Chapter 23.2, Problem 13LC

a.

Interpretation Introduction

Interpretation: To write the IUPAC names and the common names for the given compounds.

Concept Introduction: The nomenclature is generally based on the parent alkane chain which is the longest chain containing the hydroxyl group. The suffix for alcohols is “-ol”. Number the parent chain in such a way that the hydroxyl group will get the lowest number and then name the substituents if any along with the number of the carbon to which the substituent is attached. Finally, write the IUPAC name of the alcohol with the suffix “ol”

Answer to Problem 13LC

  

Explanation of Solution

In butan-2-ol the longest chain is made up of four carbons and the OH group is attached to the second carbon. The substituent is named first and then the longest carbon chain and then the suffix of the alcohol group. Therefore, in this case, the name is butan-2-ol.

b.

Interpretation Introduction

Interpretation: To write the IUPAC names and the common names for the given compounds.

Concept Introduction: The nomenclature is generally based on the parent alkane chain which is the longest chain containing the amine group. The suffix for amines will be ‘amine.’ Number the alky chain in such a way that amine will get the lowest number and then name the substituent if any along with the number of the carbon to which the substituent is attached. Finally, write the IUPAC name of the amine with the suffix ‘amine’

Answer to Problem 13LC

  

Explanation of Solution

In propan-1-amine the longest carbon chain is made up of three carbons and the amine is attached to the first carbon. The substituent is named first and then the longest carbon chain and then the suffix of the amine group. Therefore, in this case, the name is Propan-1-amine.

c.

Interpretation Introduction

Interpretation: To write the IUPAC names and the common names for the given compounds.

Concept Introduction: The alkyl groups and the aryl group that is attached on either side of the oxygen are named alphabetically by adding ether at the end. The substituent group with a greater number of carbons is considered as parent hydrocarbon and the other substituent group attached to the same oxygen is named using the prefix ‘oxy’.

Answer to Problem 13LC

  

Explanation of Solution

In 1-propoxybutane the longest carbon chain is made up of four carbons which is butane and the other substituent has three carbons which is propane. The substituent is named first and then the longest chain with oxy as a prefix. Therefore, the name is 1-propoxybutane.