Concept explainers
The work done will be same for two specimens.
Answer to Problem 6.86P
The work done associated with specimen A and specimen B is not same.
Explanation of Solution
Given:
The height of the specimen A is
The cross section of the specimen A is
The height of the specimen B is
The cross section of the specimen B is
The flash thickness is
The largest strain in finishing forging is
Formula used:
The expression for the work done is given as,
Here,
The expression for the force is given as,
Here,
The expression for the average pressure is given as,
Here,
The expression for volume is given as,
Calculation:
Tre expression of specimen A radius from equation (4) can be calculated as,
Now from equation (3) and (5),
Substitute equation (6) in equation (2),
Substitute equation (7) in equation (1),
Work done by the specimen A can be calculated as,
Substitute
Work done by the specimen B can be calculated as,
Substitute
Conclusion:
Therefore, work done associated with specimen A and specimen B is not same.
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Chapter 6 Solutions
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