Chapter 23, Problem 80A

Interpretation Introduction

Interpretation: To determine the mass of one liter of ${\text{SO}}_{\text{2}}$ in grams at standard temperature and pressure.

Concept Introduction: Standard temperature and pressure describe the temperature and pressure at standard conditions. The standard temperature is 273K and the standard pressure is 1 atm. This STP condition is used to represent a standard set of conditions for the experimental values that are to be established and allow comparisons between two different data sets.

Answer to Problem 80A

The mass of ${\text{SO}}_{\text{2}}$ required is 2.86 grams.

Explanation of Solution

At standard temperature and pressure conditions, 1 mole of any gas will occupy 22.4L.

The mass of 1 mole of SO₂ is 64 grams

For 1L solution, the mass of SO₂ will be

  $\text{1L}\times \frac{{\text{1moleSO}}_{\text{2}}}{\text{22}\text{.4L}}\times \frac{{\text{64gSO}}_{\text{2}}}{{\text{1moleSO}}_{\text{2}}}$

Therefore, 1L solution will contain 2.8571 grams of ${\text{SO}}_{\text{2}}$ which is approximately equal to 2.86 grams.

Conclusion

The mass required is calculated by considering the standard conditions. The mass is rounded-off to three significant figures which are given 2.86 grams of ${\text{SO}}_{\text{2}}$ .