Microbiology: An Evolving Science (Fourth Edition)
4th Edition
ISBN: 9780393615098
Author: John W. Foster, Joan L. Slonczewski
Publisher: W. W. Norton & Company
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Chapter 8.3, Problem 3TQ
Summary Introduction
To review:
The study of changed gene expression due to mutation.
Introduction:
Translation is the process of synthesis of proteins from an mRNA (messenger ribonucleic acid) template. Information is present in the form of a sequence of
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The diagram below represents the tryptophan operon with the trp leader mRNA transcript enlarged to represent the AUG translation start codon, two consecutive tryptophan amino acid
codons (UGGUGG), and 4 regions (1, 2, 3, and 4) that base pair to form different hairpin-loop structures in the mRNA leader region. Suppose a mutant bacteria has region
3 of the trp operon attenuator region mutated so that it cannot base pair normally. Would the bacteria grow in the absence of the amino acid tryptophan?
(hint: in order for bacteria to grow in absence of tryptophan it should be able to synthesize its own tryptophan)
Leader region
trpE
trpD
trpC
trpB
trpA
DNA
5'
3'
Transcription
trp leader sequence MRNA
AUG
UGGUGG
UUUUUU
1 2
3
(tryptophan
codons)
There is insufficient information to answer the question.
Yes
No
O O
The diagram below represents the tryptophan operon with the trp leader mRNA transcript enlarged to represent the AUG translation start codon, two consecutive
tryptophan amino acid codons (UGGUGG), and 4 regions (1, 2, 3, and 4) that base pair to form different hairpin-loop structures in the MRNA leader region. Suppose a
mutant bacteria has region
4 of the trp operon attenuator region mutated so that it cannot base pair normally. Would the bacteria grow in the absence of the amino acid tryptophan?
(hint: in order for bacteria to grow in absence of tryptophan it should be able to synthesize its own tryptophan)
Lead&r region
trpE
trpD
trpC
trpB
trpA
DNA
5'
3'
Transcription
trp leader sequence MRNA
UGGUGG
1
(tryptophan
codons)
AUG
UUUUUU
No
There is insutficient information to answer the question.
O Yes
The lac operon of E. coli controls the expression of genes that code for enzymes involved in lactose metabolism. Mutations to various regions of the lac operon have been discovered which affect both the control of gene expression and the function of the gene products. These mutations include:
I - = produces a repressor protein that cannot bind to the operator region
IS = produces a repressor protein that cannot be removed from the operator region
OC = cannot bind a repressor protein
Z - = produces a defective (non-functioning) β-galactosidase enzyme
+ = wild type
Detail the functionality of the lac operon under the following genetic and cellular conditions. You do not need to consider the role of CAP in your analysis.
Genes
Repressed (yes/no)
Constitutive (yes/no)
I+ OC Z+
I+ O+ Z+
(Lactose
present)
I- O+ Z+
Chapter 8 Solutions
Microbiology: An Evolving Science (Fourth Edition)
Ch. 8.1 - Prob. 1TQCh. 8.1 - Prob. 2TQCh. 8.1 - Prob. 3TQCh. 8.3 - Prob. 1TQCh. 8.3 - Prob. 2TQCh. 8.3 - Prob. 3TQCh. 8.3 - Prob. 4TQCh. 8.3 - Prob. 5TQCh. 8.3 - Prob. 6TQCh. 8.3 - Prob. 7TQ
Ch. 8.3 - Prob. 8TQCh. 8.6 - Prob. 1TQCh. 8 - Prob. 1RQCh. 8 - Prob. 2RQCh. 8 - Prob. 3RQCh. 8 - Prob. 4RQCh. 8 - Prob. 5RQCh. 8 - Prob. 6RQCh. 8 - Prob. 7RQCh. 8 - Prob. 8RQCh. 8 - Prob. 9RQCh. 8 - Prob. 10RQCh. 8 - Prob. 11RQCh. 8 - Prob. 12RQCh. 8 - Prob. 13RQCh. 8 - Prob. 14RQCh. 8 - Prob. 15RQCh. 8 - Prob. 16RQCh. 8 - Prob. 17RQCh. 8 - Prob. 1TQCh. 8 - Prob. 2TQCh. 8 - Prob. 3TQ
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- The lac operon of E. coli controls the expression of genes that code for enzymes involved in lactose metabolism. Mutations to various regions of the lac operon have been discovered which affect both the control of gene expression and the function of the gene products. These mutations include: I - = produces a repressor protein that cannot bind to the operator region IS = produces a repressor protein that cannot be removed from the operator region OC = cannot bind a repressor protein Z - = produces a defective (non-functioning) β-galactosidase enzyme + = wild type Detail the functionality of the lac operon under the following genetic and cellular conditions. You do not need to consider the role of CAP in your analysis. Genes Repressed (yes/no) Constitutive (yes/no) IS O+ Z+ IS OC Z+arrow_forwardThe lac operon consists of three structural genes, lacZ, lacY and lacA that are transcribed as a single polycistronic mRNA. You are given a new strain of Escherichia coli with the following lac operon genotype: p+0°Z•Y*A +// P*O*Z*Y+ A- (i) Explain how the lac I gene affects gene expression. (ii) Explain the function of the lacP in the bacterial operon. (iii) Which part of the lac operon is cis-dominant? Explain.arrow_forwardHow will transcription of the E. coli trp (tryptophan) operon be affected by the following manipulations of the leader region of the trp mRNA?(a) Increasing the distance (number of bases) between the leader peptide gene and region 2(b) Increasing the distance between region 2 and region 3(c) Removing region 4(d) Changing several nucleotides in region 3 so that in can base pair with region 4 but not with region 2arrow_forward
- In the regulation of the tryophan operon in bacteria, the co-occurence of transcription and translation plays a key role regulating full activation of operon expression. Diagram and explain how during the conditions of high tryptophan concentration this system regulates the expression of genes in the operon.arrow_forwardConsider the lac operon of E. coli. Specifically, explain the following: a. Describe the overall chromosomal structure/organization of the operon, indicating the location and function of the regulatory regions and the structural genes. b. Is lac a catabolic or anabolic pathway? Explain. Is the operon inducible or repressible? Explain. c. Describe the mechanisms involved in negative control & positive controlarrow_forwardYou can determine the regulation of an unknown operon based on descriptions like those in the table below. For each row, choose whether the fact would suggest positive or negative or inducible or repressible regulation and indicate your answer with an X in the column. Only one X should appear in each row. In the presence of the signal, the structural genes are expressed. In the presence of the signal, the structural genes are not expressed. In the absence of the signal, the structural genes are expressed. In the absence of the signal, the structural genes are not expressed. The binding of the regulatory protein to the operon results in structural gene expression. The binding of the regulatory protein to the operon prevents structural gene expression. A mutation in the regulatory protein results in constitutive expression of the structural genes. A mutation in the regulatory protein results in no or low expression of the structural genes. Positive? Negative? Inducible? Repressible?arrow_forward
- Bacterial DNA containing an operon encoding three enzymes is introduced into chromosomal DNA in yeast (a eukaryote) in such a way that it is properly flanked by a promoter and a transcriptional terminator. The bacterial DNA is transcribed and the RNA correctly processed, but only the protein nearest the promoter is produced. Can you suggest why?arrow_forwardThe trp operon in E. coli encodes enzymes essential for the biosynthesis of tryptophan. In the operon, trpR gene encodes the repressor. A trpR repressor cannot bind tryptophan. The trpO is the operator. trpA encodes the enzyme tryptophan synthetase. For the enzyme (A), indicate with a + or-whether or not it is made when there is tryptophan and when there is no tryptophan. Without Tryptophan With Tryptophan R'O A /R* O' A R'O' A/R* Oʻ A R*OA/R' O Aarrow_forwardBob determines that Red/pink protein is synthesized at much higher amounts than the Brown protein; Bob thinks that this is how the burger always is perfectly medium-rare (pink/red in the interior of the patty, with a small amount of brown at the burger’s surface). Bob also knows that R and B both are transcribed from the single operon. Briefly describe the biological mechanism allowing for accumulation of more R than B protein.arrow_forward
- The diagram below represents a hypothetical operon in the bacterium E. coli. The operon consists of two structural genes (A and B), which code for the enzymes “Aase" and "Base", respectively, and also includes P (promoter) and O (operator) regions as shown. A В When a certain compound (X) is added to the growth medium of E. coli, the separate enzymes "Aase" and "Base" are both synthesized at a 50-fold higher rate than in the absence of X. (X has a molecular weight of about 200.) Which of the following statements is true of the operon described above? The region of the A gene that codes for the carboxyl-terminal amino acid of “Aase" is near the left end of the A gene. The P region contains nucleotide sequences to which the RNA polymerase holoenzyme (including the o subunit) binds specifically but which the core enzyme does not recognize. The addition of X to the growth medium causes a repressor protein to bind tightly to the O region. The mRNA copied from this operon will be covalently…arrow_forwardA number of mutations affect the expression of the lac operon in E. coli. Consider each genotype below and complete the table using “+” to indicate that the gene is expressed, and “−” to indicate that gene is not expressed.arrow_forwardAnalyze the following genotypes of the Lac Operon in E. coli. In each case, determine whether Beta-galactosidase (enzyme that digests lactose) and permease (membrane channel that brings lactose into the cell) would be made in the presence or absence of lactose. For the purpose of this question, ignore glucose levels. Simply select 'YES' if the proteins are made or 'NO' if they are not . (Refer to the Lac Operon diagram for the meaning of the letters in the genotypes. Remember a "plus" superscript indicates normal functioning part of operon or repressor gene, a "minus" indicates loss of function, "OC" means "operator- constitutive", and "IS" means "super-repressor") Absence of Lactose Presence of Lactose Genotype В-gal Permease В -gal Permease IS pt 0 z+ Y-/ I† p+ 0C z¯ y+ It p+ 0C z+ y+/ I* P¯ 0 Z- Y It P 0C Z- Y+/ I¯ p* 0 z+ y It pt o z Y+/ I¯ p+ 0 z+ Yarrow_forward
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