Chemistry 2012 Student Edition (hard Cover) Grade 11
Chemistry 2012 Student Edition (hard Cover) Grade 11
12th Edition
ISBN: 9780132525763
Author: Prentice Hall
Publisher: Prentice Hall
Question
Book Icon
Chapter 22, Problem 104A

a.

Interpretation Introduction

Interpretation: To determine the oxidation number for each of the elements in a given compound.

Concept Introduction: Oxidation number determines the number of electrons lost or gained by an atom or ion.

a.

Expert Solution
Check Mark

Answer to Problem 104A

The oxidation number of calcium is +2, carbon is +4 and oxygen is -2.

Explanation of Solution

The given compound is CaCO3 .

The calculation for the oxidation number is as follows:

  2+C+3−2=0−4+C=0C=−4

Thus, the oxidation number of calcium is +2, carbon is +4 and oxygen is -2.

b.

Interpretation Introduction

Interpretation: To determine the oxidation number for each of the elements in a given compound.

Concept Introduction: Oxidation number determines the number of electrons lost or gained by an atom or ion.

b.

Expert Solution
Check Mark

Answer to Problem 104A

The oxidation number of chlorine is 0.

Explanation of Solution

The given compound is Cl2 .

The oxidation number of chlorine gas is zero.

Thus, the oxidation number of chlorine is 0.

c.

Interpretation Introduction

Interpretation: To determine the oxidation number for each of the elements in a given compound.

Concept Introduction: Oxidation number determines the number of electrons lost or gained by an atom or ion.

c.

Expert Solution
Check Mark

Answer to Problem 104A

The oxidation number of lithium is +1, iodine is +5 and oxygen is -2.

Explanation of Solution

The given compound is LiIO3 .

The calculation for the oxidation number is as follows:

  1+I+3−2=0I−5=0I=+5

Thus, the oxidation number of lithium is +1, iodine is +5 and oxygen is -2.

d.

Interpretation Introduction

Interpretation: To determine the oxidation number for each of the elements in a given compound.

Concept Introduction: Oxidation number determines the number of electrons lost or gained by an atom or ion.

d.

Expert Solution
Check Mark

Answer to Problem 104A

The oxidation number of sodium is +1, sulfur is +4 and oxygen is -2.

Explanation of Solution

The given compound is Na2SO3 .

The calculation for the oxidation number is as follows:

  2+1+S+3−2=0S−4=0S=+4

Thus, the oxidation number of sodium is +1, sulfur is +4 and oxygen is -2.

Previous
Chapter 22, Problem 103A
Next
Chapter 22, Problem 105A

Chapter 22 Solutions

Chemistry 2012 Student Edition (hard Cover) Grade 11

Ch. 22.1 - Prob. 1SPCh. 22.1 - Prob. 2SPCh. 22.1 - Prob. 3SPCh. 22.1 - Prob. 4SPCh. 22.1 - Prob. 5SPCh. 22.1 - Prob. 6SPCh. 22.1 - Prob. 7LCCh. 22.1 - Prob. 8LCCh. 22.1 - Prob. 9LCCh. 22.1 - Prob. 10LC
Ch. 22.1 - Prob. 11LCCh. 22.1 - Prob. 12LCCh. 22.1 - Prob. 13LCCh. 22.2 - Prob. 14LCCh. 22.2 - Prob. 15LCCh. 22.2 - Prob. 16LCCh. 22.2 - Prob. 17LCCh. 22.2 - Prob. 18LCCh. 22.3 - Prob. 19SPCh. 22.3 - Prob. 20SPCh. 22.3 - Prob. 21LCCh. 22.3 - Prob. 22LCCh. 22.3 - Prob. 23LCCh. 22.3 - Prob. 24LCCh. 22.3 - Prob. 25LCCh. 22.3 - Prob. 26LCCh. 22.3 - Prob. 27LCCh. 22.4 - Prob. 28LCCh. 22.4 - Prob. 29LCCh. 22.4 - Prob. 30LCCh. 22.4 - Prob. 31LCCh. 22.4 - Prob. 32LCCh. 22.5 - Prob. 33LCCh. 22.5 - Prob. 34LCCh. 22.5 - Prob. 35LCCh. 22.5 - Prob. 36LCCh. 22.5 - Prob. 37LCCh. 22.5 - Prob. 38LCCh. 22.5 - Prob. 39LCCh. 22.5 - Prob. 40LCCh. 22 - Prob. 41ACh. 22 - Prob. 42ACh. 22 - Prob. 43ACh. 22 - Prob. 44ACh. 22 - Prob. 45ACh. 22 - Prob. 46ACh. 22 - Prob. 47ACh. 22 - Prob. 48ACh. 22 - Prob. 49ACh. 22 - Prob. 50ACh. 22 - Prob. 51ACh. 22 - Prob. 52ACh. 22 - Prob. 53ACh. 22 - Prob. 54ACh. 22 - Prob. 55ACh. 22 - Prob. 56ACh. 22 - Prob. 57ACh. 22 - Prob. 58ACh. 22 - Prob. 59ACh. 22 - Prob. 60ACh. 22 - Prob. 61ACh. 22 - Prob. 62ACh. 22 - Prob. 63ACh. 22 - Prob. 64ACh. 22 - Prob. 65ACh. 22 - Prob. 66ACh. 22 - Prob. 67ACh. 22 - Prob. 68ACh. 22 - Prob. 69ACh. 22 - Prob. 70ACh. 22 - Prob. 71ACh. 22 - Prob. 72ACh. 22 - Prob. 73ACh. 22 - Prob. 74ACh. 22 - Prob. 75ACh. 22 - Prob. 76ACh. 22 - Prob. 77ACh. 22 - Prob. 78ACh. 22 - Prob. 79ACh. 22 - Prob. 80ACh. 22 - Prob. 81ACh. 22 - Prob. 82ACh. 22 - Prob. 84ACh. 22 - Prob. 85ACh. 22 - Prob. 86ACh. 22 - Prob. 87ACh. 22 - Prob. 89ACh. 22 - Prob. 90ACh. 22 - Prob. 91ACh. 22 - Prob. 92ACh. 22 - Prob. 93ACh. 22 - Prob. 94ACh. 22 - Prob. 95ACh. 22 - Prob. 96ACh. 22 - Prob. 97ACh. 22 - Prob. 98ACh. 22 - Prob. 99ACh. 22 - Prob. 100ACh. 22 - Prob. 101ACh. 22 - Prob. 102ACh. 22 - Prob. 103ACh. 22 - Prob. 104ACh. 22 - Prob. 105ACh. 22 - Prob. 106ACh. 22 - Prob. 107ACh. 22 - Prob. 108ACh. 22 - Prob. 109ACh. 22 - Prob. 110ACh. 22 - Prob. 111ACh. 22 - Prob. 1STPCh. 22 - Prob. 2STPCh. 22 - Prob. 3STPCh. 22 - Prob. 4STPCh. 22 - Prob. 5STPCh. 22 - Prob. 6STPCh. 22 - Prob. 7STPCh. 22 - Prob. 8STPCh. 22 - Prob. 9STPCh. 22 - Prob. 10STPCh. 22 - Prob. 11STPCh. 22 - Prob. 12STPCh. 22 - Prob. 13STPCh. 22 - Prob. 14STPCh. 22 - Prob. 15STPCh. 22 - Prob. 16STP
Knowledge Booster
Background pattern image
Recommended textbooks for you
Text book image
Chemistry
Chemistry
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Cengage Learning
Text book image
Chemistry
Chemistry
ISBN:9781259911156
Author:Raymond Chang Dr., Jason Overby Professor
Publisher:McGraw-Hill Education
Text book image
Principles of Instrumental Analysis
Chemistry
ISBN:9781305577213
Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:Cengage Learning
Text book image
Organic Chemistry
Chemistry
ISBN:9780078021558
Author:Janice Gorzynski Smith Dr.
Publisher:McGraw-Hill Education
Text book image
Chemistry: Principles and Reactions
Chemistry
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:Cengage Learning
Text book image
Elementary Principles of Chemical Processes, Bind...
Chemistry
ISBN:9781118431221
Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:WILEY
SEE MORE TEXTBOOKS