. 6.41QCh. 6 - Prob. 6.42QCh. 6 - Prob. 6.43QCh. 6 - Prob. 6.44QCh. 6 - Prob. 6.45QCh. 6 - Prob. 6.46QCh. 6 - Prob. 6.47QCh. 6 - Prob. 6.48QCh. 6 - Prob. 6.49QCh. 6 - Prob. 6.50QCh. 6 - Prob. 6.51QCh. 6 - Prob. 6.52QCh. 6 - Prob. 6.53QCh. 6 - Prob. 6.54QCh. 6 - Prob. 6.55QCh. 6 - Prob. 6.56QCh. 6 - Prob. 6.57QCh. 6 - Prob. 6.58QCh. 6 - Prob. 6.59QCh. 6 - Prob. 6.60QCh. 6 - Prob. 6.61QCh. 6 - Prob. 6.62QCh. 6 - Prob. 6.63QCh. 6 - Prob. 6.64QCh. 6 - Prob. 6.65QCh. 6 - Prob. 6.66QCh. 6 - Prob. 6.67QCh. 6 - Prob. 6.68QCh. 6 - Prob. 6.69QCh. 6 - Prob. 6.70QCh. 6 - Prob. 6.71QCh. 6 - Prob. 6.72QCh. 6 - Prob. 6.73PCh. 6 - Prob. 6.74PCh. 6 - Prob. 6.75PCh. 6 - Prob. 6.76PCh. 6 - Prob. 6.77PCh. 6 - Prob. 6.78PCh. 6 - Prob. 6.79PCh. 6 - Prob. 6.80PCh. 6 - Prob. 6.81PCh. 6 - Prob. 6.82PCh. 6 - Prob. 6.83PCh. 6 - Prob. 6.84PCh. 6 - Prob. 6.85PCh. 6 - Prob. 6.86PCh. 6 - Prob. 6.87PCh. 6 - Prob. 6.88PCh. 6 - Prob. 6.89PCh. 6 - Prob. 6.90PCh. 6 - Prob. 6.91PCh. 6 - Prob. 6.92PCh. 6 - Prob. 6.93PCh. 6 - Prob. 6.94PCh. 6 - Prob. 6.95PCh. 6 - Prob. 6.96PCh. 6 - Prob. 6.97PCh. 6 - Prob. 6.98PCh. 6 - Prob. 6.99PCh. 6 - Prob. 6.100PCh. 6 - Prob. 6.101PCh. 6 - Prob. 6.102PCh. 6 - Prob. 6.103PCh. 6 - Prob. 6.104PCh. 6 - Prob. 6.105PCh. 6 - Prob. 6.106PCh. 6 - Prob. 6.107PCh. 6 - Prob. 6.108PCh. 6 - Prob. 6.109PCh. 6 - Prob. 6.110PCh. 6 - Prob. 6.111PCh. 6 - Prob. 6.112PCh. 6 - Prob. 6.113PCh. 6 - Prob. 6.114PCh. 6 - Prob. 6.115PCh. 6 - Prob. 6.116PCh. 6 - Prob. 6.117PCh. 6 - Prob. 6.118PCh. 6 - Prob. 6.119PCh. 6 - Prob. 6.120PCh. 6 - Prob. 6.121PCh. 6 - Prob. 6.122PCh. 6 - Prob. 6.123PCh. 6 - Prob. 6.124PCh. 6 - Prob. 6.125PCh. 6 - Prob. 6.126PCh. 6 - Prob. 6.127PCh. 6 - Prob. 6.128PCh. 6 - Prob. 6.129PCh. 6 - Prob. 6.130PCh. 6 - Prob. 6.131PCh. 6 - Prob. 6.132PCh. 6 - Prob. 6.133PCh. 6 - Prob. 6.134PCh. 6 - Prob. 6.135PCh. 6 - Prob. 6.136PCh. 6 - Prob. 6.137PCh. 6 - Prob. 6.138PCh. 6 - Prob. 6.139PCh. 6 - Prob. 6.140PCh. 6 - Prob. 6.142DCh. 6 - Prob. 6.143DCh. 6 - Prob. 6.144DCh. 6 - Prob. 6.145DCh. 6 - Prob. 6.146DCh. 6 - Prob. 6.147DCh. 6 - Prob. 6.149D
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.Similar questions
- 2. A metal alloy has been tested in a tensile test with the following results for the flow curve parameters: strength coefficient = 620.5 MPa and strain-hardening exponent = 0.26. The same metal is now tested in a compression test in which the starting height of the specimen = 62.5 mm and its diameter 25 mm. Assuming that the cross section increases uniformly, determine the load required to compress the specimen to a height of (a) 50 mm and (b) 37.5 mm.arrow_forwardAn Aluminum plate of thickness 5 mm has ultimate strength of 70 GPa. The shear force required by the punching tool to punch a hole of 28 mm diameter isarrow_forwardShear Stress Punch Metal sheet 3. What force is required to punch a 20-mm-diameter hole in a plate that is 25 mm thick? The shear strength of the plate is 350 MN/m².arrow_forward
- Figure shows that a hole must be drilled in a plate with a shear strength of 40 ksi. Compressive stress in the punch is limited to 50 ksi. calculate the thickness maximum of the plate in which a hole of 2.5 inches in diameter can be drilled. The figure is in the attached image.arrow_forwardA wire is drawn through a draw die with an entry angle = 15o. The starting diameter is 0.100 in. And the final diameter = 0.080 in. The coefficient of friction at the work-given interface = 0.07. The metal has a coefficient of resistance K = 30,000 psi and a strain hardening exponent of n = 0.20. Determine the stretching force and the stretching force in this operation.arrow_forwardA strip of metal is originally 5 m long. It is stretched in 3 steps: first to a length of 6 m, then to 7 m and finally to 8 m. The original cross section area of the metal strip is 40 mm?. Compute the final cross section and find the percentage reduction in area due to the above stretching process. Also calculate the force required for the final stage of stretching, assuming that the true stress true strain relation for the material is given as o = 700 0.48 MPa. 5 (c)arrow_forward
- An indirect extrusion operation produces the cross-section shown in Figure 1 (Dimensions in cm) from an aluminum alloy (annealed) billet whose diameter is 300 mm and length of 500 mm. In the Johnson strain equation, a=0.8 and b=1.2 1.1 calculate shape factor of the product 1.2 If the butt left in the container at the end of the stroke is 25 mm thick, what is the (5)length of the extruded section?arrow_forwardIn a slab rolling operation, the maximum thickness reduction (del hmax) is given by del hmax = μ²R, where R is the radius of the roll and u is the coefficient of friction between the roll and the sheet. If µ = 0.1, find the maximum angle subtended by the deformation zone at the centre of the roll.arrow_forwardWrite out the most general expression for shear strain along a single axis resulting from all possible applied stresses, assuming that the material is elastically isotropic.arrow_forward
- A direct extrusion operation the cross section shown in Figure is produced from a copper billet whose diameter 225mm and length = 500 mm. In the flow curve for copper, the strength coefficient = 400 MPa and strain hardening exponent = 0.30. In the Johnson strain equation, a = 0.8 and b = 1.5. Determine: 1. The extrusion ratio, 2. The shape factor, 3. The force required to drive the ram forward during extrusion at the point in the process when the billet length remaining in the container = 325 mm ,4.The length of the extruded section at the end of the operation if the volume of the butt left in the container is 225,000 mm3. * 100arrow_forwardSketch a tensile member with (a) a rectangular crosssection, (b) a solid circular cross section, and (c) a circulartubecross section, and label the dimensions symbolically (e.g.,label the radius for the solid circular case). For each member, write out the definition of engineering stress in terms of the actual dimensions of the component. If therectangular member has dimensions of width and thicknessequal to 1 cm 0.3 cm, what would be the radius of a solidcircular member such that the stress is equal for an equaltensile load? If a tube has an outer radius equal to that ofthis same solid cylinder, what is the maximum inner radiussuch that the stress does not exceed 200% of the stress inthe solid cylinder?arrow_forwardTwo high rolling mill setup has been used to reduce the thickness of a plate from 40 mm at the maximum draft per pass to become 34 mm after the last pass. The width of the rolled material is 560 mm and the roll diameter is 560 mm. The material has a strength coefficient of 260 MPa and a strain hardening exponent of 0.18. The coefficient of friction during the process was 0.085. Determine the following: 1- Number of passes required to perform the reduction process = 2- Strain of the last pass = 3- Average flow stress of the last pass = MPa 4- The rolling force to roll the last pass =arrow_forward
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