Chemistry 2012 Student Edition (hard Cover) Grade 11
Chemistry 2012 Student Edition (hard Cover) Grade 11
12th Edition
ISBN: 9780132525763
Author: Prentice Hall
Publisher: Prentice Hall
Question
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Chapter 22, Problem 71A

(a)

Interpretation Introduction

Interpretation: The primary carbon needs to be identified.

Concept Concept Introduction-

Carbon atoms can be classified on the basis of carbon attached to them as:

  1. Primary carbon: When only one carbon atom attached to it. Remaining all the bonds attached to hydrogen
  2. Secondary carbon: When a carbon atom is attached to two carbon atoms and remaining two are hydrogen atoms.
  3. Tertiary carbon: When carbon is attached to 3 carbon atoms and one hydrogen atom.
  4. Quaternary carbon: When carbon atom is attached to four carbon atoms and no hydrogen atom.

(a)

Expert Solution
Check Mark

Explanation of Solution

In the given molecule,

  Chemistry 2012 Student Edition (hard Cover) Grade 11, Chapter 22, Problem 71A , additional homework tip  1

Carbon atom labelled as 4 is attached to one carbon and three hydrogen atoms. Hence it is a primary carbon.

(b)

Interpretation Introduction

Interpretation- To identify the secondary carbon.

Concept Introduction-

Carbon atoms can be classified on the basis of carbon attached to them as:

  1. Primary carbon: When only one carbon atom attached to it. Remaining all the bonds attached to hydrogen.
  2. Secondary carbon: When carbon atoms is attached to carbon two carbon and remaining two are hydrogen atoms.
  3. Tertiary carbon: When carbon is attached to 3 carbon atoms and one hydrogen atom.
  4. Quaternary carbon: When carbon atom is attached to four carbon atoms and no hydrogen atom.

(b)

Expert Solution
Check Mark

Explanation of Solution

In the given molecule,

  Chemistry 2012 Student Edition (hard Cover) Grade 11, Chapter 22, Problem 71A , additional homework tip  2

Carbon atom labelled as 2 is attached to two carbon and two hydrogen atoms. Hence it is a secondary carbon.

(c)

Interpretation Introduction

Interpretation- To identify the tertiary carbon.

Concept Introduction-

Carbon atoms can be classified on the basis of carbon attached to them as:

  1. Primary carbon: When only one carbon atom attached to it. Remaining all the bonds attached to hydrogen.
  2. Secondary carbon: When carbon atoms is attached to carbon two carbon and remaining two are hydrogen atoms.
  3. Tertiary carbon: When carbon is attached to 3 carbon atoms and one hydrogen atom.
  4. Quaternary carbon: When carbon atom is attached to four carbon atoms and no hydrogen atom.

(c)

Expert Solution
Check Mark

Explanation of Solution

In the given molecule,

  Chemistry 2012 Student Edition (hard Cover) Grade 11, Chapter 22, Problem 71A , additional homework tip  3

Carbon atom labelled as 3 is attached to three carbon and one hydrogen atoms. Hence it is a tertiary carbon.

(d)

Interpretation Introduction

Interpretation- To identify the quaternary carbon.

Concept Introduction-

Carbon atoms can be classified on the basis of carbon attached to them as:

  1. Primary carbon: When only one carbon atom attached to it. Remaining all the bonds attached to hydrogen.
  2. Secondary carbon: When carbon atoms is attached to carbon two carbon and remaining two are hydrogen atoms.
  3. Tertiary carbon: When carbon is attached to 3 carbon atoms and one hydrogen atom.
  4. Quaternary carbon: When carbon atom is attached to four carbon atoms and no hydrogen atom.

(d)

Expert Solution
Check Mark

Explanation of Solution

In the given molecule,

  Chemistry 2012 Student Edition (hard Cover) Grade 11, Chapter 22, Problem 71A , additional homework tip  4

Carbon atom labelled as 1 is attached to four carbon and no hydrogen atoms. Hence it is a quaternary carbon.

Chapter 22 Solutions

Chemistry 2012 Student Edition (hard Cover) Grade 11

Ch. 22.1 - Prob. 11LCCh. 22.1 - Prob. 12LCCh. 22.1 - Prob. 13LCCh. 22.2 - Prob. 14LCCh. 22.2 - Prob. 15LCCh. 22.2 - Prob. 16LCCh. 22.2 - Prob. 17LCCh. 22.2 - Prob. 18LCCh. 22.3 - Prob. 19SPCh. 22.3 - Prob. 20SPCh. 22.3 - Prob. 21LCCh. 22.3 - Prob. 22LCCh. 22.3 - Prob. 23LCCh. 22.3 - Prob. 24LCCh. 22.3 - Prob. 25LCCh. 22.3 - Prob. 26LCCh. 22.3 - Prob. 27LCCh. 22.4 - Prob. 28LCCh. 22.4 - Prob. 29LCCh. 22.4 - Prob. 30LCCh. 22.4 - Prob. 31LCCh. 22.4 - Prob. 32LCCh. 22.5 - Prob. 33LCCh. 22.5 - Prob. 34LCCh. 22.5 - Prob. 35LCCh. 22.5 - Prob. 36LCCh. 22.5 - Prob. 37LCCh. 22.5 - Prob. 38LCCh. 22.5 - Prob. 39LCCh. 22.5 - Prob. 40LCCh. 22 - Prob. 41ACh. 22 - Prob. 42ACh. 22 - Prob. 43ACh. 22 - Prob. 44ACh. 22 - Prob. 45ACh. 22 - Prob. 46ACh. 22 - Prob. 47ACh. 22 - Prob. 48ACh. 22 - Prob. 49ACh. 22 - Prob. 50ACh. 22 - Prob. 51ACh. 22 - Prob. 52ACh. 22 - Prob. 53ACh. 22 - Prob. 54ACh. 22 - Prob. 55ACh. 22 - Prob. 56ACh. 22 - Prob. 57ACh. 22 - Prob. 58ACh. 22 - Prob. 59ACh. 22 - Prob. 60ACh. 22 - Prob. 61ACh. 22 - Prob. 62ACh. 22 - Prob. 63ACh. 22 - Prob. 64ACh. 22 - Prob. 65ACh. 22 - Prob. 66ACh. 22 - Prob. 67ACh. 22 - Prob. 68ACh. 22 - Prob. 69ACh. 22 - Prob. 70ACh. 22 - Prob. 71ACh. 22 - Prob. 72ACh. 22 - Prob. 73ACh. 22 - Prob. 74ACh. 22 - Prob. 75ACh. 22 - Prob. 76ACh. 22 - Prob. 77ACh. 22 - Prob. 78ACh. 22 - Prob. 79ACh. 22 - Prob. 80ACh. 22 - Prob. 81ACh. 22 - Prob. 82ACh. 22 - Prob. 84ACh. 22 - Prob. 85ACh. 22 - Prob. 86ACh. 22 - Prob. 87ACh. 22 - Prob. 89ACh. 22 - Prob. 90ACh. 22 - Prob. 91ACh. 22 - Prob. 92ACh. 22 - Prob. 93ACh. 22 - Prob. 94ACh. 22 - Prob. 95ACh. 22 - Prob. 96ACh. 22 - Prob. 97ACh. 22 - Prob. 98ACh. 22 - Prob. 99ACh. 22 - Prob. 100ACh. 22 - Prob. 101ACh. 22 - Prob. 102ACh. 22 - Prob. 103ACh. 22 - Prob. 104ACh. 22 - Prob. 105ACh. 22 - Prob. 106ACh. 22 - Prob. 107ACh. 22 - Prob. 108ACh. 22 - Prob. 109ACh. 22 - Prob. 110ACh. 22 - Prob. 111ACh. 22 - Prob. 1STPCh. 22 - Prob. 2STPCh. 22 - Prob. 3STPCh. 22 - Prob. 4STPCh. 22 - Prob. 5STPCh. 22 - Prob. 6STPCh. 22 - Prob. 7STPCh. 22 - Prob. 8STPCh. 22 - Prob. 9STPCh. 22 - Prob. 10STPCh. 22 - Prob. 11STPCh. 22 - Prob. 12STPCh. 22 - Prob. 13STPCh. 22 - Prob. 14STPCh. 22 - Prob. 15STPCh. 22 - Prob. 16STP
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