EBK MANUFACTURING PROCESSES FOR ENGINEE
6th Edition
ISBN: 9780134425115
Author: Schmid
Publisher: YUZU
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Chapter 6, Problem 6.43Q
To determine
Process of making stepped extrusion.
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Illustrate the advantages of direct extrusion on indirect extrusion?
With a neat diagram differentiate the direct and indirect extrusion process. Write any two advantages and applications of extrusion.
A billet 100 mm long and 40 mm diameter is to be extruded in a direct extrusion with
final diameter of product 32 mm. The semi die angle is 60°. The work metal has a
strength coefficient 500 Map, and strain hardening 0.2 use the Johnson formula with
a=0.8 and b=1.45 to estimate the extrusion strain. Determine the pressure applied to
the end of the billet as the ram moves forward.
Chapter 6 Solutions
EBK MANUFACTURING PROCESSES FOR ENGINEE
Ch. 6 - Prob. 6.1QCh. 6 - Prob. 6.2QCh. 6 - Prob. 6.3QCh. 6 - Prob. 6.4QCh. 6 - Prob. 6.5QCh. 6 - Prob. 6.6QCh. 6 - Prob. 6.7QCh. 6 - Prob. 6.8QCh. 6 - Prob. 6.9QCh. 6 - Prob. 6.10Q
Ch. 6 - Prob. 6.11QCh. 6 - Prob. 6.12QCh. 6 - Prob. 6.13QCh. 6 - Prob. 6.14QCh. 6 - Prob. 6.15QCh. 6 - Prob. 6.16QCh. 6 - Prob. 6.17QCh. 6 - Prob. 6.18QCh. 6 - Prob. 6.19QCh. 6 - Prob. 6.20QCh. 6 - Prob. 6.21QCh. 6 - Prob. 6.22QCh. 6 - Prob. 6.23QCh. 6 - Prob. 6.24QCh. 6 - Prob. 6.25QCh. 6 - Prob. 6.26QCh. 6 - Prob. 6.27QCh. 6 - Prob. 6.28QCh. 6 - Prob. 6.29QCh. 6 - Prob. 6.30QCh. 6 - Prob. 6.31QCh. 6 - Prob. 6.32QCh. 6 - Prob. 6.33QCh. 6 - Prob. 6.34QCh. 6 - Prob. 6.35QCh. 6 - Prob. 6.36QCh. 6 - Prob. 6.37QCh. 6 - Prob. 6.38QCh. 6 - Prob. 6.39QCh. 6 - Prob. 6.40QCh. 6 - Prob. 6.41QCh. 6 - Prob. 6.42QCh. 6 - Prob. 6.43QCh. 6 - Prob. 6.44QCh. 6 - Prob. 6.45QCh. 6 - Prob. 6.46QCh. 6 - Prob. 6.47QCh. 6 - Prob. 6.48QCh. 6 - Prob. 6.49QCh. 6 - Prob. 6.50QCh. 6 - Prob. 6.51QCh. 6 - Prob. 6.52QCh. 6 - Prob. 6.53QCh. 6 - Prob. 6.54QCh. 6 - Prob. 6.55QCh. 6 - Prob. 6.56QCh. 6 - Prob. 6.57QCh. 6 - Prob. 6.58QCh. 6 - Prob. 6.59QCh. 6 - Prob. 6.60QCh. 6 - Prob. 6.61QCh. 6 - Prob. 6.62QCh. 6 - Prob. 6.63QCh. 6 - Prob. 6.64QCh. 6 - Prob. 6.65QCh. 6 - Prob. 6.66QCh. 6 - Prob. 6.67QCh. 6 - Prob. 6.68QCh. 6 - Prob. 6.69QCh. 6 - Prob. 6.70QCh. 6 - Prob. 6.71QCh. 6 - Prob. 6.72QCh. 6 - Prob. 6.73PCh. 6 - Prob. 6.74PCh. 6 - Prob. 6.75PCh. 6 - Prob. 6.76PCh. 6 - Prob. 6.77PCh. 6 - Prob. 6.78PCh. 6 - Prob. 6.79PCh. 6 - Prob. 6.80PCh. 6 - Prob. 6.81PCh. 6 - Prob. 6.82PCh. 6 - Prob. 6.83PCh. 6 - Prob. 6.84PCh. 6 - Prob. 6.85PCh. 6 - Prob. 6.86PCh. 6 - Prob. 6.87PCh. 6 - Prob. 6.88PCh. 6 - Prob. 6.89PCh. 6 - Prob. 6.90PCh. 6 - Prob. 6.91PCh. 6 - Prob. 6.92PCh. 6 - Prob. 6.93PCh. 6 - Prob. 6.94PCh. 6 - Prob. 6.95PCh. 6 - Prob. 6.96PCh. 6 - Prob. 6.97PCh. 6 - Prob. 6.98PCh. 6 - Prob. 6.99PCh. 6 - Prob. 6.100PCh. 6 - Prob. 6.101PCh. 6 - Prob. 6.102PCh. 6 - Prob. 6.103PCh. 6 - Prob. 6.104PCh. 6 - Prob. 6.105PCh. 6 - Prob. 6.106PCh. 6 - Prob. 6.107PCh. 6 - Prob. 6.108PCh. 6 - Prob. 6.109PCh. 6 - Prob. 6.110PCh. 6 - Prob. 6.111PCh. 6 - Prob. 6.112PCh. 6 - Prob. 6.113PCh. 6 - Prob. 6.114PCh. 6 - Prob. 6.115PCh. 6 - Prob. 6.116PCh. 6 - Prob. 6.117PCh. 6 - Prob. 6.118PCh. 6 - Prob. 6.119PCh. 6 - Prob. 6.120PCh. 6 - Prob. 6.121PCh. 6 - Prob. 6.122PCh. 6 - Prob. 6.123PCh. 6 - Prob. 6.124PCh. 6 - Prob. 6.125PCh. 6 - Prob. 6.126PCh. 6 - Prob. 6.127PCh. 6 - Prob. 6.128PCh. 6 - Prob. 6.129PCh. 6 - Prob. 6.130PCh. 6 - Prob. 6.131PCh. 6 - Prob. 6.132PCh. 6 - Prob. 6.133PCh. 6 - Prob. 6.134PCh. 6 - Prob. 6.135PCh. 6 - Prob. 6.136PCh. 6 - Prob. 6.137PCh. 6 - Prob. 6.138PCh. 6 - Prob. 6.139PCh. 6 - Prob. 6.140PCh. 6 - Prob. 6.142DCh. 6 - Prob. 6.143DCh. 6 - Prob. 6.144DCh. 6 - Prob. 6.145DCh. 6 - Prob. 6.146DCh. 6 - Prob. 6.147DCh. 6 - Prob. 6.149D
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.Similar questions
- A cylindrical billet that is 100 mm long and 50 mm in diameter is reduced by indirect (backward) extrusion to a 20 mm diameter. The die angle is 90°. In the Johnson equation, a = 0.8 and b = 1.4. In the flow curve for the work metal, the strength coefficient = 800 MPa and strain hardening exponent = 0.13. Determine (a) extrusion ratio, (b) true strain (homogeneous deformation), (c) extrusion strain, (d) ram pressure, and (e) ram forcearrow_forwardA cylindrical billet that is 100 mm long and 50 mm in diameter is reduced by indirect (backward) extrusion to a 20 mm diameter. The die angle is 90°. In the Johnson equation, a = 0.8 and b = 1.4. In the flow curve for the work metal, the strength coefficient = 800 MPa and strain hardening exponent = 0.13. Determine (a) extrusion ratio, (b) true strain (homogeneous deformation), (c) extrusion strain, (d) ram pressure, and (e) ram force Please answer d and e (a) Calculate the extrusion ratio. r=6.25 (b) Calculate the true strain. εtrue=1.8333 (c) Calculate the extrusion strain by using Johnson's equation. εext =3.366arrow_forwardA cylindrical billet that is 80 mm long and 32 mm diameter is reduced by backward extrusion to a 12 mm diameter. Half die angle is 90°. If the Johnson equation has a= 0.8 and b= 1.2 , and the flow curve for the work material has strength coefficient is 500 MPa, and strain hardening exponent is 0.8, Determine (a) extrusion ration, (b) true strain, (c) extrusion strain, (d) ram pressure, and (e) ram force.arrow_forward
- Describe the effect that extrusion has on material properties with examplesarrow_forwardWhat are the advantages and limitations of extrusion process?arrow_forwardA cylindrical billet that is 100 mm long and 50 mm in diameter is reduced by indirect (backward) extrusion to a 20 mm diameter. The die angle is 90°. In the Johnson equation, a = 0.8 and b = 1.4. In the flow curve for the work metal, the strength coefficient = 800 MPa and strain hardening exponent = 0.13. Determine d) ram pressure, and (e) ram forcearrow_forward
- Why are hot rolled products normally available only in standard sizes and shapes? Why the friction between tool and work-piece is not an undesirable feature in hot rolling? Why might small-diameter rolls be desired when rolling thin products?arrow_forwardAn open die forging operation is performed to produce a steel cylinder with a diameter of 9.7mm and a height of 1.7mm. The strength coefficient for this steel is 500MPA, and the strain hardening exponent is 0.25. Coefficient of friction at the die-work interface is 0.12. The initial stock of raw material has a diameter of 5mm. (a) What height/length of stock is needed to provide sufficient volume of material for this forging operation? (b) Compute the maximum force that the punch must apply to form the head in this open- die operation.arrow_forwardWhat are the advantages of a counterblow or impact forging machine? What are some of the properties desired in forging dies?arrow_forward
- You have been asked to work on some design problems and technically support the team working on extrusion and forging operations: 1) The team are extruding a billet that is 80 mm long with diameter of 40 mm is directly to a diameter of 20 mm. The extrusion die has a die angle of 75°, see Figure 1. For the work metal, K = 600 MPa and n = 0.25. In the Johnson extrusion strain equation, a = 0.8 and b = 1.4. Remaining billet length 75 Ram pressure, p D. Dr Figure 1: Extrusion process. Determine the following design parameters: (a) Extrusion ratio. (b) True strain (homogeneous deformation). (c) Extrusion strain. (d) Ram pressure at L= 80, 40, and 10 mm. (e) Draw the relationship between the ram pressure and billet length and discuss the results. What are your recommendations to dccrcase the required ram pressure?arrow_forward1. A cylindrical billet that is 100 mm long and 50 mm in diameter is reduced by direct (forward) extrusion to a 20 mm diameter. The die angle is 90°. the flow curve for the work metal has a strength coefficient of 800 MPa. Determine (a) extrusion ratio, (b) true strain (homogeneous deformation), (c) ram pressure, and (e) ram force.arrow_forwardThe process of extrusion is usually described as a semi-continuous operation. Explain it?arrow_forward
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