Genetics: Analysis and Principles
6th Edition
ISBN: 9781259616020
Author: Robert J. Brooker Professor Dr.
Publisher: McGraw-Hill Education
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 2, Problem 13EQ
Summary Introduction
To review:
The meaning of chi-square value of 1.005.
Introduction:
Chi-squared test is a simple test that explains the data obtained from the genetic crosses which have a unique pattern of inheritance. It is used for solving genetic problems by deducing a hypothesis for the given data. Chi-square is, in fact, a hypothesis testing pattern.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
type
P =
n!
(p)* (q)"*
х! (n - х)!
Practice Problem:
You cross a true-breeding pea plant with red flowers to a true-breeding pea plant with white
flowers. All of your offspring have red flowers. Which gene is dominant? Why? What is the
genotype of your offspring?
You then cross the offspring to each other. What ratio do you expect? Why?
You count 1000 plants and look at their flowers. Your results are as follows:
740 red
260 white
Does this follow a simple Mendelian inheritance pattern? Why or why not?
DADT 2
MEA SUDI
ND D LUT IONS
A genetic engineer was attempting to cross a tiger and
a cheetah. She predicted a phenotypic outcome of the
traits she was observing to be in the following ratio:
4 stripes only: 3 spots only: 9 both stripes and spots.
When the cross was performed and she counted the
individuals she found 50 with stripes only, 41 with
spots only and 85 with both.
What is the computed chi-square value?
А. 3.126
В. 2.415
С. 4.001
D. 1.163
In a genetics experiment on peas, one sample of offspring contained 352 green peas and 474 yellow peas. Based on those results, estimate the probability of getting an
offspring pea that is green. Is the result reasonably close to the value of
4
that was expected?
The probability of getting a green pea is approximately
(Type an integer or decimal rounded to three decimal places as needed.)
Chapter 2 Solutions
Genetics: Analysis and Principles
Ch. 2.1 - 1. Experimental advantages of using pea plants...Ch. 2.1 - The term cross refers to an experiment in which a....Ch. 2.1 - 3. To avoid self-fertilization in his pea plants,...Ch. 2.2 - Prob. 1COMQCh. 2.2 - Prob. 2COMQCh. 2.3 - A pea plant has the genotype rrYy. How many...Ch. 2.3 - A cross is made between a pea plant that is RrYy...Ch. 2.3 - Prob. 3COMQCh. 2.4 - Which of the following would not be observed in a...Ch. 2.4 - Prob. 2COMQ
Ch. 2.5 - A cross is made between AABbCcDd and AaBbccdd...Ch. 2.5 - Prob. 2COMQCh. 2.5 - Prob. 3COMQCh. 2 - 1. Why did Mendel’s work refute the idea of...Ch. 2 - 2. What is the difference between...Ch. 2 - 3. Describe the difference between genotype and...Ch. 2 - 4. With regard to genotypes, what is a...Ch. 2 - 5. How can you determine whether an organism is...Ch. 2 - In your own words, describe Mendels law of...Ch. 2 - Based on genes in pea plants that we have...Ch. 2 - Prob. 8CONQCh. 2 - Do you know the genotype of an individual with a...Ch. 2 - 10. A cross is made between a pea plant that has...Ch. 2 - Prob. 11CONQCh. 2 - 12. Describe the significance of nonparentals with...Ch. 2 - For the following pedigrees, describe what you...Ch. 2 - Ectrodactyly, also known as lobster claw syndrome,...Ch. 2 - Identical twins are produced from the same sperm...Ch. 2 - In cocker spaniels, solid coat color is dominant...Ch. 2 - A cross was made between a white male dog and two...Ch. 2 - 18. In humans, the allele for brown eye color (B)...Ch. 2 - Albinism, a condition characterized by a partial...Ch. 2 - A true-breeding tall plant was crossed to a dwarf...Ch. 2 - 21. For pea plants with the following genotypes,...Ch. 2 - 22. An individual has the genotypeand makes an...Ch. 2 - 23. In people with maple syrup urine disease, the...Ch. 2 - Prob. 24CONQCh. 2 - 25. A true-breeding pea plant with round and Page...Ch. 2 - Prob. 26CONQCh. 2 - 27. What are the expected phenotypic ratios from...Ch. 2 - Prob. 28CONQCh. 2 - Prob. 29CONQCh. 2 - A pea plant that is dwarf with green, wrinkled...Ch. 2 - 31. A true-breeding plant with round and green...Ch. 2 - Wooly hair is a rare dominant trait found in...Ch. 2 - Huntington disease is a rare dominant trait that...Ch. 2 - 34. A woman with achondroplasia (a dominant form...Ch. 2 - 1. Describe three advantages of using pea plants...Ch. 2 - Explain the technical differences between a...Ch. 2 - 3. How long did it take Mendel to complete the...Ch. 2 - 4. For all seven characters described in the data...Ch. 2 - From the point of view of crosses and data...Ch. 2 - 6. As in many animals, albino coat color is a...Ch. 2 - 7. The fungus Melampsora lini causes a disease...Ch. 2 - For Mendels data for the experiment in Figure 2.8,...Ch. 2 - 9. Would it be possible to deduce the law of...Ch. 2 - In fruit flies, curved wings are recessive to...Ch. 2 - A recessive allele in mice results in an unusally...Ch. 2 - Prob. 12EQCh. 2 - Prob. 13EQCh. 2 - Prob. 14EQCh. 2 - 15. A cross was made between two strains of plants...Ch. 2 - A cross was made between two pea plants, TtAa and...Ch. 2 - Consider this four-factor cross: TtRryyAaTtRRYyaa,...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- Shown are F₂ results of a monohybrid cross performed by Mendel. a) Calculate the expected numbers of each type of pods. Full pods Constricted pods Total 882 298 1180 0.84 b) What do these p-values mean with regards to your null hypothesis? (Please choose either reject or fail to reject.)arrow_forwardMendelian Genetics [6F.R]:Question 1 In rabbits, grey fur (G) is dominant to white fur (g) and black eyes (B) are dominant to red eyes (b). A male rabbit with the genotype GgBb is crossed with a female rabbit with the genotype ggbb. What percent of the offspring will have white fur and red eyes? Select one: 25% 50% 100% 0% 1000arrow_forwardKernel color in wheat is controlled by 2 pairs of genes (AABB). Determine the color of each offspring with the following genotypes: (Note: 4 alleles – red; 3 – medium red; 2 – intermediate red; 1 – light red; 0 – white). CAPITAL letters only and with spaces when applicable. AABb - AaBb - AABB - aaBb - aabb -arrow_forward
- This question deals with Mendelian Genetics. Read each part carefully before you answer it. In the following questions, assume green pea pods are dominant over yellow pea pods. a) If a pea plant that is Heterozygous for pod color is crossed with a pea plant with yellow pods, what do you expect to see in the offspring (the f1 generation)? Specifically, what genotypes, what phenotypes, and in what ratios? (Use G for the green pod gene and g for the yellow pod gene.) (It is usually helpful to write out all the possible genotypes and give the phenotype for each genotype before answering the specific question.)arrow_forwardUsing your calculated expected numbers and the following observed numbers for each progeny phenotype, calculate chi-square: 320 short, black, rough hairs 80 long, black, rough hairs Transform the calculated fraction for each phenotype into a number to 2 decimal places, then add and type answer AS NUMBER rounded to one decimal place. 7 2 3 4 % 5 MacBook Pro 6 7 8arrow_forwardWheat kernel color is an additive trait controlled by two genes, gene A and gene B. The A1 and B1 alleles add 1 unit of color to the kernels. The A2 and B2 alleles add 0 units of color to the kernels. Question 1: If you crossed a dihybrid (A1A2 B1B2) individual to a A2A2 B2B2 individual, which of the following phenotypes are possible? a. 0 units (white) b. 1 unit (light pink) c. 2 units (dark pink) d. 3 units (light red) e. 4 units (dark red) Question 2: If you crossed a dihybrid (A1A2 B1B2) individual to a A2A2 B2B2 individual, what is your expected phenotypic ratio? a. 1:2:1 b. 1:1:1:1 c. 9:3:3:1 d. 3:1arrow_forward
- #2 a) If sex and eye colored were viewed as two different phenotypes with male being dominant over female (or vice versa), then Mendelian ratios of a dihybrid cross may explain the ratios that Morgan got. Here is some hypothetical data based on the ratios gotten by Morgan and the expected Mendelian ratios for a dihybrid F1 cross. Perform a Chi-square test (separate scrap paper) with the null hypothesis being that the "Morgan observed ratios" are within chance from the Mendelian ratios. State whether the Chi-square test supports or rejects the null hypothesis and explain. (Be sure to include the X2 value, degrees of freedom, critical value.) Hint: what did Morgan discover? Think about this for your degrees of freedom.* Expected Mendelian Ratios Morgan Observed Ratios 900 Red, male 800 Red, male 300 Red, female 400 Red, female 300 white, male 400 white, male O white, female 100 white, female Terms of Use Support | Schoology Blog | PRIVACY POLICY INarrow_forward# 2 a) If sex and eye colored were viewed as two different phenotypes with male being dominant over female (or vice versa), then Mendelian ratios of a dihybrid cross may explain the ratios that Morgan got. Here is some hypothetical data based on the ratios gotten by Morgan and the expected Mendelian ratios for a dihybrid F1 cross. Perform a Chi-square test (separate scrap paper) with the null hypothesis being that the "Morgan observed ratios" are within chance from the Mendelian ratios. State whether the Chi-square test supports or rejects the null hypothesis and explain. (Be sure t include the X2 value, degrees of freedom, critical value.) Hint: what did Morgan discover? Think about this for your degrees of freedom. * Expected Mendelian Ratios Morgan Observed Ratios 900 Red, male 800 Red, male 300 Red, female 400 Red, female 400 white, male 300 white, maile O white, female 100 white, female Schoology Support | Schoology Blog | PRIVACY POLICY | Terms of Use INTLarrow_forwardGenes A and B are on two different chromosomes. You construct a Punnett Square to to show the expected genotypes in the offspring of a cross between these two genotypes: AaBB x AaBb. What are the dimensions of the smallest Punnett square you can make to show the expected results? (e.g., 2x2, 4x1. Don’t worry about the order of the two numbers if they differ. That is, 4x8 is the same as 8x4)arrow_forward
- For many students, calculating the chi square value is the most challenging part of conducting a chi square test so it is important to practice. Consider the following information: An F1 tall, round seed pea plant is crossed with a dwarf, wrinkled seed pea plant. The following offspring are observed: Tall, round: 510 Tall, wrinkled: 495 Dwarf, round: 490 Dwarf, wrinkled: 505 a. What is the expected phenotype ratio? #:# or #:#:#:#, depending on what you think the answer is. b. What is the calculated chi-square value? Format your answer with 1 significant digit (i.e. 0.#). c. What is the critical chi-square value from the table provided in the book at the P=0.05 level of significance? Enter the number exactly as shown in this table.arrow_forwardI have a vial of F2 offspring resulting from a two-generation cross between true-breeding wildtype females and true-breeding pink-bodied males. I scored F2 phenotypes for a total of 120 flies and obtain the following data: Based on the above observed data in the chart, determine the expected number of flies for the following three scenarios provided in a-c below. Show work for each calculation. 2) The mutant allele is dominant and is located on an autosomearrow_forwardOn the basis of Mendel’s observations (i.e. Mendelian patterns), predict the results from the following crosses with peas. Show the results in terms of genotypes, phenotypes, and their proportions in the offspring. The progeny of a tall (dominant and homozygous) variety crossed with a dwarf variety. The progeny of (a) self-fertilized. The progeny from (a) crossed with the original tall parent. The progeny of (a) crossed with the original dwarf parent.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Human Anatomy & Physiology (11th Edition)BiologyISBN:9780134580999Author:Elaine N. Marieb, Katja N. HoehnPublisher:PEARSONBiology 2eBiologyISBN:9781947172517Author:Matthew Douglas, Jung Choi, Mary Ann ClarkPublisher:OpenStaxAnatomy & PhysiologyBiologyISBN:9781259398629Author:McKinley, Michael P., O'loughlin, Valerie Dean, Bidle, Theresa StouterPublisher:Mcgraw Hill Education,
- Molecular Biology of the Cell (Sixth Edition)BiologyISBN:9780815344322Author:Bruce Alberts, Alexander D. Johnson, Julian Lewis, David Morgan, Martin Raff, Keith Roberts, Peter WalterPublisher:W. W. Norton & CompanyLaboratory Manual For Human Anatomy & PhysiologyBiologyISBN:9781260159363Author:Martin, Terry R., Prentice-craver, CynthiaPublisher:McGraw-Hill Publishing Co.Inquiry Into Life (16th Edition)BiologyISBN:9781260231700Author:Sylvia S. Mader, Michael WindelspechtPublisher:McGraw Hill Education
Human Anatomy & Physiology (11th Edition)
Biology
ISBN:9780134580999
Author:Elaine N. Marieb, Katja N. Hoehn
Publisher:PEARSON
Biology 2e
Biology
ISBN:9781947172517
Author:Matthew Douglas, Jung Choi, Mary Ann Clark
Publisher:OpenStax
Anatomy & Physiology
Biology
ISBN:9781259398629
Author:McKinley, Michael P., O'loughlin, Valerie Dean, Bidle, Theresa Stouter
Publisher:Mcgraw Hill Education,
Molecular Biology of the Cell (Sixth Edition)
Biology
ISBN:9780815344322
Author:Bruce Alberts, Alexander D. Johnson, Julian Lewis, David Morgan, Martin Raff, Keith Roberts, Peter Walter
Publisher:W. W. Norton & Company
Laboratory Manual For Human Anatomy & Physiology
Biology
ISBN:9781260159363
Author:Martin, Terry R., Prentice-craver, Cynthia
Publisher:McGraw-Hill Publishing Co.
Inquiry Into Life (16th Edition)
Biology
ISBN:9781260231700
Author:Sylvia S. Mader, Michael Windelspecht
Publisher:McGraw Hill Education
How to solve genetics probability problems; Author: Shomu's Biology;https://www.youtube.com/watch?v=R0yjfb1ooUs;License: Standard YouTube License, CC-BY
Beyond Mendelian Genetics: Complex Patterns of Inheritance; Author: Professor Dave Explains;https://www.youtube.com/watch?v=-EmvmBuK-B8;License: Standard YouTube License, CC-BY