Genetics: Analysis and Principles
6th Edition
ISBN: 9781259616020
Author: Robert J. Brooker Professor Dr.
Publisher: McGraw-Hill Education
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Chapter 2, Problem 25CONQ
A true-breeding pea plant with round and Page 44 green seeds was crossed to a true-breeding plant with wrinkled and yellow seeds. Round and yellow seeds are the dominant traits. The
A. An
B. Three out of three
C. Five
D. An
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A true-breeding pea plant with round and green seeds was crossed with a true-breeding plant with wrinkled and yellow seeds. Round and yellow seeds are the dominant traits. The F1 plants were allowed to self-fertilize. What are the following probabilities for the F2 generation?
a. An F2 plant with wrinkled, yellow seeds.
b. Two out of three F2 plants with round, yellow seeds and one with wrinkled, green seeds.
c. Four F2 plants in the following order: one has round, yellow seeds; one has round, green seeds; and two have wrinkled, green seeds.
d. An F2 plant will not have round, yellow seeds.
If a cross is made between two plants that are heterozygous for two traits (AaBb), then their offspring should
follow the 9:3:3:1 ratio. In this case, A is the dominant allele for purple leaves, and B is the dominant allelle for
curly roots. If the two parents were crossed to yield 320 progeny, approximately how many plants with purple
leaves and curly roots would you expect?
Group of answer choices
a. 180
b.225
c.25
d.50
Two pure-breeding lines of petunia plants are crossed. Line 1 plants grow to a height of 54
cm, and Line 2 plants grow to a height of 18 cm. Petunia plant height is controlled by three
genes, A, B and C. Line 1 has the genotype A₁A₁B₁B₁C₁C₁, and line 2 has the genotype
A2A2B₂B₂C₂C₂. Assume that genotype alone determines plant height under ideal growth
conditions and that the alleles of the three genes are additive.
If the F1 plants are self crossed, what is the expected proportion of F2 plants with the
genotype A₁A₁B₁B₁C₁C₁
1/8
1/32
1/16
1/4
1/64
Chapter 2 Solutions
Genetics: Analysis and Principles
Ch. 2.1 - 1. Experimental advantages of using pea plants...Ch. 2.1 - The term cross refers to an experiment in which a....Ch. 2.1 - 3. To avoid self-fertilization in his pea plants,...Ch. 2.2 - Prob. 1COMQCh. 2.2 - Prob. 2COMQCh. 2.3 - A pea plant has the genotype rrYy. How many...Ch. 2.3 - A cross is made between a pea plant that is RrYy...Ch. 2.3 - Prob. 3COMQCh. 2.4 - Which of the following would not be observed in a...Ch. 2.4 - Prob. 2COMQ
Ch. 2.5 - A cross is made between AABbCcDd and AaBbccdd...Ch. 2.5 - Prob. 2COMQCh. 2.5 - Prob. 3COMQCh. 2 - 1. Why did Mendel’s work refute the idea of...Ch. 2 - 2. What is the difference between...Ch. 2 - 3. Describe the difference between genotype and...Ch. 2 - 4. With regard to genotypes, what is a...Ch. 2 - 5. How can you determine whether an organism is...Ch. 2 - In your own words, describe Mendels law of...Ch. 2 - Based on genes in pea plants that we have...Ch. 2 - Prob. 8CONQCh. 2 - Do you know the genotype of an individual with a...Ch. 2 - 10. A cross is made between a pea plant that has...Ch. 2 - Prob. 11CONQCh. 2 - 12. Describe the significance of nonparentals with...Ch. 2 - For the following pedigrees, describe what you...Ch. 2 - Ectrodactyly, also known as lobster claw syndrome,...Ch. 2 - Identical twins are produced from the same sperm...Ch. 2 - In cocker spaniels, solid coat color is dominant...Ch. 2 - A cross was made between a white male dog and two...Ch. 2 - 18. In humans, the allele for brown eye color (B)...Ch. 2 - Albinism, a condition characterized by a partial...Ch. 2 - A true-breeding tall plant was crossed to a dwarf...Ch. 2 - 21. For pea plants with the following genotypes,...Ch. 2 - 22. An individual has the genotypeand makes an...Ch. 2 - 23. In people with maple syrup urine disease, the...Ch. 2 - Prob. 24CONQCh. 2 - 25. A true-breeding pea plant with round and Page...Ch. 2 - Prob. 26CONQCh. 2 - 27. What are the expected phenotypic ratios from...Ch. 2 - Prob. 28CONQCh. 2 - Prob. 29CONQCh. 2 - A pea plant that is dwarf with green, wrinkled...Ch. 2 - 31. A true-breeding plant with round and green...Ch. 2 - Wooly hair is a rare dominant trait found in...Ch. 2 - Huntington disease is a rare dominant trait that...Ch. 2 - 34. A woman with achondroplasia (a dominant form...Ch. 2 - 1. Describe three advantages of using pea plants...Ch. 2 - Explain the technical differences between a...Ch. 2 - 3. How long did it take Mendel to complete the...Ch. 2 - 4. For all seven characters described in the data...Ch. 2 - From the point of view of crosses and data...Ch. 2 - 6. As in many animals, albino coat color is a...Ch. 2 - 7. The fungus Melampsora lini causes a disease...Ch. 2 - For Mendels data for the experiment in Figure 2.8,...Ch. 2 - 9. Would it be possible to deduce the law of...Ch. 2 - In fruit flies, curved wings are recessive to...Ch. 2 - A recessive allele in mice results in an unusally...Ch. 2 - Prob. 12EQCh. 2 - Prob. 13EQCh. 2 - Prob. 14EQCh. 2 - 15. A cross was made between two strains of plants...Ch. 2 - A cross was made between two pea plants, TtAa and...Ch. 2 - Consider this four-factor cross: TtRryyAaTtRRYyaa,...
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- If a cross is made between two plants that are heterozygous for two traits (AaBb), then their offspring should follow the 9:3:3:1 ratio. In this case, A is the dominant allele for purple leaves, and B is the dominant allelle for curly roots. If the two parents were crossed to yield 320 progeny, approximately how many plants with purple leaves and curly roots would you expect? Group of answer choices a.180 b.225 c.25 d.50 As part of a lab experiment, you create a two-locus cross between two plants, and you expect to see a 8:4:2:2 ratio of offspring. You determine the phenotype for 160 offspring, and find the proportions 84:38:19:19. If you use a chi-square test to determine whether the offspring do indeed fit this pattern, how many degrees of freedom would the test have? Group of answer choices a.2 b.3 c.83 d.4arrow_forwardA test cross between a plant of genotype PpSs and the tester white plant with wrinkled seed coat (ppss) gives the following numbers of progeny in four phenotypic types. 14:87:83:16 (purple flower + smooth seed coat: purple flower + wrinkled seed coat: white flower + smooth seed coat: white flower + wrinkled seed coat). a. What is the expected ratio of progeny phenotypes assuming independent assortment of alleles? b. Explain how ratios of progeny show that the two genes are linked. c. How many map units separate the purple and smooth genes? Show your calculations. d. What is the “parental” genotype of the heterozygous parent? (i.e. Which alleles of the P and S loci are present on each of the two chromosomes of the doubly heterozygous parent of this test cross?)arrow_forwardSunflowers with flowers 10 cm in diameter are crossed with a plant that has 16 cm flowers. The F1 plants have flowers 13 cm in diameter. In the F2 generation, 4 flowers are 10 cm in diameter and 4 are 16 cm in diameter. Between these are 5 phenotypic classes with diameters intermediate to those at the extremes.a) Assuming that the alleles that contribute to flower diameter act additively, how many genes control flower size? b) How much does each additive allele contribute to flower diameter? c) What size flower makes up the largest phenotypic class?arrow_forward
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- In summer squash, white fruit color (W) is dominant over yellow fruit color (w) and disk-shaped fruit (D) is dominant over sphere-shaped fruit (d).. If a squash plant true-breeding for white, disk-shaped fruit is crossed with a plant true-breeding for yellow, sphere-shaped fruit, what will the phenotypic and genotypic ratios be for: a. the F1 generation? b. the F2 generation? You must show the Punnett Square for the F2 generation!arrow_forwardSunflowers with flowers 10 cm in diameter are crossed with a plant that has 16 cm flowers. The F1 plants have flowers 13 cm in diameter. In the F2 generation, 4 flowers are 10 cm in diameter and 4 are 16 cm in diameter. Between these are 5 phenotypic classes with diameters intermediate to those at the extremes.How much does each additive allele contribute to flower diameter?(show work) What size flower makes up the largest phenotypic class?(show work)arrow_forwardA variety of opium poppy (Papaver somniferum L.) with lacerate leaves was crossed with a variety that has normal leaves. All the F1 had lacerate leaves. Two F1 plants were interbred to produce the F2. Of the F2, 249 had lacerate leaves and 16 had normal leaves. Give genotypes for all the plants in the P, F1, and F2 generations. Explain how lacerate leaves are determined in the opium poppy.arrow_forward
- Leaf color and stem length in a certain species of diploid flowers are controlled separately by the R and S locus. The R allele (dominant) results in red leaves while r results in yellow leaves. S (dominant) results in short stems and s results in long stems. A cross is performed between a true breeding long-stemmed red plant and a true breeding short- stemmed yellow plant. a. What is the genotype and phenotype of the resulting F1 plants? b. The resulting F1 plants are crossed with long-stemmed plants with yellow leaves. 100 offspring are collected from this cross, and the following phenotype counts are observed. phenotype long red short red count 43 8 long yellow short yellow 40 What are the corresponding genotypes for each of the four classes of the offspring from this cross? c. Using the information above, determine the genotype of the gametes contributed by "parent A" to each of the resulting offspring. Label the gamete types as parental or nonparental.arrow_forwardIn watermelons, bitter fruit (B) is dominant over sweet fruit (b), and yellow spots (S) are dominant over no spots (s). The genes for these two characteristics assort independently. A homozygous plant that has bitter fruit and yellow spots is crossed with a homozygous plant that has sweet fruit and no spots. The F1 are intercrossed to produce the F2. a. What are the phenotypic ratios in the F2? b. If an F1 plant is backcrossed with the bitter, yellow-spotted parent, what phenotypes and proportions are expected in the offspring? c. If an F1 plant is backcrossed with the sweet, unspotted parent, what phenotypes and proportions are expected in the offspring?arrow_forwardPurebred wrinkled, green-seeded pea plants were crossed with purebred round, yellow-seeded plants. The F1, all of which had round and yellow seeds, were then self-crossed resulting in the following F2: 172 plants with round and yellow seeds, 55 plants with round and green seeds, 58 plants with wrinkled and yellow seeds, and 15 plants with wrinkled and green seeds. Calculate the chi-square value and determine the p-value range. Which of the following are the correct chi-square values, p-value range, and whether you would accept or reject the hypothesis that these results are consistent with Mendelian predictions?arrow_forward
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