Genetics: From Genes to Genomes
6th Edition
ISBN: 9781259700903
Author: Leland Hartwell Dr., Michael L. Goldberg Professor Dr., Janice Fischer, Leroy Hood Dr.
Publisher: McGraw-Hill Education
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Chapter 13, Problem 33P
Among adults with Turner syndrome, it has been found that a very high proportion are genetic mosaics. These are of two types: In some individuals, the majority of cells are XO, but a minority of cells are XX. In other Turner individuals, the majority of cells are XO, but a minority of cells are XY. Explain how these two patterns of somatic mosaics could arise.
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Chapter 13 Solutions
Genetics: From Genes to Genomes
Ch. 13 - For each of the terms in the left column, choose...Ch. 13 - Prob. 2PCh. 13 - For each of the following types of chromosomal...Ch. 13 - For the following types of chromosomal...Ch. 13 - One of the X chromosomes in a particular...Ch. 13 - A diploid strain of yeast was made by mating a...Ch. 13 - The two graphs that follow represent genomic...Ch. 13 - A series of chromosomal mutations in Drosophila...Ch. 13 - Indicate which of the four major classes of...Ch. 13 - The recessive, X-linked z1 mutation of the...
Ch. 13 - Genes a and b are 21 m.u. apart when mapped in...Ch. 13 - In the following group of figures, the pink lines...Ch. 13 - Three strains of Drosophila Bravo, X-ray, and...Ch. 13 - Two yeast strains were mated and sporulated...Ch. 13 - Suppose a haploid yeast strain carrying two...Ch. 13 - In the mating between two haploid yeast strains...Ch. 13 - During ascus formation in Neurospora, any...Ch. 13 - In the following figure, black and pink lines...Ch. 13 - In Drosophila, the gene for cinnabar eye color is...Ch. 13 - Semisterility in corn, as seen by unfilled ears...Ch. 13 - A promising biological method for insect control...Ch. 13 - Prob. 23PCh. 13 - a. Among the progeny of a self-fertilized...Ch. 13 - Duchenne muscular dystrophy DMD is caused by a...Ch. 13 - WHIM syndrome is a disease of the immune system...Ch. 13 - Explain how transposable elements can cause the...Ch. 13 - The Drosophila genome normally harbors about 40 P...Ch. 13 - Drosophila P elements were discovered because of a...Ch. 13 - Flies homozygous for mutant alleles of a...Ch. 13 - Fred and Mary have a child named Bob. The genomic...Ch. 13 - Uniparental disomy is a rare phenomenon in which...Ch. 13 - Among adults with Turner syndrome, it has been...Ch. 13 - In Neurospora, his2 mutants require the amino acid...Ch. 13 - Human geneticists interested in the effects of...Ch. 13 - The incidence of Down syndrome will be very high...Ch. 13 - The Drosophila chromosome 4 is extremely small;...Ch. 13 - Down syndrome is usually caused by having a...Ch. 13 - Common red clover, Trifolium pratense, is a...Ch. 13 - The numbers of chromosomes in the somatic cells of...Ch. 13 - Prob. 41PCh. 13 - Somatic cells in organisms of a particular diploid...Ch. 13 - An allotetraploid species has a genome composed of...Ch. 13 - Prob. 44PCh. 13 - Chromosomes normally associate during meiosis I as...Ch. 13 - Using whole-genome sequencing, how could you...Ch. 13 - Prob. 47PCh. 13 - Prob. 48PCh. 13 - Seedless watermelons that you find in the...Ch. 13 - The names of hybrid animals are usually themselves...Ch. 13 - While most animals cannot tolerate polyploidy,...Ch. 13 - What characteristic property of translocations...Ch. 13 - Prob. 53PCh. 13 - In the accompanying figure, the top and bottom...Ch. 13 - Prob. 55PCh. 13 - The accompanying figure shows idiograms of human...Ch. 13 - Prob. 57P
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- Given the karyotype shown at right, is this a male or a female? Normal or abnormal? What would the phenotype of this individual be?arrow_forwardWild-type strains of the haploid fungus Neurospora canmake their own tryptophan. An abnormal allele td renders the fungus incapable of making its own tryptophan.An individual of genotype td grows only when its medium supplies tryptophan. The allele su assorts independently of td; its only known effect is to suppress the tdphenotype. Therefore, strains carrying both td and su donot require tryptophan for growth.a. If a td ; su strain is crossed with a genotypically wildtype strain, what genotypes are expected in the progenyand in what proportions?b. What will be the ratio of tryptophan-dependent totryptophan-independent progeny in the cross of part a?arrow_forwardFemales heterozygous for the recessive second chromosome mutations px, sp, and cn are mated to a male homozygous for all three mutations. The offspring are as follows: Must show all work 1.) What gene is in the middle? and what are the map distances between the genes in centimorgans? 2.) What is the interference?arrow_forward
- Three autosomal recessive mutations in yeast, all producing the same phenotype (m1, m2, and m3), are subjected to complementation analysis. Of the results shown below, which, if any, are alleles of one another? Predict the results of the cross that is not shown—that is, m2 * m3. Cross 1: m1 * m24 F1: all wild-type progeny Cross 2: m1 * m34 F1: all mutant progenyarrow_forwardIn corn, male sterility is controlled by maternal cytoplasmic elements. This phenotype renders the male part of corn plants (i.e. the tassel) unable to produce fertile pollen; the female parts, however, remain receptive to pollination by pollen from male-fertile corn plants. However, the presence of a nuclear fertility restorer gene F restores fertility to male-sterile lines. Using the following color-coded circles, simulate the crosses indicated below. Put the illustrations of crosses in the spaces provided. Be sure to include in the labels the genotypes and phenotypes of the offspring in each cross. Big light green circle - male-sterile cytoplasm Big orange circle - male-fertile cytoplasm Small orange circle - FF nucleus Small half-light green-half-orange circle - Ff nucleus Small light-green circle - ff nucleusarrow_forwardA Neurospora colony at the edge of a plate seemed to be sparse (low density) in comparison with the other colonies on the plate. This colony was thought to be a possible mutant, and so it was removed and crossed with a wild type of the opposite mating type. From this cross, 100 ascospore progeny were obtained. None of the colonies from these ascospores was sparse, all appearing to be normal. What is the simplest explanation of this result? How would you test your explanation? (Note: Neurospora is haploid.)arrow_forward
- Chlamydomonas, a eukaryotic green alga, may be sensitive to the antibiotic erythromycin, which inhibits protein synthesis in bacteria. There are two mating types in this alga, mt+ and mt-. If an mt+ cell sensitive to the antibiotic is crossed with an mt- cell that is resistant, all progeny cells are sensitive. The reciprocal cross (mt+ resistant and mt- sensitive) yields all resistant progeny cells. Assuming that the mutation for resistance is in the chloroplast DNA, what can you conclude from the results of these crosses?arrow_forwardA couple planning their family are aware that through the past three generations on the husband’s side a substantial number of stillbirths have occurred and several malformed babies were born who died early in childhood. The wife has studied genetics and urges her husband to visit a genetic counseling clinic, where a complete karyotype-banding analysis is performed. Although the tests show that he has a normal complement of 46 chromosomes, banding analysis reveals that one member of the chromosome 1 pair (in group A) contains an inversion covering 70 percent of its length. The homolog of chromosome 1 and all other chromosomes show the normal banding sequence. (a) How would you explain the high incidence of past stillbirths? (b) What can you predict about the probability of abnormality/ normality of their future children? (c) Would you advise the woman that she will have to bring each pregnancy to term to determine whether the fetus is normal? If not, what else can you suggest?arrow_forwardList two factors that affect the type and severity of abnormalities in an individual who is an aneuploid mosaic.arrow_forward
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