Chapter 23, Problem 52A

a)

Interpretation Introduction

Interpretation: To draw the structural formula for the products of the reactions given.

Concept Introduction: Addition reactions are those types of reactions in which two or more molecules join together to form a larger molecule. These types of reactions will form additive products.

Answer to Problem 52A

  

The name of the given structure is 1,2-dichlorobutane.

Explanation of Solution

In the given reaction, the double bond break and the bond between the chlorine molecule. The double bond of the butene breaks and the bond between the chlorine break generating the chloride atom. The chlorine will attack the butene which results in the formation of 1,2-dichlorobutane.

b)

Interpretation Introduction

Interpretation: To draw the structural formula for the products of the reactions given.

Concept Introduction: Addition reactions are those types of reactions in which two or more molecules join together to form a larger molecule. These types of reactions will form additive products.

Answer to Problem 52A

  

Explanation of Solution

In the given reaction, the double bond break and the bond between the bromine molecule. The double bond of the butene breaks and the bond between the bromine break generate the bromide ion. The bromine will attack the butene which results in the formation of 1,2-dibromoobutane.

c)

Interpretation Introduction

Interpretation: To draw the structural formula for the products of the reactions given.

Concept Introduction: Addition reactions are those types of reactions in which two or more molecules join together to form a larger molecule. These types of reactions will form additive products.

Answer to Problem 52A

  

Explanation of Solution

In this reaction, the HBr will add the following anti-Markovnikov’s rule. This reaction will take place in the presence of peroxide which results in the free radical mechanism and initiate the reaction and add bromine radical. This mechanism results in the product which is Bromo cyclohexane in this case.