Organic Chemistry: Structure and Function
Organic Chemistry: Structure and Function
8th Edition
ISBN: 9781319079451
Author: K. Peter C. Vollhardt, Neil E. Schore
Publisher: W. H. Freeman
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Chapter 4.3, Problem 4.7E

(a)

Interpretation Introduction

Interpretation: The Newman projections of C–C bond in cyclopropane, cyclobutane, cyclopentane,and cyclohexane should be drawn in most stable conformation.

Concept introduction: Various interconvertible forms that result from rotation around the C–C bond in ethane are termed as its conformers. To depict such conformation Newman projections are written. These are obtained by conversion of hashed-wedged line structure simply when molecule is viewed in a plane along the C–C as illustrated below:

  Organic Chemistry: Structure and Function, Chapter 4.3, Problem 4.7E , additional homework tip  1

As rotation is carried out along C–C axis, energy changes occur due to bond rotation from staggered to eclipsed conformation. This change amounts to torsional strain. Energy difference between eclipsed and staggered conformations corresponds to barrier that must be overcome for rotation. Staggered conformation is regarded most stable conformation for any cycloalkane due to least torsional strain, whereas the eclipsed has large amount of torsional strain due to steric repulsions of methyl groups as illustrated below.

  Organic Chemistry: Structure and Function, Chapter 4.3, Problem 4.7E , additional homework tip  2

(b)

Interpretation Introduction

Interpretation: The indicated molecules should be drawn in chair conformations.

  Organic Chemistry: Structure and Function, Chapter 4.3, Problem 4.7E , additional homework tip  3

Concept introduction:In chair form, all the C—C—C bond anglesare 109.5° .Since this is ideal tetrahedral angle so there is no angular strain in chair form. The staggered C—H bond further allows for no amount of torsional strain. There are two kinds of hydrogens in cyclohexane namely axial and equatorial indicated as follows:

  Organic Chemistry: Structure and Function, Chapter 4.3, Problem 4.7E , additional homework tip  4

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4.(a). Draw the structures of (i) cis-1,4-Dibromocyclohexane and (ii) trans-1,4- Dibromocyclohexane. 4(b). Draw the most stable conformers of (i) cis-1,4-Dibromocyclohexane and (ii) trans-1,4-Dibromocyclohexane. 4(c)Which is more stable? (i) cis-1,4-Dibromocyclohexane or (ii) trans-1,4- Dibromolcyclohexane. Explain the reason for your choice.
4. (a) Draw a skeletal (line-bond) structure for 3,4-dimethylhexane. (b) Draw a sawhorse representation of any staggered conformation of this molecule looking down the carbon-3 to carbon-4 bond. (c) Draw a Newman projection looking down the carbon-3 to carbon-4 bond of the same conformation that you drew as a sawhorse representation.
For 1,2-dichloroethane: (a) Draw Newman projections for all eclipsed conformations formed by rotation from 0 to 360° about the carbon-carbon single bond. (b) Which eclipsed conformation(s) has the lowest energy? Which has the highest energy? (c) Which, if any, of these eclipsed conformations are related by reflection?
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Chapter 4 Alkanes and Cycloalkanes Lesson 2; Author: Linda Hanson;https://www.youtube.com/watch?v=AL_CM_Btef4;License: Standard YouTube License, CC-BY
Chapter 4 Alkanes and Cycloalkanes Lesson 1; Author: Linda Hanson;https://www.youtube.com/watch?v=PPIa6EHJMJw;License: Standard Youtube License