Chemistry 2012 Student Edition (hard Cover) Grade 11
Chemistry 2012 Student Edition (hard Cover) Grade 11
12th Edition
ISBN: 9780132525763
Author: Prentice Hall
Publisher: Prentice Hall
Question
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Chapter 7, Problem 79A

(a)

Interpretation Introduction

Interpretation : The A-group number to which element X belong is to be identified.

Concept Introduction : Cations and anions combine to form an ionic compound.

The cation of metal and anion of non-metal are the main components of ionic compounds.

(a)

Expert Solution
Check Mark

Answer to Problem 79A

Element X belongs to the 6A group number.

Explanation of Solution

Even though ionic compounds are formed of ions, they have no electrical charge.

The smallest whole-number ratio of ions in an ionic compound is known as a formula unit.

The given formula is CaX .

Since calcium is a metal belonging to the 2A group it will lose 2 electrons to form an octet configuration.

The formed cation from calcium is Ca2+ .

The anion should be X2 where the non-metal will gain 2 electrons to form an octet.

So, the group number will be 6A group.

(b)

Interpretation Introduction

Interpretation : The A-group number to which element X belong is to be identified.

Concept Introduction : Cations and anions combine to form an ionic compound.

The cation of metal and anion of non-metal are the main components of ionic compounds.

(b)

Expert Solution
Check Mark

Answer to Problem 79A

Element X belongs to the 7A group number.

Explanation of Solution

Even though ionic compounds are formed of ions, they have no electrical charge. The smallest whole-number ratio of ions in an ionic compound is known as a formula unit.

The given formula is MgX2 .

Since magnesium is a metal belonging to the 2A group it will lose 2 electrons to form an octet configuration.

The formed cation from calcium is Mg2+ .

The anion should be 2X where there are two non-metals each will gain 1 electron to form an octet.

So, the group number will be 7A group.

(c)

Interpretation Introduction

Interpretation : The A-group number to which element X belong is to be identified.

Concept Introduction : Cations and anions combine to form an ionic compound.

The cation of metal and anion of non-metal are the main components of ionic compounds.

(c)

Expert Solution
Check Mark

Answer to Problem 79A

The element X belongs to 1A group number.

Explanation of Solution

Even though ionic compounds are formed of ions, they have no electrical charge. The smallest whole-number ratio of ions in an ionic compound is known as a formula unit.

The given formula is X3N .

Since nitrogen is a non-metal belonging to the 5A group it will gain 3 electrons to form an octet configuration.

The formed anion from nitrogen is N3 .

The cation should be 3X+ where there are three metals each will lose 1 electron to form an octet.

So, the group number will be 1A group.

(d)

Interpretation Introduction

Interpretation : The A-group number to which element X belong is to be identified.

Concept Introduction : Cations and anions combine to form an ionic compound.

The cation of metal and anion of non-metal are the main components of ionic compounds.

(d)

Expert Solution
Check Mark

Answer to Problem 79A

Element X belongs to 6A group number.

Explanation of Solution

Even though ionic compounds are formed of ions, they have no electrical charge.

The smallest whole-number ratio of ions in an ionic compound is known as a formula unit.

The given formula is Al2X3 .

Since aluminum is a metal belonging to the 3A group each of it will lose 3 electrons to form an octet configuration.

The formed cation from aluminium is 2Al3+ .

The anion should be 3X2 where the non-metal each will gain two 2 electrons to form an octet.

So, the group number will be 6A group.

(e)

Interpretation Introduction

Interpretation : The A-group number to which element X belong is to be identified.

Concept Introduction : Cations and anions combine to form an ionic compound.

The cation of metal and anion of non-metal are the main components of ionic compounds.

(e)

Expert Solution
Check Mark

Answer to Problem 79A

The element X belongs to 1A group number.

Explanation of Solution

Even though ionic compounds are formed of ions, they have no electrical charge. The smallest whole-number ratio of ions in an ionic compound is known as a formula unit.

The given formula is XF .

Since fluorine is a non-metal belonging to the 7A group it will gain 1 electron to form an octet configuration.

The formed anion from fluorine is F .

The cation should be X+ where the metal will lose 1 electron to form an octet.

So, the group number will be 1A group.

(f)

Interpretation Introduction

Interpretation : The A-group number to which element X belong is to be identified.

Concept Introduction : Cations and anions combine to form an ionic compound.

The cation of metal and anion of non-metal are the main components of ionic compounds.

(f)

Expert Solution
Check Mark

Answer to Problem 79A

The element X belongs to 2A group number.

Explanation of Solution

Even though ionic compounds are formed of ions, they have no electrical charge. The smallest whole-number ratio of ions in an ionic compound is known as a formula unit.

The given formula is XS .

Since sulphide is a non-metal belonging to the 6A group it will gain 2 electrons to form an octet configuration.

The formed anion from sulphide is S2 .

The cation should be X2+ where the metal will lose 2 electrons to form an octet.

So, the group number will be 2A group.

Chapter 7 Solutions

Chemistry 2012 Student Edition (hard Cover) Grade 11

Ch. 7.2 - Prob. 11SPCh. 7.2 - Prob. 12LCCh. 7.2 - Prob. 13LCCh. 7.2 - Prob. 14LCCh. 7.2 - Prob. 15LCCh. 7.2 - Prob. 16LCCh. 7.2 - Prob. 17LCCh. 7.2 - Prob. 18LCCh. 7.2 - Prob. 19LCCh. 7.3 - Prob. 20LCCh. 7.3 - Prob. 21LCCh. 7.3 - Prob. 22LCCh. 7.3 - Prob. 23LCCh. 7.3 - Prob. 24LCCh. 7.3 - Prob. 25LCCh. 7.3 - Prob. 26LCCh. 7 - Prob. 27ACh. 7 - Prob. 28ACh. 7 - Prob. 29ACh. 7 - Prob. 30ACh. 7 - Prob. 31ACh. 7 - Prob. 32ACh. 7 - Prob. 33ACh. 7 - Prob. 34ACh. 7 - Prob. 35ACh. 7 - Prob. 36ACh. 7 - Prob. 37ACh. 7 - Prob. 38ACh. 7 - Prob. 39ACh. 7 - Prob. 40ACh. 7 - Prob. 41ACh. 7 - Prob. 42ACh. 7 - Prob. 43ACh. 7 - Prob. 44ACh. 7 - Prob. 45ACh. 7 - Prob. 46ACh. 7 - Prob. 47ACh. 7 - Prob. 48ACh. 7 - Prob. 49ACh. 7 - Prob. 50ACh. 7 - Prob. 51ACh. 7 - Prob. 52ACh. 7 - Prob. 53ACh. 7 - Prob. 54ACh. 7 - Prob. 55ACh. 7 - Prob. 56ACh. 7 - Prob. 57ACh. 7 - Prob. 58ACh. 7 - Prob. 59ACh. 7 - Prob. 60ACh. 7 - Prob. 61ACh. 7 - Prob. 62ACh. 7 - Prob. 63ACh. 7 - Prob. 64ACh. 7 - Prob. 65ACh. 7 - Prob. 66ACh. 7 - Prob. 67ACh. 7 - Prob. 68ACh. 7 - Prob. 69ACh. 7 - Prob. 70ACh. 7 - Prob. 71ACh. 7 - Prob. 72ACh. 7 - Prob. 73ACh. 7 - Prob. 74ACh. 7 - Prob. 75ACh. 7 - Prob. 76ACh. 7 - Prob. 77ACh. 7 - Prob. 78ACh. 7 - Prob. 79ACh. 7 - Prob. 80ACh. 7 - Prob. 81ACh. 7 - Prob. 82ACh. 7 - Prob. 83ACh. 7 - Prob. 84ACh. 7 - Prob. 85ACh. 7 - Prob. 86ACh. 7 - Prob. 87ACh. 7 - Prob. 88ACh. 7 - Prob. 89ACh. 7 - Prob. 90ACh. 7 - Prob. 91ACh. 7 - Prob. 92ACh. 7 - Prob. 93ACh. 7 - Prob. 94ACh. 7 - Prob. 95ACh. 7 - Prob. 96ACh. 7 - Prob. 97ACh. 7 - Prob. 98ACh. 7 - Prob. 99ACh. 7 - Prob. 100ACh. 7 - Prob. 101ACh. 7 - Prob. 102ACh. 7 - Prob. 103ACh. 7 - Prob. 104ACh. 7 - Prob. 105ACh. 7 - Prob. 106ACh. 7 - Prob. 107ACh. 7 - Prob. 108ACh. 7 - Prob. 109ACh. 7 - Prob. 110ACh. 7 - Prob. 111ACh. 7 - Prob. 112ACh. 7 - Prob. 113ACh. 7 - Prob. 114ACh. 7 - Prob. 1STPCh. 7 - Prob. 2STPCh. 7 - Prob. 3STPCh. 7 - Prob. 4STPCh. 7 - Prob. 5STPCh. 7 - Prob. 6STPCh. 7 - Prob. 7STPCh. 7 - Prob. 8STPCh. 7 - Prob. 9STPCh. 7 - Prob. 10STPCh. 7 - Prob. 11STPCh. 7 - Prob. 12STP
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