Genetics: From Genes to Genomes
6th Edition
ISBN: 9781259700903
Author: Leland Hartwell Dr., Michael L. Goldberg Professor Dr., Janice Fischer, Leroy Hood Dr.
Publisher: McGraw-Hill Education
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Textbook Question
Chapter 13, Problem 8P
A series of chromosomal mutations in Drosophila were used to map the javelin gene, which affects bristle shape, and the henna gene, which affects eye pigmentation. Both the javelin and the henna mutant alleles are recessive to wild type. The chromosomal mutations are all rearrangements of chromosome 3. A diagram of chromosome 3 follows: 3L is the left arm, and 3R is the right arm. The DNA sequences are numbered from bp #1 to bp #24, 598, 654 on 3L, and bp #1 to bp #27, 929, 329 on 3R.
The chromosomal breakpoints for six chromosome 3 rearrangements are indicated in the following table. The exact breakpoints of each chromosomal mutation have been determined using PCR and DNA sequencing. For example, deletion A has one breakpoint just after bp #6, 000, 587, and another just after bp #6, 902, 063 on the left arm of chromosome 3.
Flies with a chromosome containing one of these six rearrangements (deletions or inversions) were mated to flies homozygous for both javelin and henna. The
| a. | Using these data, what can you conclude about the locations of the javelin and henna genes on chromosome 3? |
| b. | For each chromosome rearrangement, draw on a diagram of a normal chromosome 3 the positions and 5′-to-3′ orientations of PCR primer pairs that could be used to amplify an approximately 100 bp region containing the rearrangement breakpoints. |
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
The locations of six deletions have been mapped to a Drosophila chromosome, as shown in the following deletion map. Recessive mutations a, b, c, d, e, and f are known to be located in the same region as the deletions, but the order of the mutations on the chromosome is not known.
One of the X chromosomes in a particular Drosophila female had a normal order of genes but carried recessive alleles of the genes for yellow body color (y), vermilion eye color (v), and forked bristles (f), as well as the dominant X-linked Bar eye mutation (B). Her other X chromosome carried the wild-type alleles of all four genes, but the region including y, v, and f (but not B) was inverted with respect to the normal order of genes. This female was crossed to a wild-type male as diagrammed here.
1. Draw the meiotic prophase I chromosomes with maximal pairing from the inversion heterozygous female.
2. (continued) When a crossover occurs between v and f, please draw the resulting chromosomes in four gametes.
ARVC5 is a disorder characterized by the replacement of healthy heart tissue with fatty fibrous tissue. Recent research has discovered the
mutated gene that causes the disorder is on chromosome 3. People who have the mutation have a GCG triplet instead of the normal ACA triplet.
The following is a section of a gene on chromosome 3:
GGT GCG ACA ATT
1. Complete the following table.
AA
DNA sense strand
DNA antisense strand GGT GCG ACA ATT
mRNA
tRNA
2. Indicate the change in the amino acid sequence resulting from the mutation in the gene described above.,
B I
123
|||
14
E
GO
LG
US X₂
x²
Chapter 13 Solutions
Genetics: From Genes to Genomes
Ch. 13 - For each of the terms in the left column, choose...Ch. 13 - Prob. 2PCh. 13 - For each of the following types of chromosomal...Ch. 13 - For the following types of chromosomal...Ch. 13 - One of the X chromosomes in a particular...Ch. 13 - A diploid strain of yeast was made by mating a...Ch. 13 - The two graphs that follow represent genomic...Ch. 13 - A series of chromosomal mutations in Drosophila...Ch. 13 - Indicate which of the four major classes of...Ch. 13 - The recessive, X-linked z1 mutation of the...
Ch. 13 - Genes a and b are 21 m.u. apart when mapped in...Ch. 13 - In the following group of figures, the pink lines...Ch. 13 - Three strains of Drosophila Bravo, X-ray, and...Ch. 13 - Two yeast strains were mated and sporulated...Ch. 13 - Suppose a haploid yeast strain carrying two...Ch. 13 - In the mating between two haploid yeast strains...Ch. 13 - During ascus formation in Neurospora, any...Ch. 13 - In the following figure, black and pink lines...Ch. 13 - In Drosophila, the gene for cinnabar eye color is...Ch. 13 - Semisterility in corn, as seen by unfilled ears...Ch. 13 - A promising biological method for insect control...Ch. 13 - Prob. 23PCh. 13 - a. Among the progeny of a self-fertilized...Ch. 13 - Duchenne muscular dystrophy DMD is caused by a...Ch. 13 - WHIM syndrome is a disease of the immune system...Ch. 13 - Explain how transposable elements can cause the...Ch. 13 - The Drosophila genome normally harbors about 40 P...Ch. 13 - Drosophila P elements were discovered because of a...Ch. 13 - Flies homozygous for mutant alleles of a...Ch. 13 - Fred and Mary have a child named Bob. The genomic...Ch. 13 - Uniparental disomy is a rare phenomenon in which...Ch. 13 - Among adults with Turner syndrome, it has been...Ch. 13 - In Neurospora, his2 mutants require the amino acid...Ch. 13 - Human geneticists interested in the effects of...Ch. 13 - The incidence of Down syndrome will be very high...Ch. 13 - The Drosophila chromosome 4 is extremely small;...Ch. 13 - Down syndrome is usually caused by having a...Ch. 13 - Common red clover, Trifolium pratense, is a...Ch. 13 - The numbers of chromosomes in the somatic cells of...Ch. 13 - Prob. 41PCh. 13 - Somatic cells in organisms of a particular diploid...Ch. 13 - An allotetraploid species has a genome composed of...Ch. 13 - Prob. 44PCh. 13 - Chromosomes normally associate during meiosis I as...Ch. 13 - Using whole-genome sequencing, how could you...Ch. 13 - Prob. 47PCh. 13 - Prob. 48PCh. 13 - Seedless watermelons that you find in the...Ch. 13 - The names of hybrid animals are usually themselves...Ch. 13 - While most animals cannot tolerate polyploidy,...Ch. 13 - What characteristic property of translocations...Ch. 13 - Prob. 53PCh. 13 - In the accompanying figure, the top and bottom...Ch. 13 - Prob. 55PCh. 13 - The accompanying figure shows idiograms of human...Ch. 13 - Prob. 57P
Additional Science Textbook Solutions
Find more solutions based on key concepts
Why is it unlikely that two neighboring water molecules would be arranged like this?
Campbell Biology (10th Edition)
Identify each of the following reproductive barriers as prezygotic or postzygotic. a. One lilac species lives o...
Campbell Essential Biology with Physiology (5th Edition)
Describe Mendels conclusions about how traits are passed from generation to generation.
Concepts of Genetics (12th Edition)
Some people consider Pasteur or Koch to be the Father of Microbiology, rather than Leeuwenhoek. Why might they ...
Microbiology with Diseases by Body System (5th Edition)
Describe the evolution of mammals, tracing their synapsid lineage from early amniote ancestors to true mammals....
Loose Leaf For Integrated Principles Of Zoology
Sea turtles have disappeared from many regions, and one way of trying to save them is to reintroduce them to ar...
Marine Biology (Botany, Zoology, Ecology and Evolution)
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- One of the X chromosomes in a particular Drosophila female had a normal order of genes but carried recessive alleles of the genes for yellow body color (y), vermilion eye color (v), and forked bristles (f), as well as the dominant X-linked Bar eye mutation (B). Her other X chromosome carried the wild-type alleles of all four genes, but the region including y+, v+, and f+ (but not B+) was inverted with respect to the normal order of genes. This female was crossed to a wild- type male in the cross diagrammed her. The cross produced the following male offspring:* table in figure a. Why are there no male offspring with the allele combinations y v f+, v+ v+ f, y v+ f+, or y+ v f (regardless of the allele of the Bar eye gene)?b. What kinds of crossovers produced the y v f b+ and v+ y+ f+ B offspring? Can you determine any genetic distances from these classed of progeny?c. What kinds of crossovers produced the y+ v f+ B+ and y v+ f B offspring?arrow_forwardIn tomato plants, the genes for fruit colour (C), fruit fructose content (F), fruit length (L), and plant height (H) are all found on chromosome 4. Map distances between the four genes are shown below. Genes Distance in Map Units H and F 40 F and L 12 C and F 75 L and C 87 L and H 52 Sketch and label a gene map to identify the order of the four genes on chromosome 1 in tomato plants.arrow_forwardOne of the X chromosomes in a particular Drosophila female had a normal order of genes but carried recessive alleles of the genes for yellow body color (y), vermilion eye color (v), and forked bristles (f), as well as the dominant X-linked Bar eye mutation (B). Her other X chromosome carried the wild-type alleles of all four genes, but the region including y+, v+, and f+ (but not B+) was inverted with respect to the normal order of genes. This female was crossed to a wild-type male in the cross diagrammed her. The cross produced the following male offspring: Y v f B 48 y+ v+ f+ B+ 45 y v f B+ 11 y+ v+ f+ B 8 y v f B 1 y+ v+ f+ B+ 1 a. Why are there no male offspring with the allele combinations y v f+, v+ v+ f, y v+ f+, or y+ v f (regardless of the allele of the Bar eye gene)? b.What kinds of crossovers produced the y v f b+ and v+ y+ f+ B offspring? Can you determine any genetic distances from these classed of progeny? c. What kinds of crossovers produced the…arrow_forward
- The beach mouse (Peromyscus polionotus) is a small rodent found in the southeastern United States. Coat color in the beach mouse is variable, from dark brown to blonde (Figure 1). A pigment called eumelanin is responsible for some of the diversity in mouse coat color. The MC1R gene, located on chromosome 8, plays a major role in the synthesis of eumelanin. There are two alleles of MC1R: R allele. Results in a functional MC1R protein that leads to stimulation of pigment production. This allele is found in dark colored mice. C allele. Results in a non-functional MC1R protein. Pigment production is, as a result, not stimulated. This allele is found in light colored mice. Figure 1. Beach mouse with light fur (left) and dark (right). These mice are hunted by visual predators like owls and fox. The distribution of coat color is not random. Beach mice with dark fur are found further inland, on dark brown soils while mice with light fur are found on beaches, where the sand is…arrow_forwardA male Drosophila with wild-type phenotype is discovered to have only seven chromosomes, whereas normally 2n = 8. Close examination reveals that one member of chromosome IV (the smallest chromosome) is attached to (translocated to) the end of chromosome II. If this male mates with a female with a normal chromosome composition who is homozygous for the recessive chromosome IV mutation eyeless (genotype = ee), what would be the eye genotypes, eye phenotypes, and total number of chromosomes in all potential offspring if the male is homozygous for the wild-type allele (EE)? put a table for punnet squarearrow_forwardThe beach mouse (Peromyscus polionotus) is a small rodent found in the southeastern United States. Coat color in the beach mouse is variable, from dark brown to blonde (Figure 1). A pigment called eumelanin is responsible for some of the diversity in mouse coat color. The MC1R gene, located on chromosome 8, plays a major role in the synthesis of eumelanin. There are two alleles of MC1R: R allele. Results in a functional MC1R protein that leads to stimulation of pigment production. This allele is found in dark colored mice. C allele. Results in a non-functional MC1R protein. Pigment production is, as a result, not stimulated. This allele is found in light colored mice. Figure 1. Beach mouse with light fur (left) and dark (right). These mice are hunted by visual predators like owls and fox. The distribution of coat color is not random. Beach mice with dark fur are found further inland, on dark brown soils while mice with light fur are found on beaches, where the sand is light brown.…arrow_forward
- A male Drosophila with wild-type phenotype is discovered to have only seven chromosomes, whereas normally 2n = 8. Close examination reveals that one member of chromosome IV (the smallest chromosome) is attached to (translocated to) the end of chromosome II. If this male mates with a female with a normal chromosome composition who is homozygous for the recessive chromosome IV mutation eyeless (genotype = ee), what would be the eye genotypes, eye phenotypes, and total number of chromosomes in all potential offspring if the male is homozygous for the wild-type allele (EE)?arrow_forwardIn Drosophila, the genes for eye color, wing shape, and wing length are located on chromosome II. Purple eyes (pr), arc bent wings (a), and vestigial wings (vg) are the mutant forms of the wild type traits red eyes, straight wings, and long wings, respectively. You've discovered some data in your genetics laboratory which indicates that the distance between vg and pr is 12.5 m.u., the distance between a and pr is 44.7 m.u., and the distance between a and vg is 32.2 m.u. From this information, deduce the order of these genes on chromosome II and identify which gene is in the middle. A. a B. pr C. not enough information to tell D. vgarrow_forwardQUESTION 11 The location of five deletions have been mapped to a Drosophila chromosome, as shown in the following deletion map. Recessive mutations a, b, c, d and e are known to be located in the same region as the deletions but the order of the mutations on the chromosome is not known. Drosophila Chromosome Deletion 1 Deletion 2 Deletion 3 Deletion 4 Deletion 5 When flies homozygous for the recessive mutation are crossed with flies heterozygous for the deletions, the following results are obtained in which "m" represents recovery of flies with a mutant phenotype and "+" represents recovery of only flies with a wildtype phenotype. Use the data from the table below to determine the order of the genes (a-e) on the chromosome. Mutants Deletions a b C d e 1 + + + + m 2 + m + m 3 m m m m 4 + + m + + 5 m + m m + What is the gene order for these five genes? Please do not separate the letters representing the mutations with spaces or punctuation (e.g. LMNOP)arrow_forward
- Colchicine is a chemical mutagen that inhibits the spindle formation and prevents anaphase, which retains the cell’s single restitution nucleus (doubled chromosome number). Suppose that an onion (2n=16) is subjected to three consecutive rounds of colchicine treatment, what will be the resulting chromosome number of the treated onion?arrow_forwardIn 1983, a sheep farmer in Oklahoma noticed in his flock a ram that possessed increased muscle mass in his hindquarters. Many of the offspring of this ram possessed the same trait, which became known as the callipyge phenotype (callipyge is Greek for “beautiful buttocks”). The mutation that caused the callipyge phenotype was eventually mapped to a position on the sheep chromosome 18. When the male callipyge offspring of the original mutant ram were crossed with normal females, they produced the following progeny: 14 male callipyge, 14 female callipyge, 14 male normal, and 14 female normal. When the female callipyge offspring of the original mutant ram were crossed with normal males, all of the offspring were normal. Analysis of the chromosomes of these offspring of callipyge females showed that half of them received a chromosome 18 with the allele encoding callipyge from their mother. Propose an explanation for the inheritance of the allele for callipyge. How might you test your…arrow_forwardRice has a chromosome number of 2n = 24. If different euploids and aneuploids are available in rice, identify the chromosomal mutation, chromosome configuration, chromosome number, and/or type of gametes in each of the mutations below. Example: For 10B, the answer is “10 II + 2 I”arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Human Anatomy & Physiology (11th Edition)BiologyISBN:9780134580999Author:Elaine N. Marieb, Katja N. HoehnPublisher:PEARSON
Biology 2eBiologyISBN:9781947172517Author:Matthew Douglas, Jung Choi, Mary Ann ClarkPublisher:OpenStax
Anatomy & PhysiologyBiologyISBN:9781259398629Author:McKinley, Michael P., O'loughlin, Valerie Dean, Bidle, Theresa StouterPublisher:Mcgraw Hill Education,
Molecular Biology of the Cell (Sixth Edition)BiologyISBN:9780815344322Author:Bruce Alberts, Alexander D. Johnson, Julian Lewis, David Morgan, Martin Raff, Keith Roberts, Peter WalterPublisher:W. W. Norton & Company
Laboratory Manual For Human Anatomy & PhysiologyBiologyISBN:9781260159363Author:Martin, Terry R., Prentice-craver, CynthiaPublisher:McGraw-Hill Publishing Co.
Inquiry Into Life (16th Edition)BiologyISBN:9781260231700Author:Sylvia S. Mader, Michael WindelspechtPublisher:McGraw Hill Education
Human Anatomy & Physiology (11th Edition)
Biology
ISBN:9780134580999
Author:Elaine N. Marieb, Katja N. Hoehn
Publisher:PEARSON
Biology 2e
Biology
ISBN:9781947172517
Author:Matthew Douglas, Jung Choi, Mary Ann Clark
Publisher:OpenStax
Anatomy & Physiology
Biology
ISBN:9781259398629
Author:McKinley, Michael P., O'loughlin, Valerie Dean, Bidle, Theresa Stouter
Publisher:Mcgraw Hill Education,
Molecular Biology of the Cell (Sixth Edition)
Biology
ISBN:9780815344322
Author:Bruce Alberts, Alexander D. Johnson, Julian Lewis, David Morgan, Martin Raff, Keith Roberts, Peter Walter
Publisher:W. W. Norton & Company
Laboratory Manual For Human Anatomy & Physiology
Biology
ISBN:9781260159363
Author:Martin, Terry R., Prentice-craver, Cynthia
Publisher:McGraw-Hill Publishing Co.
Inquiry Into Life (16th Edition)
Biology
ISBN:9781260231700
Author:Sylvia S. Mader, Michael Windelspecht
Publisher:McGraw Hill Education
Genome Annotation, Sequence Conventions and Reading Frames; Author: Loren Launen;https://www.youtube.com/watch?v=MWvYgGyqVys;License: Standard Youtube License