Genetics: Analysis and Principles
6th Edition
ISBN: 9781259616020
Author: Robert J. Brooker Professor Dr.
Publisher: McGraw-Hill Education
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Chapter 2, Problem 30CONQ
A pea plant that is dwarf with green, wrinkled seeds was crossed to a true-breeding plant that is tall with yellow, round seeds. The
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A pea plant that is dwarf with green, wrinkled seeds was crossedto a true-breeding plant that is tall with yellow, round seeds. TheF1 generation was allowed to self-fertilize. What types of gametes,and in what proportions, would the F1 generation make? Whatwould be the ratios of genotypes and phenotypes of the F2generation?
A cross is carried out between two pure lines of tomato plants, one having regular leaves and red fruit and the other having potato leaves and yellow fruit. The F1 generation all have regular leaves and red fruit. The F1 individuals are then crossed with one another.
Question text
The expected phenotypic ratio for leaf shape and fruit colour genes is 9:3:3:1, if both genes are on different chromosomes and assort independently during gamete formation. The information below represents two sets of data collected from the above cross. Data Set 1 is from a population of 5000 tomato plants and Data Set 2 is from a population of 50 tomato plants.
Phenotypes
Observed Probabilities
Data Set 1(N = 5000)
Data Set 2(N = 50)
Regular Red
0.58
0.050
Regular Yellow
0.16
0.29
Potato Red
0.20
0.050
Potato Yellow
0.060
0.61
A. Compare both data sets to the expected probabilities. Are there any significant differences between the observed results and the expected…
A white F2 plant is allowed to self-fertilize. Of the progeny, 3/4 are white-flowered, and 1/4 are purple-flowered. What is the genotype of the white F2 plant?
Chapter 2 Solutions
Genetics: Analysis and Principles
Ch. 2.1 - 1. Experimental advantages of using pea plants...Ch. 2.1 - The term cross refers to an experiment in which a....Ch. 2.1 - 3. To avoid self-fertilization in his pea plants,...Ch. 2.2 - Prob. 1COMQCh. 2.2 - Prob. 2COMQCh. 2.3 - A pea plant has the genotype rrYy. How many...Ch. 2.3 - A cross is made between a pea plant that is RrYy...Ch. 2.3 - Prob. 3COMQCh. 2.4 - Which of the following would not be observed in a...Ch. 2.4 - Prob. 2COMQ
Ch. 2.5 - A cross is made between AABbCcDd and AaBbccdd...Ch. 2.5 - Prob. 2COMQCh. 2.5 - Prob. 3COMQCh. 2 - 1. Why did Mendel’s work refute the idea of...Ch. 2 - 2. What is the difference between...Ch. 2 - 3. Describe the difference between genotype and...Ch. 2 - 4. With regard to genotypes, what is a...Ch. 2 - 5. How can you determine whether an organism is...Ch. 2 - In your own words, describe Mendels law of...Ch. 2 - Based on genes in pea plants that we have...Ch. 2 - Prob. 8CONQCh. 2 - Do you know the genotype of an individual with a...Ch. 2 - 10. A cross is made between a pea plant that has...Ch. 2 - Prob. 11CONQCh. 2 - 12. Describe the significance of nonparentals with...Ch. 2 - For the following pedigrees, describe what you...Ch. 2 - Ectrodactyly, also known as lobster claw syndrome,...Ch. 2 - Identical twins are produced from the same sperm...Ch. 2 - In cocker spaniels, solid coat color is dominant...Ch. 2 - A cross was made between a white male dog and two...Ch. 2 - 18. In humans, the allele for brown eye color (B)...Ch. 2 - Albinism, a condition characterized by a partial...Ch. 2 - A true-breeding tall plant was crossed to a dwarf...Ch. 2 - 21. For pea plants with the following genotypes,...Ch. 2 - 22. An individual has the genotypeand makes an...Ch. 2 - 23. In people with maple syrup urine disease, the...Ch. 2 - Prob. 24CONQCh. 2 - 25. A true-breeding pea plant with round and Page...Ch. 2 - Prob. 26CONQCh. 2 - 27. What are the expected phenotypic ratios from...Ch. 2 - Prob. 28CONQCh. 2 - Prob. 29CONQCh. 2 - A pea plant that is dwarf with green, wrinkled...Ch. 2 - 31. A true-breeding plant with round and green...Ch. 2 - Wooly hair is a rare dominant trait found in...Ch. 2 - Huntington disease is a rare dominant trait that...Ch. 2 - 34. A woman with achondroplasia (a dominant form...Ch. 2 - 1. Describe three advantages of using pea plants...Ch. 2 - Explain the technical differences between a...Ch. 2 - 3. How long did it take Mendel to complete the...Ch. 2 - 4. For all seven characters described in the data...Ch. 2 - From the point of view of crosses and data...Ch. 2 - 6. As in many animals, albino coat color is a...Ch. 2 - 7. The fungus Melampsora lini causes a disease...Ch. 2 - For Mendels data for the experiment in Figure 2.8,...Ch. 2 - 9. Would it be possible to deduce the law of...Ch. 2 - In fruit flies, curved wings are recessive to...Ch. 2 - A recessive allele in mice results in an unusally...Ch. 2 - Prob. 12EQCh. 2 - Prob. 13EQCh. 2 - Prob. 14EQCh. 2 - 15. A cross was made between two strains of plants...Ch. 2 - A cross was made between two pea plants, TtAa and...Ch. 2 - Consider this four-factor cross: TtRryyAaTtRRYyaa,...
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- A female of genotype a b c + + + produces 100 meiotic tetrads. Of these, 68 show no crossover events. Of the remaining 32, 20 show a crossover between a and b, 10 show a crossover between b and c, and 2 show a double crossover between a and b and between b and c. Of the 400 gametes produced, how many of each of the 8 different genotypes will be produced? Assuming the order a–b–c and the allele arrangement previously shown, what is the map distance between these loci?arrow_forwardIn tomatoes, red fruit is dominant to yellow fruit, and purple stems are dominant to green stems. Thegenes encoding these traits are on different homologous chromosomes. The progeny from a matingconsisted of 305 red fruit, purple stem plants; 328 red fruit, green stem plants; 110 yellow fruit,purple stem plants; and 97 yellow fruit, green stem plants. What would be the genotypic and phenotypic outcome if each parent was self-fertilized?arrow_forwardA red-fruited tomato plant (which is dominant), when crossed with a yellow-fruited one, produces progeny about half of which are red-fruited and half which are yellow fruited. What are the genotypes of the parents?arrow_forward
- The recessive allele s causes Drosophila to have small wings, and the s+ allele causes normal wings. This gene is known to be X linked. If a small-winged male is crossed with a homozygous wild-type female, what ratio of normal to small-winged flies can be expected in each sex in the F1? If F1 flies are intercrossed, what F2 progeny ratios are expected? What progeny ratios are predicted if F1 females are backcrossed with their father?arrow_forwardThe crossing of two orange-flowering plants results in ~2/3 orange-flower progeny and ~1/3 white-flower progeny. The crossing of two orange-flowering F1 plants generates the same progeny ratios as observed for the parental cross, while the crossing of white-flowering F1 plants only produces white-flowering progeny. What is a likely explanation for these results?arrow_forwardAssume that the trihybrid cross AABBrr x aabbRR is made in a plant species. Assume that A and B are dominant alleles, but there is no dominance effect of alleles at the R locus. a) How many different gametes are possible in the F1generation? What are the genotypes of these gametes? b) What is the probability of the parental aabbRR genotype in the F2 progeny? c) What proportion of the F2 progeny would be expected to be homozygous for all three genes?arrow_forward
- Heterozygous round, homozygous green seeded plants were mated with heterozygous yellow, homozygous wrinkled seeded plants. What is the probability of producing a pod of 7 peas with 3 round and green seeds, 2 round and yellow seed, and 2 wrinkled yellow seeds?arrow_forwardA genotypically wild-type fruit fly is crossed to a fly with homozygous recessive mutations in two different genes that result in a wingless and an eyeless phenotype. The F1 generation is 100% phenotypically wild type. Two of the phenotypically wild-type F1 flies are mated and the following offspring are observed in the F2 generation: Wild type: 367 Wingless (wg): 119 Eyeless (ey): 134 Eyeless, wingless (ey; wg): 52 Part 1 Assuming independent assortment, how many F2 offspring would be expected to be homozygous for the wingless mutation but have normal eyes? O224 O126 O 112 O 378 Part 2 How many degrees of freedom are there in the results of this cross? O0 O 1 02 03 O4arrow_forwardA heterozygous pea plant that is tall with yellow seeds, TtGg, is allowed to self-fertilize. What is the probability that an offspring will be either tall with yellow seeds, tall with green seeds or dwarf with yellow seeds? Use the Sum Rule to calculate the probability asked in the problem.arrow_forward
- Two pure-breeding strains of flies are mated, and the F1 are intercrossed. The first strain has curled wings and black bodies. The second strain has straight wings and brown bodies. The F2 progeny are 271 straight wings with brown bodies, 31 curled wings with black bodies, 94 curled wings with brown bodies and 90 straight wings with black bodies. If the F1 were backcrossed to the straight, wing brown bodied parent, what phenotypes would be produced among the progeny? What would be the proportion of each phenotype?arrow_forwardA squash comes in one of three shapes (long, oval, or round) and one of three colors (green, yellow, or white). A cross between long green female squash and round white male squash produced all oval and yellow. What is the the genotype of the parents and F1 progenies? if the F1 progenies were crossed, what is the probability that an F2 offspring will have the same phenotype as the female parent?arrow_forwardPURPLE VESTIGIAL DIHYBRID CROSS In the parental generation, you mate a pure-breeding wild-type female (put/pu+;vg+/vg+) with a pure-breeding purple, vestigial (pu/pu;vg/vg) to produce an F1 generation that is all wild-type (pu*/pu;vg+/vg). Note that the F1 flies are all dihybrid. Next, you mate several F1 dihybrid females (pu*/pu;vg+/vg) with tester males, which are purple, vestigial (pu/pu;vg/vg). The offspring of this dihybrid testcross are: Phenotype Genotype Tester Gamete Dihybrid Gamete Number Wild-type 437 417 77 59 Purple, vestigial Vestigial Purple Copy the table into your notes and derive the dihybrid gametes following the example in the first section. The columns in blue (phenotypes and numbers of offspring) are what you can see and count. The genotypes of the testcross offspring (orange) must be deduced from the phenotypes and knowing that the tester contributed pu vg gametes. Finally, you can deduce the dihybrid gametes (green) by subtracting the tester gamete contribution…arrow_forward
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