EBK MANUFACTURING PROCESSES FOR ENGINEE
6th Edition
ISBN: 9780134425115
Author: Schmid
Publisher: YUZU
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Question
Chapter 6, Problem 6.46Q
(a)
To determine
The defects in extrusion.
(b)
To determine
The defects in drawing.
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A cylindrical billet that is 80 mm long and 32 mm diameter is reduced by
backward extrusion to a 12 mm diameter. Half die angle is 90°. If the
Johnson equation has a= 0.8 and b= 1.2 , and the flow curve for the work
material has strength coefficient is 500 MPa, and strain hardening
exponent is 0.8, Determine (a) extrusion ration, (b) true strain, (c)
extrusion strain, (d) ram pressure, and (e) ram force.
1. A cylindrical billet that is 100 mm long and 50 mm in diameter is reduced by direct (forward)
extrusion to a 20 mm diameter. The die angle is 90°. the flow curve for the work metal has a
strength coefficient of 800 MPa. Determine (a) extrusion ratio, (b) true strain (homogeneous
deformation), (c) ram pressure, and (e) ram force.
Describe the effect that extrusion has on material properties with examples
Chapter 6 Solutions
EBK MANUFACTURING PROCESSES FOR ENGINEE
Ch. 6 - Prob. 6.1QCh. 6 - Prob. 6.2QCh. 6 - Prob. 6.3QCh. 6 - Prob. 6.4QCh. 6 - Prob. 6.5QCh. 6 - Prob. 6.6QCh. 6 - Prob. 6.7QCh. 6 - Prob. 6.8QCh. 6 - Prob. 6.9QCh. 6 - Prob. 6.10Q
Ch. 6 - Prob. 6.11QCh. 6 - Prob. 6.12QCh. 6 - Prob. 6.13QCh. 6 - Prob. 6.14QCh. 6 - Prob. 6.15QCh. 6 - Prob. 6.16QCh. 6 - Prob. 6.17QCh. 6 - Prob. 6.18QCh. 6 - Prob. 6.19QCh. 6 - Prob. 6.20QCh. 6 - Prob. 6.21QCh. 6 - Prob. 6.22QCh. 6 - Prob. 6.23QCh. 6 - Prob. 6.24QCh. 6 - Prob. 6.25QCh. 6 - Prob. 6.26QCh. 6 - Prob. 6.27QCh. 6 - Prob. 6.28QCh. 6 - Prob. 6.29QCh. 6 - Prob. 6.30QCh. 6 - Prob. 6.31QCh. 6 - Prob. 6.32QCh. 6 - Prob. 6.33QCh. 6 - Prob. 6.34QCh. 6 - Prob. 6.35QCh. 6 - Prob. 6.36QCh. 6 - Prob. 6.37QCh. 6 - Prob. 6.38QCh. 6 - Prob. 6.39QCh. 6 - Prob. 6.40QCh. 6 - Prob. 6.41QCh. 6 - Prob. 6.42QCh. 6 - Prob. 6.43QCh. 6 - Prob. 6.44QCh. 6 - Prob. 6.45QCh. 6 - Prob. 6.46QCh. 6 - Prob. 6.47QCh. 6 - Prob. 6.48QCh. 6 - Prob. 6.49QCh. 6 - Prob. 6.50QCh. 6 - Prob. 6.51QCh. 6 - Prob. 6.52QCh. 6 - Prob. 6.53QCh. 6 - Prob. 6.54QCh. 6 - Prob. 6.55QCh. 6 - Prob. 6.56QCh. 6 - Prob. 6.57QCh. 6 - Prob. 6.58QCh. 6 - Prob. 6.59QCh. 6 - Prob. 6.60QCh. 6 - Prob. 6.61QCh. 6 - Prob. 6.62QCh. 6 - Prob. 6.63QCh. 6 - Prob. 6.64QCh. 6 - Prob. 6.65QCh. 6 - Prob. 6.66QCh. 6 - Prob. 6.67QCh. 6 - Prob. 6.68QCh. 6 - Prob. 6.69QCh. 6 - Prob. 6.70QCh. 6 - Prob. 6.71QCh. 6 - Prob. 6.72QCh. 6 - Prob. 6.73PCh. 6 - Prob. 6.74PCh. 6 - Prob. 6.75PCh. 6 - Prob. 6.76PCh. 6 - Prob. 6.77PCh. 6 - Prob. 6.78PCh. 6 - Prob. 6.79PCh. 6 - Prob. 6.80PCh. 6 - Prob. 6.81PCh. 6 - Prob. 6.82PCh. 6 - Prob. 6.83PCh. 6 - Prob. 6.84PCh. 6 - Prob. 6.85PCh. 6 - Prob. 6.86PCh. 6 - Prob. 6.87PCh. 6 - Prob. 6.88PCh. 6 - Prob. 6.89PCh. 6 - Prob. 6.90PCh. 6 - Prob. 6.91PCh. 6 - Prob. 6.92PCh. 6 - Prob. 6.93PCh. 6 - Prob. 6.94PCh. 6 - Prob. 6.95PCh. 6 - Prob. 6.96PCh. 6 - Prob. 6.97PCh. 6 - Prob. 6.98PCh. 6 - Prob. 6.99PCh. 6 - Prob. 6.100PCh. 6 - Prob. 6.101PCh. 6 - Prob. 6.102PCh. 6 - Prob. 6.103PCh. 6 - Prob. 6.104PCh. 6 - Prob. 6.105PCh. 6 - Prob. 6.106PCh. 6 - Prob. 6.107PCh. 6 - Prob. 6.108PCh. 6 - Prob. 6.109PCh. 6 - Prob. 6.110PCh. 6 - Prob. 6.111PCh. 6 - Prob. 6.112PCh. 6 - Prob. 6.113PCh. 6 - Prob. 6.114PCh. 6 - Prob. 6.115PCh. 6 - Prob. 6.116PCh. 6 - Prob. 6.117PCh. 6 - Prob. 6.118PCh. 6 - Prob. 6.119PCh. 6 - Prob. 6.120PCh. 6 - Prob. 6.121PCh. 6 - Prob. 6.122PCh. 6 - Prob. 6.123PCh. 6 - Prob. 6.124PCh. 6 - Prob. 6.125PCh. 6 - Prob. 6.126PCh. 6 - Prob. 6.127PCh. 6 - Prob. 6.128PCh. 6 - Prob. 6.129PCh. 6 - Prob. 6.130PCh. 6 - Prob. 6.131PCh. 6 - Prob. 6.132PCh. 6 - Prob. 6.133PCh. 6 - Prob. 6.134PCh. 6 - Prob. 6.135PCh. 6 - Prob. 6.136PCh. 6 - Prob. 6.137PCh. 6 - Prob. 6.138PCh. 6 - Prob. 6.139PCh. 6 - Prob. 6.140PCh. 6 - Prob. 6.142DCh. 6 - Prob. 6.143DCh. 6 - Prob. 6.144DCh. 6 - Prob. 6.145DCh. 6 - Prob. 6.146DCh. 6 - Prob. 6.147DCh. 6 - Prob. 6.149D
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.Similar questions
- Forging processes may be characterized by die work limitation. This categorization yields three basic types.arrow_forwardA cylindrical billet that is 100 mm long and 50 mm in diameter is reduced by indirect (backward) extrusion to a 20 mm diameter. The die angle is 90°. In the Johnson equation, a = 0.8 and b = 1.4. In the flow curve for the work metal, the strength coefficient = 800 MPa and strain hardening exponent = 0.13. Determine (a) extrusion ratio, (b) true strain (homogeneous deformation), (c) extrusion strain, (d) ram pressure, and (e) ram forcearrow_forwardA cylindrical billet that is 100 mm long and 50 mm in diameter is reduced by indirect (backward) extrusion to a 20 mm diameter. The die angle is 90°. In the Johnson equation, a = 0.8 and b = 1.4. In the flow curve for the work metal, the strength coefficient = 800 MPa and strain hardening exponent = 0.13. Determine (a) extrusion ratio, (b) true strain (homogeneous deformation), (c) extrusion strain, (d) ram pressure, and (e) ram force Please answer d and e (a) Calculate the extrusion ratio. r=6.25 (b) Calculate the true strain. εtrue=1.8333 (c) Calculate the extrusion strain by using Johnson's equation. εext =3.366arrow_forward
- A billet 100 mm long and 40 mm diameter is to be extruded in a direct extrusion with final diameter of product 32 mm. The semi die angle is 60°. The work metal has a strength coefficient 500 Map, and strain hardening 0.2 use the Johnson formula with a=0.8 and b=1.45 to estimate the extrusion strain. Determine the pressure applied to the end of the billet as the ram moves forward.arrow_forwardA deep drawing operation for a cup is performed in which the inside diameter = 60 mm %3D and the height = 50 mm. The blank thickness = 3 mm, and %3D %3D the starting blank diameter = 108 mm. Punch and die radii = %3D 4 mm. Tensile strength = 400 MPa and yield strength = 180 %3D MPa for this sheet metal. Determine (a) drawing ratio, (b) reduction, (c) drawing force, and (d) blankholder force. *arrow_forwardWrite down what you know about extrusion defects or rolling defectsarrow_forward
- During a direct extrusion process for a billet with 5 in long and diameter 2.5 in to 1.6 in. For the work metal, strength coefficient is 75000 Ib/in, and strain hardening exponent is 0.4, also the die angle of extrusion is 90. In Johnson extrusion strain equation a = 0.8, and b= 1.5. Determine: (a) extrusion ratio (b) true strain (c) extrusion strain, and (d) ram pressure at length 5, 4.2, 2.3,1.5,and 0 in.arrow_forward4) Make a summary of the types of defects found in sheet-metal forming processes, and include brief comments on the reason(s) for each defect.arrow_forwardYou have been asked to work on some design problems and technically support the team working on extrusion and forging operations: 1) The team are extruding a billet that is 80 mm long with diameter of 40 mm is directly to a diameter of 20 mm. The extrusion die has a die angle of 75°, see Figure 1. For the work metal, K = 600 MPa and n = 0.25. In the Johnson extrusion strain equation, a = 0.8 and b = 1.4. Remaining billet length 75 Ram pressure, p D. Dr Figure 1: Extrusion process. Determine the following design parameters: (a) Extrusion ratio. (b) True strain (homogeneous deformation). (c) Extrusion strain. (d) Ram pressure at L= 80, 40, and 10 mm. (e) Draw the relationship between the ram pressure and billet length and discuss the results. What are your recommendations to dccrcase the required ram pressure?arrow_forward
- With a neat diagram differentiate the direct and indirect extrusion process. Write any two advantages and applications of extrusion.arrow_forward1) A upset forging operation is performed in an open die. The initial size of the workpart is: Do = 63 mm, and ho = 100 mm. The part is upset to a diameter = 70 mm. The work metal has a flow curve with strength coefficient = 600 MPa and strain hardening exponent= 0.22. Coefficient of friction at the die-work interface = 0.40. Determine (a) final height of the part, and (b) maximum force in the operation.arrow_forwardIllustrate the advantages of direct extrusion on indirect extrusion?arrow_forward
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