Chapter 22, Problem 99A

a.

Interpretation Introduction

Interpretation: To write the equilibrium constant for the given reaction.

Concept Introduction: At equilibrium, the ratio of the concentration of the products to the concentration of reactants is defined as the equilibrium constant.

Answer to Problem 99A

The equilibrium constant expression is depicted as follows:

  $K_{\text{eq}}=\frac{{\left[\text{ICl}\right]}^2}{\left[{\text{Cl}}_2\right]\left[{\text{I}}_2\right]}$

Explanation of Solution

The given chemical equation is depicted as follows:

  ${\text{Cl}}_2\left(g\right)+{\text{I}}_2\left(g\right)\rightleftharpoons 2\text{ ICl}\left(g\right)$

The equilibrium constant for the above reaction is represented as follows:

  $K_{\text{eq}}=\frac{{\left[\text{ICl}\right]}^2}{\left[{\text{Cl}}_2\right]\left[{\text{I}}_2\right]}$

b.

Interpretation Introduction

Interpretation: To write the equilibrium constant for the given reaction.

Concept Introduction: At equilibrium, the ratio of the concentration of the products to the concentration of reactants is defined as the equilibrium constant.

Answer to Problem 99A

The equilibrium constant expression is depicted as follows:

  $K_{\text{eq}}=\frac{\left[{\text{H}}_2\right]\left[{\text{Br}}_2\right]}{{\left[\text{HBr}\right]}^2}$

Explanation of Solution

The given chemical equation is depicted as follows:

  $\text{2 HBr}\left(g\right)\rightleftharpoons {\text{H}}_2\left(g\right)+{\text{Br}}_2\left(g\right)$

The equilibrium constant for the above reaction is represented as follows:

  $K_{\text{eq}}=\frac{\left[{\text{H}}_2\right]\left[{\text{Br}}_2\right]}{{\left[\text{HBr}\right]}^2}$

c.

Interpretation Introduction

Interpretation: To write the equilibrium constant for the given reaction.

Concept Introduction: At equilibrium, the ratio of the concentration of the products to the concentration of reactants is defined as the equilibrium constant.

Answer to Problem 99A

The equilibrium constant expression is depicted as follows:

  $K_{\text{eq}}=\frac{{\left[\text{HCl}\right]}^4{\left[\text{S}\right]}^3\left[{\text{SO}}_2\right]}{{\left[{\text{S}}_2{\text{Cl}}_2\right]}^2{\left[{\text{H}}_2\text{O}\right]}^2}$

Explanation of Solution

The given chemical equation is depicted as follows:

  ${\text{2 S}}_2{\text{Cl}}_2\left(g\right)+2{\text{ H}}_2\text{O}\rightleftharpoons 4\text{ HCl}\left(g\right)+3\text{ S}\left(g\right)+{\text{ SO}}_2\left(g\right)$

The equilibrium constant for the above reaction is represented as follows:

  $K_{\text{eq}}=\frac{{\left[\text{HCl}\right]}^4{\left[\text{S}\right]}^3\left[{\text{SO}}_2\right]}{{\left[{\text{S}}_2{\text{Cl}}_2\right]}^2{\left[{\text{H}}_2\text{O}\right]}^2}$

d.

Interpretation Introduction

Interpretation: To write the equilibrium constant for the given reaction.

Concept Introduction: At equilibrium, the ratio of the concentration of the products to the concentration of reactants is defined as the equilibrium constant.

Answer to Problem 99A

The equilibrium constant expression is depicted as follows:

  $K_{\text{eq}}=\frac{{\left[{\text{NH}}_3\right]}^2}{\left[{\text{N}}_2\right]{\left[{\text{H}}_2\right]}^3}$

Explanation of Solution

The given chemical equation is depicted as follows:

  ${\text{N}}_2\left(g\right)+3{\text{H}}_2\left(g\right)\rightleftharpoons 2{\text{ NH}}_3\left(g\right)$

The equilibrium constant for the above reaction is represented as follows:

  $K_{\text{eq}}=\frac{{\left[{\text{NH}}_3\right]}^2}{\left[{\text{N}}_2\right]{\left[{\text{H}}_2\right]}^3}$