Genetics: Analysis and Principles
6th Edition
ISBN: 9781259616020
Author: Robert J. Brooker Professor Dr.
Publisher: McGraw-Hill Education
expand_more
expand_more
format_list_bulleted
Videos
Question
Chapter 2, Problem 12EQ
Summary Introduction
To review:
The chi square analysis for the determination of consistency of the provided data with the law of segregation.
Introduction:
Chi square test is a statistical test which is used to determine the validity of a hypothesis provided theoretically with an observed version of its own. It helps in determining how closely the observed value and the expected value are related to one another. The law of segregation states that during gamete formation, the pair of alleles separates, so that each gamete carries one allele for a gene.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
shown are the F2 results of two Mendel's monohybrid crosses. Mendel crossed 2 heterozygote parents. If he were to expect segregation to happen normally, do the results match his expectations? state a null hypothesis that you will test using chi-square analysis. Calculate the chi-square value and determine the p value for both crosses
a. Full pods: 882; constricted pods: 299 (full pods are dominant over constricted)
b. violet flowers: 705; white flowers: 500 (violet dominant over white)
List four modified Mendelian ratios that you can think of.
To assess Mendel’s law of segregation using tomatoes, a true-breeding tall variety (SS) is crossed with a true-breeding short variety (ss). The heterozygous F1 tall plants (Ss) were crossed to produce two sets of F2 data as follows.
Set 1
Set 2
30 tall
300 tall
5 short
50 short
Using the chi-square test, analyze the results for both datasets. Calculate the chi-square values and estimate the p-values in both cases.
From the above analysis, what can you conclude about the importance of generating large datasets in experimental condition?
Chapter 2 Solutions
Genetics: Analysis and Principles
Ch. 2.1 - 1. Experimental advantages of using pea plants...Ch. 2.1 - The term cross refers to an experiment in which a....Ch. 2.1 - 3. To avoid self-fertilization in his pea plants,...Ch. 2.2 - Prob. 1COMQCh. 2.2 - Prob. 2COMQCh. 2.3 - A pea plant has the genotype rrYy. How many...Ch. 2.3 - A cross is made between a pea plant that is RrYy...Ch. 2.3 - Prob. 3COMQCh. 2.4 - Which of the following would not be observed in a...Ch. 2.4 - Prob. 2COMQ
Ch. 2.5 - A cross is made between AABbCcDd and AaBbccdd...Ch. 2.5 - Prob. 2COMQCh. 2.5 - Prob. 3COMQCh. 2 - 1. Why did Mendel’s work refute the idea of...Ch. 2 - 2. What is the difference between...Ch. 2 - 3. Describe the difference between genotype and...Ch. 2 - 4. With regard to genotypes, what is a...Ch. 2 - 5. How can you determine whether an organism is...Ch. 2 - In your own words, describe Mendels law of...Ch. 2 - Based on genes in pea plants that we have...Ch. 2 - Prob. 8CONQCh. 2 - Do you know the genotype of an individual with a...Ch. 2 - 10. A cross is made between a pea plant that has...Ch. 2 - Prob. 11CONQCh. 2 - 12. Describe the significance of nonparentals with...Ch. 2 - For the following pedigrees, describe what you...Ch. 2 - Ectrodactyly, also known as lobster claw syndrome,...Ch. 2 - Identical twins are produced from the same sperm...Ch. 2 - In cocker spaniels, solid coat color is dominant...Ch. 2 - A cross was made between a white male dog and two...Ch. 2 - 18. In humans, the allele for brown eye color (B)...Ch. 2 - Albinism, a condition characterized by a partial...Ch. 2 - A true-breeding tall plant was crossed to a dwarf...Ch. 2 - 21. For pea plants with the following genotypes,...Ch. 2 - 22. An individual has the genotypeand makes an...Ch. 2 - 23. In people with maple syrup urine disease, the...Ch. 2 - Prob. 24CONQCh. 2 - 25. A true-breeding pea plant with round and Page...Ch. 2 - Prob. 26CONQCh. 2 - 27. What are the expected phenotypic ratios from...Ch. 2 - Prob. 28CONQCh. 2 - Prob. 29CONQCh. 2 - A pea plant that is dwarf with green, wrinkled...Ch. 2 - 31. A true-breeding plant with round and green...Ch. 2 - Wooly hair is a rare dominant trait found in...Ch. 2 - Huntington disease is a rare dominant trait that...Ch. 2 - 34. A woman with achondroplasia (a dominant form...Ch. 2 - 1. Describe three advantages of using pea plants...Ch. 2 - Explain the technical differences between a...Ch. 2 - 3. How long did it take Mendel to complete the...Ch. 2 - 4. For all seven characters described in the data...Ch. 2 - From the point of view of crosses and data...Ch. 2 - 6. As in many animals, albino coat color is a...Ch. 2 - 7. The fungus Melampsora lini causes a disease...Ch. 2 - For Mendels data for the experiment in Figure 2.8,...Ch. 2 - 9. Would it be possible to deduce the law of...Ch. 2 - In fruit flies, curved wings are recessive to...Ch. 2 - A recessive allele in mice results in an unusally...Ch. 2 - Prob. 12EQCh. 2 - Prob. 13EQCh. 2 - Prob. 14EQCh. 2 - 15. A cross was made between two strains of plants...Ch. 2 - A cross was made between two pea plants, TtAa and...Ch. 2 - Consider this four-factor cross: TtRryyAaTtRRYyaa,...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- Pedigree analysis is a fundamental tool for investigating whether or not a trait is following a Mendelian pattern of inheritance. It can also be used to help identify individuals within a family who may be at risk for the trait. Adam and Sarah, a young couple of Eastern European Jewish ancestry, went to a genetic counselor because they were planning a family and wanted to know what their chances were for having a child with a genetic condition. The genetic counselor took a detailed family history from both of them and discovered several traits in their respective families. Sarahs maternal family history is suggestive of an autosomal dominant pattern of cancer predisposition to breast and ovarian cancer because of the young ages at which her mother and grandmother were diagnosed with their cancers. If a mutant allele that predisposed to breast and ovarian cancer was inherited in Sarahs family, she, her sister, and any of her own future children could be at risk for inheriting this mutation. The counselor told her that genetic testing is available that may help determine if this mutant allele is present in her family members. Adams paternal family history has a very strong pattern of early onset heart disease. An autosomal dominant condition known as familial hypercholesterolemia may be responsible for the large number of deaths from heart disease. As with hereditary breast and ovarian cancer, genetic testing is available to see if Adam carries the mutant allele. Testing will give the couple more information about the chances that their children could inherit this mutation. Adam had a first cousin who died from Tay-Sachs disease (TSD), a fatal autosomal recessive condition most commonly found in people of Eastern European Jewish descent. Because TSD is a recessively inherited disorder, both of his cousins parents must have been heterozygous carriers of the mutant allele. If that is the case, Adams father could be a carrier as well. If Adams father carries the mutant TSD allele, it is possible that Adam inherited this mutation. Because Sarah is also of Eastern European Jewish ancestry, she could also be a carrier of the gene, even though no one in her family has been affected with TSD. If Adam and Sarah are both carriers, each of their children would have a 25% chance of being afflicted with TSD. A simple blood test performed on both Sarah and Adam could determine whether they are carriers of this mutation. Would you decide to have a child if the test results said that you carry the mutation for breast and ovarian cancer? The heart disease mutation? The TSD mutation? The heart disease and the mutant alleles?arrow_forwardPedigree analysis is a fundamental tool for investigating whether or not a trait is following a Mendelian pattern of inheritance. It can also be used to help identify individuals within a family who may be at risk for the trait. Adam and Sarah, a young couple of Eastern European Jewish ancestry, went to a genetic counselor because they were planning a family and wanted to know what their chances were for having a child with a genetic condition. The genetic counselor took a detailed family history from both of them and discovered several traits in their respective families. Sarahs maternal family history is suggestive of an autosomal dominant pattern of cancer predisposition to breast and ovarian cancer because of the young ages at which her mother and grandmother were diagnosed with their cancers. If a mutant allele that predisposed to breast and ovarian cancer was inherited in Sarahs family, she, her sister, and any of her own future children could be at risk for inheriting this mutation. The counselor told her that genetic testing is available that may help determine if this mutant allele is present in her family members. Adams paternal family history has a very strong pattern of early onset heart disease. An autosomal dominant condition known as familial hypercholesterolemia may be responsible for the large number of deaths from heart disease. As with hereditary breast and ovarian cancer, genetic testing is available to see if Adam carries the mutant allele. Testing will give the couple more information about the chances that their children could inherit this mutation. Adam had a first cousin who died from Tay-Sachs disease (TSD), a fatal autosomal recessive condition most commonly found in people of Eastern European Jewish descent. Because TSD is a recessively inherited disorder, both of his cousins parents must have been heterozygous carriers of the mutant allele. If that is the case, Adams father could be a carrier as well. If Adams father carries the mutant TSD allele, it is possible that Adam inherited this mutation. Because Sarah is also of Eastern European Jewish ancestry, she could also be a carrier of the gene, even though no one in her family has been affected with TSD. If Adam and Sarah are both carriers, each of their children would have a 25% chance of being afflicted with TSD. A simple blood test performed on both Sarah and Adam could determine whether they are carriers of this mutation. Would you want to know the results of the cancer, heart disease, and TSD tests if you were Sarah and Adam? Is it their responsibility as potential parents to gather this type of information before they decide to have a child?arrow_forwardPedigree analysis is a fundamental tool for investigating whether or not a trait is following a Mendelian pattern of inheritance. It can also be used to help identify individuals within a family who may be at risk for the trait. Adam and Sarah, a young couple of Eastern European Jewish ancestry, went to a genetic counselor because they were planning a family and wanted to know what their chances were for having a child with a genetic condition. The genetic counselor took a detailed family history from both of them and discovered several traits in their respective families. Sarahs maternal family history is suggestive of an autosomal dominant pattern of cancer predisposition to breast and ovarian cancer because of the young ages at which her mother and grandmother were diagnosed with their cancers. If a mutant allele that predisposed to breast and ovarian cancer was inherited in Sarahs family, she, her sister, and any of her own future children could be at risk for inheriting this mutation. The counselor told her that genetic testing is available that may help determine if this mutant allele is present in her family members. Adams paternal family history has a very strong pattern of early onset heart disease. An autosomal dominant condition known as familial hypercholesterolemia may be responsible for the large number of deaths from heart disease. As with hereditary breast and ovarian cancer, genetic testing is available to see if Adam carries the mutant allele. Testing will give the couple more information about the chances that their children could inherit this mutation. Adam had a first cousin who died from Tay-Sachs disease (TSD), a fatal autosomal recessive condition most commonly found in people of Eastern European Jewish descent. Because TSD is a recessively inherited disorder, both of his cousins parents must have been heterozygous carriers of the mutant allele. If that is the case, Adams father could be a carrier as well. If Adams father carries the mutant TSD allele, it is possible that Adam inherited this mutation. Because Sarah is also of Eastern European Jewish ancestry, she could also be a carrier of the gene, even though no one in her family has been affected with TSD. If Adam and Sarah are both carriers, each of their children would have a 25% chance of being afflicted with TSD. A simple blood test performed on both Sarah and Adam could determine whether they are carriers of this mutation. If Sarah carries the mutant cancer allele and Adam carries the mutant heart disease allele, what is the chance that they would have a child who is free of both diseases? Are these good odds?arrow_forward
- The text outlines some of the problems Frederick William I encountered in his attempt to breed tall Potsdam Guards. a. Why were the results he obtained so different from those obtained by Mendel with short and tall pea plants? b. Why were most of the children shorter than their tall parents?arrow_forward1) Identify the most important advantage that Mendel's pea plants had for studying the inheritance of traits 2) Using no more than one sentence, please explain why this advantage or characteristic was critical for the success of Mendel's experimentsarrow_forwardIn a problem involving albinism (see Problem 4), which of Mendel’spostulates are demonstrated? Problem No. 4 Albinism in humans is inherited as a simple recessive trait.Determine the genotypes of the parents and offspring for thefollowing families. When two alternative genotypes are possible,list both.(a) Two parents without albinism have five children, four withoutalbinism and one with albinism.(b) A male without albinism and a female with albinism havesix children, all without albinism.arrow_forward
- Work out the Chi-Squared Goodness of Fit for Mendel's actual data on stem length: "Expt. 7: Length of stem. –– Out of 1,064 plants, in 787 cases the stem was long, and in 277 short. Hence a mutual ratio of 2.84:1. In this experiment the dwarfed plants were carefully lifted and transferred to a special bed. This precaution was necessary, as otherwise they would have perished through being overgrown by their tall relatives. Even in their quite young state they can be easily picked out by their compact growth and thick dark–green foliage." F2: O E O-E (O-E)^2 (O-E)^2/E # short 277 266 11 121 0.455 # tall 787 798 -11 121 0.152 sums: 1,064 1064 0.607 degrees of freedom = 2-1=1 Chi-squared value = .607 p-value: 0.25 < p < 0.50 Work out the Chi-Squared Goodness of Fit for Mendel's actual data on flower position: "Expt. 6: Position of flowers. –– Among 858 cases 651…arrow_forwardKernel color in wheat is controlled by 2 pairs of genes (AABB). Determine the color of each offspring with the following genotypes: (Note: 4 alleles – red; 3 – medium red; 2 – intermediate red; 1 – light red; 0 – white). CAPITAL letters only and with spaces when applicable. AABb - AaBb - AABB - aaBb - aabb -arrow_forwardOn the basis of Mendel’s observations (i.e. Mendelian patterns), predict the results from the following crosses with peas. Show the results in terms of genotypes, phenotypes, and their proportions in the offspring. The progeny of a tall (dominant and homozygous) variety crossed with a dwarf variety. The progeny of (a) self-fertilized. The progeny from (a) crossed with the original tall parent. The progeny of (a) crossed with the original dwarf parent.arrow_forward
- This question deals with Mendelian Genetics. Read each part carefully before you answer it. In the following questions, assume green pea pods are dominant over yellow pea pods. a) If a pea plant that is Heterozygous for pod color is crossed with a pea plant with yellow pods, what do you expect to see in the offspring (the f1 generation)? Specifically, what genotypes, what phenotypes, and in what ratios? (Use G for the green pod gene and g for the yellow pod gene.) (It is usually helpful to write out all the possible genotypes and give the phenotype for each genotype before answering the specific question.)arrow_forwardIn which type of cross(es) can we apply and demonstrate the law of segregation and law of independent assortment? Why can’t we apply the 2 Mendelian laws on monohybrid crosses? Explain briefly. How can one use a pedigree chart to hypothesize how a certain condition is transmitted? Can a pedigree chart show probability of occurrence more accurately than the Punnett square? Why or why not?arrow_forwardMendel crossed Parental true-breeding (homozygous) Purple flowered peas with true-breeding (homozygous) White flowered peas, and all the F1 offspring were Purple flowered. What was the phenotype and genotype of the F1 hybrids? 3/4 purple, PP: 1/4white pp .1/2purple. PP 1/2 whitce pp purple. PA purple Pp 近arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Human Heredity: Principles and Issues (MindTap Co...BiologyISBN:9781305251052Author:Michael CummingsPublisher:Cengage Learning
Human Heredity: Principles and Issues (MindTap Co...
Biology
ISBN:9781305251052
Author:Michael Cummings
Publisher:Cengage Learning
How do Plants Handle Stress?; Author: Alex Dainis;https://www.youtube.com/watch?v=TYsnveEHqec;License: Standard Youtube License