Chemistry 2012 Student Edition (hard Cover) Grade 11
Chemistry 2012 Student Edition (hard Cover) Grade 11
12th Edition
ISBN: 9780132525763
Author: Prentice Hall
Publisher: Prentice Hall
Question
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Chapter 22, Problem 106A

a.

Interpretation Introduction

Interpretation: To determine the oxidation number of nitrogen in a given compound.

Concept Introduction: Oxidation number determines the number of electrons lost or gained by an atom or ion.

a.

Expert Solution
Check Mark

Answer to Problem 106A

The oxidation number of nitrogen is 4.

Explanation of Solution

The given compound is N2O4 .

The calculation for the oxidation number is as follows:

Consider the oxidation number of nitrogen be x .

  2x+42=08+2x=02x=8x=4

Thus, the oxidation number of nitrogen is 4.

b.

Interpretation Introduction

Interpretation: To determine the oxidation number of nitrogen in a given compound.

Concept Introduction: Oxidation number determines the number of electrons lost or gained by an atom or ion.

b.

Expert Solution
Check Mark

Answer to Problem 106A

The oxidation number of nitrogen is 5.

Explanation of Solution

The given compound is NO3 .

The calculation for the oxidation number is as follows:

Consider the oxidation number of nitrogen be x .

  x+32=1x6=1x=1+6x=5

Thus, the oxidation number of nitrogen is 5.

c.

Interpretation Introduction

Interpretation: To determine the oxidation number of nitrogen in a given compound.

Concept Introduction: Oxidation number determines the number of electrons lost or gained by an atom or ion.

c.

Expert Solution
Check Mark

Answer to Problem 106A

The oxidation number of nitrogen is 4.

Explanation of Solution

The given compound is NO2 .

The calculation for the oxidation number is as follows:

Consider the oxidation number of nitrogen be x .

  x+22=0x4=0x=4

Thus, the oxidation number of nitrogen is 4.

d.

Interpretation Introduction

Interpretation: To determine the oxidation number of nitrogen in a given compound.

Concept Introduction: Oxidation number determines the number of electrons lost or gained by an atom or ion.

d.

Expert Solution
Check Mark

Answer to Problem 106A

The oxidation number of nitrogen is -3.

Explanation of Solution

The given compound is NH4+ .

The calculation for the oxidation number is as follows:

Consider the oxidation number of nitrogen be x .

  x+41=+1x+4=+1x=14x=3

Thus, the oxidation number of nitrogen is -3.

e.

Interpretation Introduction

Interpretation: To determine the oxidation number of nitrogen in a given compound.

Concept Introduction: Oxidation number determines the number of electrons lost or gained by an atom or ion.

e.

Expert Solution
Check Mark

Answer to Problem 106A

The oxidation number of nitrogen is -3.

Explanation of Solution

The given compound is NH3 .

The calculation for the oxidation number is as follows:

Consider the oxidation number of nitrogen be x .

  x+31=0x+3=0x=03x=3

Thus, the oxidation number of nitrogen is -3.

f.

Interpretation Introduction

Interpretation: To determine the oxidation number of nitrogen in a given compound.

Concept Introduction: Oxidation number determines the number of electrons lost or gained by an atom or ion.

f.

Expert Solution
Check Mark

Answer to Problem 106A

The oxidation number of nitrogen is +2.

Explanation of Solution

The given compound is NO .

The calculation for the oxidation number is as follows:

Consider the oxidation number of nitrogen be x .

  x+12=0x2=0x=0+2x=2

Thus, the oxidation number of nitrogen is +2.

Chapter 22 Solutions

Chemistry 2012 Student Edition (hard Cover) Grade 11

Ch. 22.1 - Prob. 11LCCh. 22.1 - Prob. 12LCCh. 22.1 - Prob. 13LCCh. 22.2 - Prob. 14LCCh. 22.2 - Prob. 15LCCh. 22.2 - Prob. 16LCCh. 22.2 - Prob. 17LCCh. 22.2 - Prob. 18LCCh. 22.3 - Prob. 19SPCh. 22.3 - Prob. 20SPCh. 22.3 - Prob. 21LCCh. 22.3 - Prob. 22LCCh. 22.3 - Prob. 23LCCh. 22.3 - Prob. 24LCCh. 22.3 - Prob. 25LCCh. 22.3 - Prob. 26LCCh. 22.3 - Prob. 27LCCh. 22.4 - Prob. 28LCCh. 22.4 - Prob. 29LCCh. 22.4 - Prob. 30LCCh. 22.4 - Prob. 31LCCh. 22.4 - Prob. 32LCCh. 22.5 - Prob. 33LCCh. 22.5 - Prob. 34LCCh. 22.5 - Prob. 35LCCh. 22.5 - Prob. 36LCCh. 22.5 - Prob. 37LCCh. 22.5 - Prob. 38LCCh. 22.5 - Prob. 39LCCh. 22.5 - Prob. 40LCCh. 22 - Prob. 41ACh. 22 - Prob. 42ACh. 22 - Prob. 43ACh. 22 - Prob. 44ACh. 22 - Prob. 45ACh. 22 - Prob. 46ACh. 22 - Prob. 47ACh. 22 - Prob. 48ACh. 22 - Prob. 49ACh. 22 - Prob. 50ACh. 22 - Prob. 51ACh. 22 - Prob. 52ACh. 22 - Prob. 53ACh. 22 - Prob. 54ACh. 22 - Prob. 55ACh. 22 - Prob. 56ACh. 22 - Prob. 57ACh. 22 - Prob. 58ACh. 22 - Prob. 59ACh. 22 - Prob. 60ACh. 22 - Prob. 61ACh. 22 - Prob. 62ACh. 22 - Prob. 63ACh. 22 - Prob. 64ACh. 22 - Prob. 65ACh. 22 - Prob. 66ACh. 22 - Prob. 67ACh. 22 - Prob. 68ACh. 22 - Prob. 69ACh. 22 - Prob. 70ACh. 22 - Prob. 71ACh. 22 - Prob. 72ACh. 22 - Prob. 73ACh. 22 - Prob. 74ACh. 22 - Prob. 75ACh. 22 - Prob. 76ACh. 22 - Prob. 77ACh. 22 - Prob. 78ACh. 22 - Prob. 79ACh. 22 - Prob. 80ACh. 22 - Prob. 81ACh. 22 - Prob. 82ACh. 22 - Prob. 84ACh. 22 - Prob. 85ACh. 22 - Prob. 86ACh. 22 - Prob. 87ACh. 22 - Prob. 89ACh. 22 - Prob. 90ACh. 22 - Prob. 91ACh. 22 - Prob. 92ACh. 22 - Prob. 93ACh. 22 - Prob. 94ACh. 22 - Prob. 95ACh. 22 - Prob. 96ACh. 22 - Prob. 97ACh. 22 - Prob. 98ACh. 22 - Prob. 99ACh. 22 - Prob. 100ACh. 22 - Prob. 101ACh. 22 - Prob. 102ACh. 22 - Prob. 103ACh. 22 - Prob. 104ACh. 22 - Prob. 105ACh. 22 - Prob. 106ACh. 22 - Prob. 107ACh. 22 - Prob. 108ACh. 22 - Prob. 109ACh. 22 - Prob. 110ACh. 22 - Prob. 111ACh. 22 - Prob. 1STPCh. 22 - Prob. 2STPCh. 22 - Prob. 3STPCh. 22 - Prob. 4STPCh. 22 - Prob. 5STPCh. 22 - Prob. 6STPCh. 22 - Prob. 7STPCh. 22 - Prob. 8STPCh. 22 - Prob. 9STPCh. 22 - Prob. 10STPCh. 22 - Prob. 11STPCh. 22 - Prob. 12STPCh. 22 - Prob. 13STPCh. 22 - Prob. 14STPCh. 22 - Prob. 15STPCh. 22 - Prob. 16STP
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